International Maths Olympiad Forum By SOF Olympiad Trainer
  1. Home
  2. /  Forum

User Forum

Ask Your Question
kushank daksh from APEEJAY NOIDA SCHOOL, NIRMAN VIHAR C 187 2ND FLOOR 110092
Subject :IMO    Class : Class 2

Post Your Answer

Prithwanko Ghosh from Campus School, IIT Kanpur, Kanpur
Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B): Cost of necklace = ₹ 120
Cost of purse = ₹ 80
Total cost = ₹ 120 +  ₹ 80 = ₹ 200
Thus with ₹ 200, she can buy a necklace and purse so that no money will be left with her.


Post Your Answer

Shubh chawda from D g khetan , Mumbai
Subject :IMO    Class : Class 8

Ans 1:

Anshuman D from MVM, Hyderabad
Class : Class 9
x+1/x=4 So,(x+1/x)^2=4^2=16 x^2+2+1/x^2=16 Since (x-1/x)^2=x^2-2+1/x^2, It will be=(x+1/x)^2-4=16-4=12 So, (x-1/x)=√12 Which is equal to √2×2×3 =2√3

Ans 2:

Anshuman D from MVM, Hyderabad
Class : Class 9
x+1/x=4 So,(x+1/x)^2=4^2=16 x^2+2+1/x^2=16 Since (x-1/x)^2=x^2-2+1/x^2, It will be=(x+1/x)^2-4=16-4=12 So, (x-1/x)=√12 Which is equal to √2×2×3 =2√3

Post Your Answer

Ayush Rana from Kv no2 delhi cantt, delhi
Subject :IMO    Class : Class 3

Post Your Answer

Saurabh from Global Indian international school, Singapore
Subject :IMO    Class : Class 6

Post Your Answer

Laranya Lalchandani from Delhi Public School Sec-45, Gurgaon
Subject :IMO    Class : Class 4

Post Your Answer

Laranya Lalchandani from Delhi Public School Sec-45, Gurgaon
Subject :IMO    Class : Class 4

Post Your Answer

from Ryan International School ,
Subject :IMO    Class : Class 4

Ans 1:

dveep jain from mindful gurukul, Mumbai
Class : Class 4
Answer is c

Post Your Answer

Aarav Srivastav from DWPS , Noida Extension
Subject :IMO    Class : Class 6

Post Your Answer

Saurabh from Global Indian international school, Singapore
Subject :IMO    Class : Class 6

Post Your Answer