International Maths Olympiad Forum By SOF Olympiad Trainer - Page 471

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Subject :IMO    Class : Class 1

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Subject :IMO    Class : Class 1

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Subject :IMO    Class : Class 8

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Subject :IMO    Class : Class 4

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Class : Class 4
ans is c

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Class : Class 6
Heeeeeeeeeeeeeeeeeeeeeeeeeeellllllllllllllllllllllppppppppppppppppppppp mmmmmmmmmmmmmmmmeeeeeeeeeeeeeeeee wwwwwwwwwwwwiiiiiiiiiiitttttttttttthhhhhhhhh tttttthhhhhhhhhhhhhhhhhhhhhhhhhhhhiiiiiiiiiiiiiiiiiiiiiiiiiisssssssss qqqqqqqqqqquuuuuuuuuuuuuuuuueeeeeeeeeeeeeeessssssssssssssssstttttttttttiiiiiiiiiiiioooooooooonnnnnnnnnnnnnnn

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Class : Class 4
Right

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Subject :IMO    Class : Class 5

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Class : Class 8

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Class : Class 5
please explain how there are 14 squares

Ans 3:

Class : Class 9
I hope that you have studied in 4th standard, but it is said that if the shaded area is more or equal than half, then we count that block as a normal/whole block. That is why there are 14 squares.

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Class : Class 4

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Class : Class 5

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Class : Class 4
how are there 14 squares

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Class : Class 6

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Subject :IMO    Class : Class 5

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Subject :IMO    Class : Class 7

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Class : Class 9

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Class : Class 4
ohhhhh

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Class : Class 8
first of all you should know the meaning of thereof it is "if it is a part of something it should be taken as a whole" to find the cost pratik have to pay for 3 and 1/2 hours is first hour = 1.50 additional hour =1.00 1/2 hour is taken as a whole means one hour so, additional hour = 3 * 1.00 = 3.00 to find the money he had to pay = 3.00+1.50 =4.50 so the answer is B

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Class : Class 8

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Subject :IMO    Class : Class 7

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Subject :IMO    Class : Class 3

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Subject :IMO    Class : Class 9

Following are the steps of construction of a ∆ABC in which AB = 5 cm, ∠A = 30º and AC – BC = 2.5 cm. Arrange them and select the CORRECT option.
(i) Draw ∠BAX = 30º
(ii) Draw the perpendicular bisector of BD which cuts AX at C.
(iii) Draw AB = 5 cm
(iv) Join BD
(v) Join BC to obtain the required triangle ABC
(vi) From ray AX, cut off line segment AD = AC – BC = 2.5 cm

A(i) → (iii) → (iv) → (v) → (vi) → (ii)
B(iii) → (i) → (vi) → (iv) → (ii) → (v)
C(iii) → (i) → (ii) → (v) → (iv) → (vi)
D(iii) → (ii) → (iv) → (i) → (vi) → (v)


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