# User Forum

Subject :IMO    Class : Class 8

## Ans 1:

Class : Class 8
How can they give they two same options and mark one wrong

## Ans 2:

Class : Class 8
B and D are identical

## Ans 3:

Class : Class 9
answer is both B and D

Subject :IMO    Class : Class 7

## Ans 1:

Class : Class 7
it is very simple and can be solved with Pythagoras.Length=2y Breadth=yroot of [(2y)square ysquare]=9 x root of 5root of [4ysquare ysquare]=9 x root of 5root of 5ysquare=9 x root of 5 = y x root of 5thus y = 9 and 2y = 18p=54

## Ans 2:

Class : Class 8
explaination of answer not provide....how to check the solution??

## Ans 3:

Class : Class 7
First of all,diagonal of a rectanhle=square root of l^2 b^2,so 9Ãsquare root of 5 is square root of 81 Ã 5 that is 405 so here 2x is l and x is b.if i m taking l is 18 and b is 9 and squaring them we get 405 so perimeter of the rectangle is 2(18 9) that is 54.

Class : Class 9

## Ans 5:

Class : Class 8
pl give solution, very confusing question

Class : Class 7

## Ans 7:

Class : Class 7
Sorry diagonal of a rectangle is l^2 b^2

Class : Class 6

## Ans 9:

Class : Class 7
w=xl=2xd=9root52(l b)=?2(x 2x)=?using pythogras theorem,xsquare 4 x square=(9root5)squared5xsquare=405x square=81x=9hence substitute values with x,perimeter=54

Subject :IMO    Class : Class 5

Class : Class 6
C)

## Ans 2:

Class : Class 6
C)

Subject :IMO    Class : Class 6

Subject :IMO    Class : Class 6

Subject :IMO    Class : Class 4

## Ans 1:

Class : Class 5

Subject :IMO    Class : Class 6

Class : Class 6

Class : Class 6

## Ans 3:

Class : Class 5

Subject :IMO    Class : Class 3

Class : Class 3

Class : Class 4
436 B

## Ans 3:

Class : Class 5
aarav parikh take every box from right and solve the answer436 B

Subject :IMO    Class : Class 5

## Ans 1:

Class : Class 4
B is the answer to this question

Class : Class 6

Class : Class 3
cool