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Champ from Reliance Foundation School, Mumbai
Subject :IMO    Class : Class 7

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Champ from Reliance Foundation School, Mumbai
Subject :IMO    Class : Class 7

Ans 1:

Varnit khurana from Saint kabir school, Hissar
Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

Ans 2:

Varnit khurana from Saint kabir school, Hissar
Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

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Adnan Sathik from Birla public school , CHENNAI
Subject :IMO    Class : Class 3

Ans 1:

Vivaan Pathak from Prudence School , Ashok Vihar, Delhi
Class : Class 4
B Question

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tanmay srivastava from DPS Noida, Noida
Subject :IMO    Class : Class 4

Ans 1:

AREEN from BOLTON SCHOOL, Secunderabad
Class : Class 5
Ans is C because LIV=54 & XCIX=99 XLIV=44 & XLVI=46 CCV=205 & XCV=95 Therefore, LIVXCV

Ans 2:

Advika Narkar from VIBGYOR High Airoli, Navi Mumbai
Class : Class 5
C C C THE ANSWER IS C

Ans 3:

Krishnam Singhal from GEMS MODERN ACADEMY, DUBAI
Class : Class 3
bad question

Ans 4:

Kavish Korke from Narayana Group, Dombivli
Class : Class 4

Ans 5:

AREEN from BOLTON SCHOOL, Secunderabad
Class : Class 5
Answer is C because: LIV=54 XCIX=99 54<99 XLIV=44 XLVI=46 44<46 CCV=205 XCV=95 205>95

Ans 6:

Aditri from ISG oman, Ghubrah
Class : Class 5
probably

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Tejas from GV, BANGALORE
Subject :IMO    Class : Class 9

Ans 1:

Arpit Gupta from Pkr Jain , Ambala
Class : Class 10
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Ans 2:

from d.g.v. sr. sec. school, rohtak
Class : Class 9
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Ans 3:

Tejas from GV, BANGALORE
Class : Class 10
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Ans 4:

deepa shet from National public school , Shimoga
Class : Class 9
Yes it is correct

Ans 5:

Sairam from Swami Vivekanand High School, Mumbai
Class : Class 10
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Ans 6:

Nipun Abhilash from National Public School, Banashankhari, Bangalore
Class : Class 9
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Ans 7:

Mihir Rupani from Allen Career Institute, Rajkot
Class : Class 9
Yes the correct answer is option C because first is false and rest are.

Ans 8:

Akshaj Malpani from Indira national school, Pune
Class : Class 8
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Mystic Girl from NPS, Bnagalore
Subject :IMO    Class : Class 5

Ans 1:

Shruti Rajshree from NPS Indiranagar, Bengaluru
Class : Class 3
Yeah A is the answer

Ans 2:

Pranav M S from JSS Public school, Mysore
Class : Class 5
It is too easy 80-60+15-2=33

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Kaustubh Jha from Mount litera zee school, Patna
Subject :IMO    Class : Class 5

Ans 1:

Pranav M S from JSS Public school, Mysore
Class : Class 5
1836

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Aryaveer Agrawal from DELHI PUBLIC SCHOOL, Ahmedabad
Subject :IMO    Class : Class 8

Ans 1:

Abhigyan from ST MICHAEL SCHOOL, Durgapur
Class : Class 8
B. Is the correct answer

Ans 2:

sagar kumar from D A V public school , NOIDA
Class : Class 10
B

Ans 3:

Khyathi Komalan from Vaels international school, Chennai
Class : Class 9
The answer is (B) Using Unitary Method- Angle for 15,000 rupees= 360 degrees Angle for x rupees=60 degrees If money spent increases, degree of angle used increases, Therefore it is direct variation- x/1500=60/360 x=1/6 x 15,000 x= 2500 rupees

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Aryaveer Agrawal from DELHI PUBLIC SCHOOL, Ahmedabad
Subject :IMO    Class : Class 8

Ans 1:

sagar kumar from D A V public school , NOIDA
Class : Class 10
A

Ans 2:

Taes Padhihary from Disha Delphi Public School, Kota
Class : Class 9
A

Ans 3:

Labonyo Sen from Calcutta Girls High School, KOLKATA
Class : Class 4
A

Ans 4:

sagar kumar from D A V public school , NOIDA
Class : Class 10
A

Ans 5:

sagar kumar from D A V public school , NOIDA
Class : Class 10
A

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Ashutosh Sundresh from Shiv nadar, Faridabad
Subject :IMO    Class : Class 7

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