# User Forum

Subject :IMO    Class : Class 3

## Ans 1:

Class : Class 5

Subject :IMO    Class : Class 4

Class : Class 4
A

## Ans 2:

Class : Class 4
B is the correct answer because we cannot subtract 1000 from 100

Class : Class 4

Class : Class 1

CM = 1000 – 100.

Class : Class 2
CM=1000-100

## Ans 6:

Class : Class 6
c=100,M=1000 so cm =100-1000 (answer. c)

## Ans 7:

Class : Class 4
If there is C before M that means that we are subtracting 100 from 1000 . We write it as 1000 - 100. Answer : B

## Ans 8:

Class : Class 5
The answer is B because CM=C-M=C(100)-M(1000)We cannot subtract 100-1000 So the formula should be 1000-100 l Therefore, TH H T O 1 0 0 0 - 1 0 0 ----------------------- 9 0 0 So, B is the right answer.

Class : Class 4
A

## Ans 10:

Class : Class 5
The correcr answer is B CM = 1000 – 100.

## Ans 11:

Class : Class 5
The correct answer would be option C because CM = 900. C=100, M=1000. So, the smaller no. is in the beginning, it will be minus. So, 1000-100 is the correct ans.

Subject :IMO    Class : Class 2

Class : Class 2
C

## Ans 2:

Class : Class 3

Class : Class 1

363 - 323 = 40

Subject :IMO    Class : Class 5

## Ans 1:

Class : Class 6
(D) 1 1st number=(8*5)-(4*3) =40-12 =28 2nd number (12*7)-(9*8) =84-72 =12 Therefore, 3rd number=(5*5)-(6*1) =25-6 =19

## Ans 2:

Class : Class 5
8*5-3*4=28 12*7-9*8=12 5*5-1*6=19 So correct and is 1 D option

Class : Class 5

## Ans 4:

Class : Class 5

Subject :IMO    Class : Class 3

Class : Class 6
B

Class : Class 2
B

Class : Class 3

Class : Class 3
B

## Ans 5:

Class : Class 3
B

Subject :IMO    Class : Class 7

Class : Class 1

Kindly repost the correct question

Subject :IMO    Class : Class 9

Class : Class 1

Given a right angled ΔABC,
where AB = AC and CD is the bisector of ∠C  Subject :IMO    Class : Class 3

Class : Class 1

Subject :IMO    Class : Class 5

Class : Class 1

In mathematics, 'e' is a constant that is the base of the natural logarithm. It is the unique number whose natural logarithm is equal to one and its value is approximately 2.71828.

Subject :IMO    Class : Class 3

## Ans 1:

Class : Class 4

Class : Class 1

Handshakes by the first child = 6 (with remaining 6 children)

Handshakes by the second child = 5 (as the handshake with the first child is already counted)

Then, handshakes by the third child = 4 (as the handshakes with the first and second child are already counted)

Similarly, handshakes by the fourth, fifth and sixth child are 3, 2 and 1 respectively.

Since, the last child's handshakes are already counted, he/she will not make any new handshakes.

Therefore, a total of (6 +5 +4 + 3 + 2 + 1) = 21 handshakes took place.

Class : Class 4

## Ans 4:

Class : Class 4
You have not told that once a person has done handshake with the other people , his /her handshake will not be taken again.