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aksh gupta from dpsn, delhi
Subject :IMO    Class : Class 2

Ans 1:

Abhinha Ajay Ovhal from Podar International School, Latur
Class : Class 7

Ans 2:

Abhinha Ajay Ovhal from Podar International School, Latur
Class : Class 7
6

Ans 3:

Aashir Bhattacharya from Hiranandani Foundation School, Mumbai
Class : Class 7
there is curve at the top of rectangle shape of lantern hence thats not a rectangle. so total is 4

Ans 4:

Wrik Chatterjee from DELHI PUBLIC SCHOOL NOIDA, Noida
Class : Class 5

Ans 5:

ADYASHA SOURAV PANI from St.Helena's Pune, PUNE
Class : Class 2
Answer should be 6

Ans 6:

Iksha from Vibgyorhigh, Pune
Class : Class 1
The answer should be 6 D.1. the door 2. the big rectangle in the middle 3. one corner of the big rectangle4. second corner of the big rectangle5. one lantern lit 6. another lantern lit

Ans 7:

Divyam from Delhi Public School, Noida, Noida
Class : Class 5

Ans 8:

Divyam from Delhi Public School, Noida, Noida
Class : Class 5

Ans 9:

ayush kumar from dps noida, delhi
Class : Class 8
6

Ans 10:

Ayush Aravindan from Unicent School Miyapur, Hyderabad
Class : Class 6
Ok ok

Ans 11:

Vyan Badoni from jns , Mumbai
Class : Class 2
6

Ans 12:

Wrik Chatterjee from DELHI PUBLIC SCHOOL NOIDA, Noida
Class : Class 5
4

Ans 13:

Nikhita from Baldwin girls High school, bangalore
Class : Class 2
6 is the answer

Ans 14:

Abhinha Ajay Ovhal from Podar International School, Latur
Class : Class 7

Ans 15:

Wrik Chatterjee from DELHI PUBLIC SCHOOL NOIDA, Noida
Class : Class 5

Ans 16:

Nikhita from Baldwin girls High school, bangalore
Class : Class 2

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Garv Agarwal from Somerville School Noida, Noida
Subject :IMO    Class : Class 6

Ans 1:

Kavitharini Joseph from HUS, Chennai
Class : Class 6
how?

Ans 2:

Sahil Tejam from NPS Indiranagar, Bengaluru
Class : Class 6

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Garv Agarwal from Somerville School Noida, Noida
Subject :IMO    Class : Class 6

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A Ramakrishna Rao from D A V Public School. Unit 8. Bhubaneswar , Bhubaneswar
Subject :IMO    Class : Class 6

Ans 1:

Dheer Pandey from Sentia The Global School, Hyderabad
Class : Class 10
its d 1\15

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Manvi Mundepi from Montfort School Roorkee, Roorkee
Subject :IMO    Class : Class 6

Ans 1:

Nivedhini from Vivekanada Vidyalaya Chitlapakkam, Chennai
Class : Class 9
INDIA invented zero and its inventor is Bramagupta or Aryabhatta

Ans 2:

Gauri Singh from St Johns School Marhauli, Varanasi
Class : Class 8
India invented 0 and its inventor is Aryabhatta.

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Manvi Mundepi from Montfort School Roorkee, Roorkee
Subject :IMO    Class : Class 6

Ans 1:

Shreyansh Gupta from MVN, faridabad
Class : Class 7
okk

Ans 2:

Aryan Mohapatra from DAV PUBLIC SCHOOL,UNIT-8, Bhubaneswar
Class : Class 8
The answer is A

Ans 3:

Aryan Mohapatra from DAV PUBLIC SCHOOL,UNIT-8, Bhubaneswar
Class : Class 8

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Rs from DPS, Delhi
Subject :IMO    Class : Class 4

Ans 1:

Vedang Bhardwaj from Lotus Valley, Gurgaon
Class : Class 4
I did A but then I understood that holidays end at 13 but he will join on 14

Ans 2:

Manasvi pandey from Dps haldwani, Haldwani
Class : Class 3
B is the correct

Ans 3:

Vania Aravindan from Unicent School , Miyapur Hyderabad
Class : Class 8

Ans 4:

Vedang Bhardwaj from Lotus Valley, Gurgaon
Class : Class 4
Class:

Ans 5:

Vedang Bhardwaj from Lotus Valley, Gurgaon
Class : Class 4
no b

Ans 6:

Kaustubh M Sawale from Campion school, Bhopal
Class : Class 6
A is the right answer

Ans 7:

Saipriya from Sankara, Chennai
Class : Class 9
ans is be b ma because holidays till 13th but he will join on 14th only

Ans 8:

IAMLOST from ABC, Pune
Class : Class 8
ans will be b because holidays till 13th but he will join on 14th

Ans 9:

Kaustubh M Sawale from Campion school, Bhopal
Class : Class 6
B is the right answer as the date he will join is 14th Oct

Ans 10:

Manasvi pandey from Dps haldwani, Haldwani
Class : Class 3
B is correct

Ans 11:

Sameer Anand from ST MICHAEL'S HIGH SCHOOL, PATNA
Class : Class 8
A is the right answer

Ans 12:

Vedang Bhardwaj from Lotus Valley, Gurgaon
Class : Class 4

Ans 13:

DAIWIK SAHA from DUDES N DOLLS, FARIDABAD
Class : Class 8
a is the correct answer

Ans 14:

Vania Aravindan from Unicent School , Miyapur Hyderabad
Class : Class 8
A is the right one

Ans 15:

Rachel from Mount litera Zee School Goa, Goa
Class : Class 7
b is the correct answer

Ans 16:

Ryan Majumdar from Epistemo , Hyderabad
Class : Class 4
A is the correct answer.

Ans 17:

Aaryaman Pradhan from De paul School , Berhampur
Class : Class 5
a is the correct answer

Ans 18:

Aviya Daniel from HIM ACADEMY PUBLIC SCHOOL, Hamirpur
Class : Class 4

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Mehrin from DPS, Riyadh
Subject :IMO    Class : Class 2

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Champ from Reliance Foundation School, Mumbai
Subject :IMO    Class : Class 7

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Champ from Reliance Foundation School, Mumbai
Subject :IMO    Class : Class 7

Ans 1:

Varnit khurana from Saint kabir school, Hissar
Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

Ans 2:

Varnit khurana from Saint kabir school, Hissar
Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

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