Subject :IMO Class : Class 4
Class : Class 9
Answer : b Solution Smallest : 4608 Largest : 4688 Numbers between smallest and largest : 4640, 4680 Sum = 4640 4680 = 9320 So B is the right answer
Subject :IMO Class : Class 4
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Subject :IMO Class : Class 4
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Subject :IMO Class : Class 4
Ans 1:
Class : Class 4
Ans is 84. Area of the square = 12 x 12 = 144 which means 12 is the length of two sides of the square, therefore each side will be 6 and there are 14 sides. Hence the perimeter is 14 x 6 = 84
Ans 2:
Class : Class 5
Option A 84 m is the right answer.
Solution : The area of square is 144 m as given. Hence, the side of square is 12 m. The length of one smaller square in the shaded square is 6 m.
Hence the length of the rectangle is 6+6+6+6 =24
the breadth of rectangle is 6+6+6=18
The perimetre of rectangle is 2(l+b) = 2 (24+18) = 2*42 = 84 m
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Subject :IMO Class : Class 4
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Subject :IMO Class : Class 6
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Subject :IMO Class : Class 7