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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 6
Ans is B because 3645279+2153467=5798746. 5798746 will be rounded to its nearest ten thousand, which is 5800000, since 98746 will be rounded to nearest ten thousand, which is 100000, 1 will be carried to the lakhs place, or, you can say that 3645279 and 2153467 will be rounded to the nearest ten thousand, which will be 3650000 and 2150000, respectively. 3650000+2150000=5800000.

Ans 2:

Class : Class 6
Option B)

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Subject :IMO    Class : Class 8

Ans 1:

Class : Class 7

Ans 2:

Class : Class 9
4

Ans 3:

Class : Class 4
isn't the answer "A"

Ans 4:

Class : Class 9

Ans 5:

Class : Class 6
the solution of the equation is 3*3*5*5*5*2*7 which has seven prime factors

Ans 6:

Class : Class 8
the answer is 7.

Ans 7:

Class : Class 8
The answer is 3. When you solve the equation you get 3*3*1*1*2*14/1*1*1. Now we see that the prime numbers left are 3,3 and 2. Therefore there are 3 prime numbers.

Ans 8:

Class : Class 8
The answer is 3. When you solve the equation you get 3*3*1*1*2*14/1*1*1. Now we see that the prime numbers left are 3,3 and 2. Therefore there are 3 prime numbers.

Ans 9:

Class : Class 8
The answer is 4. There are 4 prime factors: 2,3,5 and 7

Ans 10:

Class : Class 8
ans is 7

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Subject :IMO    Class : Class 3

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Subject :IMO    Class : Class 3

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 3

Ans 2:

Class : Class 5
BIR you have written ten thousand instead of one thousand !!!

Ans 3:

Class : Class 4

Ans 4:

Class : Class 5
dfd

Ans 5:

Class : Class 2
100 tens = 1 thousand

Ans 6:

Class : Class 5
The answer is D .

Ans 7:

Class : Class 4
The answer is D

Ans 8:

Class : Class 4
10000

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Subject :IMO    Class : Class 8

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 8
its more than easy D

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Subject :IMO    Class : Class 3

Ans 1:

Class : Class 3
options given seems to be wrong

Ans 2:

Class : Class 4
Out of Syllabus

Ans 3:

Class : Class 5
IT IS OUT OF SYLLABUS.

Ans 4:

Class : Class 4

Ans 5:

Class : Class 4
out of syallabus

Ans 6:

Class : Class 5
It is NOT out of syllabus . The sulution is that one moon is 18.So,18x18=324.To get the star devide 18 by 3=6.18-6=12

Ans 7:

Class : Class 5
the answer is 108

Ans 8:

Class : Class 3

Ans 9:

Class : Class 3
I don't know the answer because IT IS OUT OF SYLLABUS

Ans 10:

Class : Class 3
it is a little tricky but i solved it.

Ans 11:

Class : Class 3
correct answer should be 33

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Subject :IMO    Class : Class 4

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Subject :IMO    Class : Class 5

Study the given line graph which shows the capacity of petrol Mohit used while travelling from City X to City Y from April to August and answer the following questions.

(A) How much more capacity of petrol was used in August than in May?
(B) What fraction of the total capacity of petrol used in July?

(A) (B)
A 20000 mL 7/26
B 22000 mL 8/29
C 10000 mL 7/27
D 25000 mL 9/36


Ans not understood... I doubt if the ans is correct.

Ans 1:

Class : Class 6
Option A)

Ans 2:

Class : Class 6
Ans is A because the answer of question (A) will be 20000 ml because 40 l-20 l=20 l. Now convert 20 l to ml, which is 20000 ml, or, you can say that 20 l and 40 l will be 20000 ml and 40000 ml, respectively. Now do 20000 ml-40000 ml=20000ml. answer of question (B) will be 7/26 by adding the capacity of petrol of April, May, June, July and August, which will be 10 l+20 l+ 25 l+35 l+40 l=130 l. In July, the capacity of petrol used was 35 l, so in fraction, it will be 35 l/130 l. Now simplify the fraction, which will be 7 l/26 l.

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