International Maths Olympiad Forum By SOF Olympiad Trainer - Page 453
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Prachi from Holy Child Public school, Faridabad
Subject :IMO    Class : Class 4

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Pragun goel from Venkateshwar International School, Delhi
Subject :IMO    Class : Class 5

Ans 1:

AREEN from BOLTON, HYDERABAD
Class : Class 6
Ans is B because 3645279+2153467=5798746. 5798746 will be rounded to its nearest ten thousand, which is 5800000, since 98746 will be rounded to nearest ten thousand, which is 100000, 1 will be carried to the lakhs place, or, you can say that 3645279 and 2153467 will be rounded to the nearest ten thousand, which will be 3650000 and 2150000, respectively. 3650000+2150000=5800000.

Ans 2:

Arunava hury from KV1 saltlake , Kolkata
Class : Class 6
Option B)

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Shruti Hegde from Mount Litera Zee school, Bengaluru
Subject :IMO    Class : Class 8

Ans 1:

Akshara from NPS, Bengaluru
Class : Class 8
Yes .... The answer is 4. ( 2, 3 ,5 and 7)

Ans 2:

Ayush Gorain from Sarala Birla Public School, Ranchi
Class : Class 8
The answer should be option (A) = 4. There are 4 prime factors, i.e. 2, 3, 5 and 7. The solution contradicts the question's answer.

Ans 3:

DEVRAJ DOLEY from NPS INTERNATIONAL SCHOOL, Guwahati
Class : Class 8
the answer is 7.

Ans 4:

Pranav from Ganges valley school, Hyderabad
Class : Class 8
The answer is 3. When you solve the equation you get 3*3*1*1*2*14/1*1*1. Now we see that the prime numbers left are 3,3 and 2. Therefore there are 3 prime numbers.

Ans 5:

Mudit garg from La blossoms school, Jalandhar
Class : Class 7

Ans 6:

Pranav from Ganges valley school, Hyderabad
Class : Class 8
The answer is 3. When you solve the equation you get 3*3*1*1*2*14/1*1*1. Now we see that the prime numbers left are 3,3 and 2. Therefore there are 3 prime numbers.

Ans 7:

svayumbhu sharma from jodhamal public school, jammu
Class : Class 9

Ans 8:

Aman Sumod from Chinmaya Vidyalaya, KANNUR
Class : Class 8
The answer is 4. There are 4 prime factors: 2,3,5 and 7

Ans 9:

Ashwin Shridhar from Vidyashilp Academy, Bangalore
Class : Class 9
4

Ans 10:

Angshu from Dehli Public School Bangalore East, Bangalore
Class : Class 8
The answer should be (A) 4.There are four factors, i.e. 2,3,5,7. Even the solution says so. Please correct the error.

Ans 11:

Hari Bhaskar from bgs, JP Nagar 7th Phase
Class : Class 6
the solution of the equation is 3*3*5*5*5*2*7 which has seven prime factors

Ans 12:

jayashree easwaran from vibgyor High, Bengaluru
Class : Class 4
isn't the answer "A"

Ans 13:

ARNAV BARANWAL from KPS SCHOOL, bhilai
Class : Class 8
ans is 7

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Advait nagale from Universal High, Thane
Subject :IMO    Class : Class 3

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Mayank Paul from Saint Edmunds School, Shillong
Subject :IMO    Class : Class 3

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Ankit Kumar Mistry from Kalyani Public School, Kolkata
Subject :IMO    Class : Class 4

Ans 1:

Shreeya Mangla from ASN Senior Secondary School, New Delhi
Class : Class 8

Ans 2:

Sarah Ahmad from st. mary's school, delhi
Class : Class 7
The answer is D- 1 thousand

Ans 3:

MANDAR PALKAR from KV DRDO, Bengaluru
Class : Class 2
100 tens = 1 thousand

Ans 4:

Amartya Dey from DPS Bangalore East, Bangalore
Class : Class 5
trick question

Ans 5:

BIR from LOTUS VALLEYINTERNATIONAL SCHOOL, NOIDA
Class : Class 4
10000

Ans 6:

Ashwak from Cambridge, Jalandhar
Class : Class 8
BIR you have written ten thousand instead of one thousand !!!

Ans 7:

Nehal from New Horizon Gurukul, Bangalore
Class : Class 6

Ans 8:

Satvik Agrawal from Delhi Public School, bhopal
Class : Class 5
dfd

Ans 9:

Ashwak from Cambridge, Jalandhar
Class : Class 8
The answer is D .

Ans 10:

Sarah Ahmad from st. mary's school, delhi
Class : Class 7

Ans 11:

Sarthak Shome from Harvest International, Bangalore
Class : Class 7
man the answer is 10 lackhs

Ans 12:

Shraddha from Delhi public school, Hyderabad
Class : Class 4
The answer is D

Ans 13:

Sweta from dpsnoida, Noida
Class : Class 4
solutions should be in detail and a little easy

Ans 14:

Aharshi Sarkar from Venkateshwar International School Dwarka, Delhi
Class : Class 4
The answer is (A) because it has said the minor 5-digit no.

Ans 15:

Midhuna from ABCD, Banglore
Class : Class 3

Ans 16:

Soumya Gupta from Prudence School Ashok Vihar, New Delhi
Class : Class 5
the answer is c

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Astha Aswani from Fatima convent school, Kanpur
Subject :IMO    Class : Class 8

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DEVANSHI R SHAH from DIVYAPATH CAMPUS, AHMEDABAD
Subject :IMO    Class : Class 7

Ans 1:

Arshia Mittal from Ryan International School, rohini
Class : Class 9
its more than easy D

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rachana from delhi public school, NACHARAM
Subject :IMO    Class : Class 3

Ans 1:

Aanya from Apeejay School , Delhi
Class : Class 3

Ans 2:

Anaisha Niranjan from DPS Noida, Noida
Class : Class 4
the answer should 107

Ans 3:

Chanchal Sharma from Universal high School, Thane West
Class : Class 3

Ans 4:

Raghav from Gems wellington school, Doha
Class : Class 6
it is a little tricky but i solved it.

Ans 5:

Aamogh from Kv, Chennai
Class : Class 3
correct answer should be 33

Ans 6:

Suchi shah from AIS, Ahmedabad
Class : Class 3
pls explain

Ans 7:

Inaaya Garg from Carmel Convent School, Chandigarh
Class : Class 3

Ans 8:

Rajdeep Chatterjee from Techno India Public School, Bolpur
Class : Class 8
IT IS OUT OF SYLLABUS.

Ans 9:

Krishang Roushan from Dimension International College, Singapore
Class : Class 3
It is not that hard, just that if you understand the question you can easily find the answer.The pea pie who are saying that the question is wrong, you are the one who is wrong, not the question!

Ans 10:

Arpit Gupta from Treamis World School, Bengaluru
Class : Class 5
options given seems to be wrong

Ans 11:

Krishna Nanda from St. Xaviers Co Ed School Bhopal, Bhopal
Class : Class 7
the answer is 108

Ans 12:

Aditya Mittal from St Peters College, AGRA
Class : Class 5
It is not wrong moon divide by star is 3 moon multiply by moon is 324 3star multiply 3star is 324 star .star equals 324/9 is 36 star - 6 moon equals 18 answer is 12

Ans 13:

Suchi shah from AIS, Ahmedabad
Class : Class 3
How the value of 2 moon is 18 i think 324/2=162

Ans 14:

Prisha Jora from Adani Public School, Mundra
Class : Class 3
I don't know the answer because IT IS OUT OF SYLLABUS

Ans 15:

princy gigo from Global Indian International School, Kuala Lumpur
Class : Class 8
out of syallabus

Ans 16:

Harshith from Cs academy, Erode
Class : Class 3

Ans 17:

IAMLOST from ABC, Pune
Class : Class 8
It is NOT out of syllabus . The sulution is that one moon is 18.So,18x18=324.To get the star devide 18 by 3=6.18-6=12

Ans 18:

AARAV GUPTA from Khaitan Public School, Ghaziabad
Class : Class 4
Out of Syllabus

Ans 19:

Jeremy Sen from Montfort Senior Secondary, Roorkee
Class : Class 5
wat

Ans 20:

AARAV GUPTA from Khaitan Public School, Ghaziabad
Class : Class 4

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Sanskriti Samant from Euroschool Wakad, Pune
Subject :IMO    Class : Class 4

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