International Maths Olympiad Forum By SOF Olympiad Trainer - Page 678

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Subject :IMO    Class : Class 4

Ans 1: (Master Answer)

Class : Class 1
The correct answer is B.

Ans 2:

Class : Class 4
why ??

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Subject :IMO    Class : Class 3

Ans 1:

Class : Class 3

Ans 2:

Class : Class 3
D 1 hr 40 mins

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Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Class : Class 1
The correct answer is A.

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Subject :IMO    Class : Class 3

Ans 1:

Class : Class 3

Ans 2:

Class : Class 3
328

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Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Class : Class 1
The correct answer is A.

Ans 2:

Class : Class 5

Ans 3:

Class : Class 9
SolutionTotal no. of days in January 20XX = 31 Now, let’s see how many days’ leave Priya took in January. Priya takes a leave on 2nd Saturday and 4th Saturday in January. That means she takes leave on January 12 and January 26. That’s 2 days of leave. There are four Sundays in January – January 6, January 13, January 20 and January 27. Sundays are holidays. That’s 4 days of leave. Republic day is also a holiday. But Republic Day falls on January 26, which is 4th Saturday. And Priya has already taken leave on 4th Saturday. So, it has been counted in leave earlier. So, total no. of days when Priya took leave = 2 4 = 6 days. Working days in January 20XX = Total days – Leave days = 31 – 6 = 25 days So, the right answer is Option A.

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Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Class : Class 1
The correct answer is B.

Ans 2:

Class : Class 9
SolutionLetter L (Option A), Letter N (Option C) and Letter V (Option D) are formed by straight lines only. But Letter D (Option B) is formed by a straight line and a curved line. So, Option B is the odd one out.

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Subject :IMO    Class : Class 3

Ans 1:

Class : Class 3
CHART IS NOT GIVEN . YOU SHOULD GIVE THE CHART

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 9
it is c

Ans 2:

Class : Class 6
See the pattern of the given answer Answer is First letter of second no. Then first letter of 1 No. And then goes on So Answer is C

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Subject :IMO    Class : Class 2

Ans 1:

Class : Class 9

Ans 2: (Master Answer)

Class : Class 1
The weight of 1 papaya is 100 gm. Hence, the correct answer is A.

Ans 3:

Class : Class 9
Total weight of the onion and cabbage =100gm.Total weight of 2 onions and 2 cabbages= 200gm, which is equivalent to the weight of one papaya. 1 papaya=200gm, hence 2 papayas= 400gm. Option B is the correct answer.

Ans 4:

Class : Class 4
Total weight of onion and cabbage is 100 gm not onions and cabbages.answer will be 400 gm

Ans 5:

Class : Class 2
the awnser is 400 because 1cabbage and 1onion=100 and there are 2 cabages and 2 onions so the awnser is.................................400

Ans 6:

Class : Class 2
it is not written onion and cabbage not onions and cabbages. So the ans should be 400.

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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 5

Ans 2:

Class : Class 6

Ans 3:

Class : Class 5
confusing

Ans 4:

Class : Class 3
idiot question

Ans 5:

Class : Class 9
confusing

Ans 6:

Class : Class 7
Wow so tricky question very interesting

Ans 7:

Class : Class 6
Confusing

Ans 8:

Class : Class 8
b easy

Ans 9:

Class : Class 7

Ans 10:

Class : Class 6
I will a sweet candy everybody.

Ans 11:

Class : Class 6
sorry for d rong post

Ans 12:

Class : Class 8
B is the answer

Ans 13:

Class : Class 4

Ans 14:

Class : Class 7

Ans 15:

Class : Class 5
u ccant even see it

Ans 16:

Class : Class 6

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