International Maths Olympiad Forum By SOF Olympiad Trainer

# User Forum

Subject :IMO    Class : Class 5

## Ans 1: (Master Answer)

Class : Class 1
The correct answer is C.

Class : Class 5

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Subject :IMO    Class : Class 4

## Ans 1:

Class : Class 4
nnnnhhhhhoooookkkkkk

## Ans 2:

Class : Class 3
It is definitely c

Class : Class 7
C is right

Class : Class 4
C

## Ans 5:

Class : Class 4
correct answer is C

## Ans 6:

Class : Class 4
how not understood

Class : Class 4
Option C

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Subject :IMO    Class : Class 5

## Ans 1:

Class : Class 6
sorry very nice question

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Subject :IMO    Class : Class 7

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Subject :IMO    Class : Class 9

## Ans 1:

Class : Class 10
Let the angle be x. Ext angle of x=180-x ATQ, req angle=x/2+((180-x)/2)=180/2=90(ans) opt a

## Ans 2:

Class : Class 10
Let the angle be x. Ext angle of x=180-x ATQ, req angle=x/2+((180-x)/2)=180/2=90(ans) opt a

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Subject :IMO    Class : Class 4

## Ans 1:

Class : Class 6
The answer is C. I have solved it before. The bill was Rs 92. 100-92= Rs 8

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Subject :IMO    Class : Class 3

Class : Class 3
c

## Ans 2:

Class : Class 4
It is 3 hours 45 minutes equal to 4:30 + 3 hours 45 minutes = 8:15

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Subject :IMO    Class : Class 1

## Ans 1: (Master Answer)

Class : Class 1
The correct answer is C.

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Subject :IMO    Class : Class 8

## Ans 1:

Class : Class 10
Ans: (c) 1187.50 Let the principal be x. A=P(1+R\100)(1+R\100)(1+R\100)=x(1 + 20\100)(1 + 20\100)(1 + 20\100) =216x\125.; CI=(A-P)=(216x\125 - x)=91x\125.; SI=(P*R*T)\100=(x*3*20)\100=3x\5.; A to Q = 91x\125 - 3x\5=152 16x\125=152.; x=152*125\16.; x=1087.50

Class : Class 8
d

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Subject :IMO    Class : Class 1

## Ans 1:

Class : Class 5
answer should be 8 bcz to reach the cake mouse has to jump one more house