International Maths Olympiad Forum By SOF Olympiad Trainer - Page 584
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Arjun Gourineni from CHIREC International School, Hyderabad
Subject :IMO    Class : Class 2

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is C

363 - 323 = 40


Ans 2:

Om Mahajan from StarChild Academy, Orlando
Class : Class 1
C

Ans 3:

Shrihan Modi from Delhi Public School Noida , Noida
Class : Class 4
C

Ans 4:

Anshul Sameer Darne from Ryan International School, Masdar
Class : Class 6
C40 is the answer.

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Atharva Panjabi from BAL BHARATI PUBLIC SCHOOL DWARKA, New Delhi
Subject :IMO    Class : Class 5

Ans 1:

Atharva Panjabi from BAL BHARATI PUBLIC SCHOOL DWARKA, New Delhi
Class : Class 4

Ans 2:

Atharva Panjabi from BAL BHARATI PUBLIC SCHOOL DWARKA, New Delhi
Class : Class 4
please show the correct explaination.

Ans 3:

ARADHYA AGARWAL from NEW ERA PROGRESSIVE SCHOOL, Korba
Class : Class 8
Answer is [D] 1

Ans 4:

Viggya Sutradhar from New look Senior Secondary school, Banswara
Class : Class 8
8*5-3*4=28 12*7-9*8=12 5*5-1*6=19 So correct and is 1 D option

Ans 5:

Saksham Chanani from Sri Sri Academy, Kolkata
Class : Class 9

Ans 6:

Preya from New Horizon Gurukul, Bangalore
Class : Class 5
ya

Ans 7:

Aarya Teja from Bharatiya Vidya Bhavans Public School, Hyderabad
Class : Class 6
(D) 1 1st number=(8*5)-(4*3) =40-12 =28 2nd number (12*7)-(9*8) =84-72 =12 Therefore, 3rd number=(5*5)-(6*1) =25-6 =19

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Shiven Dinkar from DPS NOIDA Sector 30, Delhi
Subject :IMO    Class : Class 3

Ans 1:

Avik Arya from Trileaves Global school , Chennai
Class : Class 3
B/D

Ans 2:

Adya gupta from DPS, RKP
Class : Class 2
B

Ans 3:

Amarjit Pattanaik from sainik school, Chennai
Class : Class 6
The answer is B

Ans 4:

Girish Garg from Delhi public school, Bathinda
Class : Class 3
B

Ans 5:

Naitik from Billabong High International School, Noida
Class : Class 5
b

Ans 6:

Amarjit Pattanaik from sainik school, Chennai
Class : Class 6
The answer is B.

Ans 7:

Amarjit Pattanaik from sainik school, Chennai
Class : Class 6
The answer is B.

Ans 8:

Saanvi from DPS INTERNATIONAL SCHOOL, Singapore
Class : Class 4
( B ) is the answer 😁

Ans 9:

Amarjit Pattanaik from sainik school, Chennai
Class : Class 6

Ans 10:

Lavith karn from Euro school wakad, pune
Class : Class 3
The anwer is B

Ans 11:

Aditya Raj from Kairali School, Ranchi
Class : Class 6
B

Ans 12:

Urvee Sarang Gokhale from Sri Sri Ravi Shankar Vidya Mandir, Pune
Class : Class 5
B is the correct answer.

Ans 13:

Girish Garg from Delhi public school, Bathinda
Class : Class 3
B

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Atharv Deshmukh from Podar international school, Aurangabad
Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

Kindly repost the correct question


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Swapnil Ganguly from Salt Lake School , Kolkata
Subject :IMO    Class : Class 9

Ans 1:

Gauransh Gupta from Manavsthali School R-block, NEW DELHI
Class : Class 5

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is A.

Given a right angled ΔABC,
where AB = AC and CD is the bisector of ∠C. 
 


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Kushagra Gupta from Manav Rachna, Faridabad
Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is D.


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Seshasayee sudharsan from PSBB Learning Leadership Academy, Bangalore
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

In mathematics, 'e' is a constant that is the base of the natural logarithm. It is the unique number whose natural logarithm is equal to one and its value is approximately 2.71828.


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AARAV GUPTA from Khaitan Public School, Ghaziabad
Subject :IMO    Class : Class 3

Ans 1:

Vedant Chhabra from Blue Ridge Public School , Pune
Class : Class 5

Ans 2:

Vedant Chhabra from Blue Ridge Public School , Pune
Class : Class 5

Ans 3:

Advika Narkar from The Shishukunj International School, Jhalaria Campus, Indore
Class : Class 8
No answer is C admin is right

Ans 4: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is C.

Handshakes by the first child = 6 (with remaining 6 children)

Handshakes by the second child = 5 (as the handshake with the first child is already counted)

Then, handshakes by the third child = 4 (as the handshakes with the first and second child are already counted)

Similarly, handshakes by the fourth, fifth and sixth child are 3, 2 and 1 respectively.

Since, the last child's handshakes are already counted, he/she will not make any new handshakes.

Therefore, a total of (6 +5 +4 + 3 + 2 + 1) = 21 handshakes took place.


Ans 5:

Advika Narkar from The Shishukunj International School, Jhalaria Campus, Indore
Class : Class 8
You have not told that once a person has done handshake with the other people , his /her handshake will not be taken again.

Ans 6:

Yatharth from DPS, VADODARA
Class : Class 4

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Parth Thakkar from Mount Literal Zee School, Ahmedabad
Subject :IMO    Class : Class 6

Ans 1:

akshanjaswal from Modern Delhi International School, Faridabad
Class : Class 10
2X(5X20X15) =3000, so B is the answer

Ans 2:

Pisal Dhruv from Veer Bhagat Singh International School, Mumbai
Class : Class 7
then the question turns to 2x(5x20x15) =30000, hence B is the correct answer

Ans 3:

ARKA ALOK GANGOPAADHYAY from GARDEN HIGH SCHOOL , KOLKATA
Class : Class 7
Answer is B

Ans 4:

Parth Thakkar from Mount Literal Zee School, Ahmedabad
Class : Class 9
The answer is option B but you have typed 30000 but the answer is written is 3000

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Sourav Jena from ODM public school , BHUBANESWAR
Subject :IMO    Class : Class 5

Ans 1:

Seshasayee sudharsan from PSBB Learning Leadership Academy, Bangalore
Class : Class 6
Please I want to tell something the spelling is wrong of genius

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