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Champ from Reliance Foundation School, Mumbai
Subject :IMO    Class : Class 7

Ans 1:

Varnit khurana from Saint kabir school, Hissar
Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

Ans 2:

Varnit khurana from Saint kabir school, Hissar
Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

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adnan from Birla public school , Doha
Subject :IMO    Class : Class 3

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tanmay srivastava from DPS Noida, Noida
Subject :IMO    Class : Class 4

Ans 1:

AREEN from BOLTON SCHOOL, Secunderabad
Class : Class 5
Ans is C because LIV=54 & XCIX=99 XLIV=44 & XLVI=46 CCV=205 & XCV=95 Therefore, LIVXCV

Ans 2:

ASHMI Narkar from Vibgyor High Airoli, Navi Mumbai
Class : Class 4
C C C THE ANSWER IS C

Ans 3:

AREEN from BOLTON SCHOOL, Secunderabad
Class : Class 5
Answer is C because: LIV=54 XCIX=99 54<99 XLIV=44 XLVI=46 44<46 CCV=205 XCV=95 205>95

Ans 4:

Krishnam Singhal from GEMS MODERN ACADEMY, DUBAI
Class : Class 3
bad question

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Tejas from GV, BANGALORE
Subject :IMO    Class : Class 9

Ans 1:

Arpit Gupta from Pkr Jain , Ambala
Class : Class 10
C option is correct......as the first is false and rest are true.

Ans 2:

Sairam from Swami Vivekanand High School, Mumbai
Class : Class 10
Actually, the answer should be FTF which is not given in the options. Considering statement 1, the sides of the triangle are 4cm, 8cm, and 12cm. But according to inequalities of triangles, sum of any to sides of a triangle is greater than the third side. But 4+8=12; i.e. sum of the two sides is equal to the third side. So statement 1 is FALSE. Considering statement 2, it is possible to construct an angle of 67.5 only using a ruler and compass. Taking statement 3, without a base, we can't construct a triangle.

Ans 3:

deepa shet from National public school , Shimoga
Class : Class 9
Yes it is correct

Ans 4:

from d.g.v. sr. sec. school, rohtak
Class : Class 9
answer should be FTF

Ans 5:

Tejas from GV, BANGALORE
Class : Class 10
The answer is (C) --- F,T,T. Here's why:The first one is false anyway, as the '12' side is equal to (not less than, as must be) the sum of the other two '4' and '8' sides.The second one is TRUE (not false!) as I can easily construct a 90^ angle and 45^ angle with ruler and compass; and simply bisect that in-between angle to get a 67.5 angle.Even the third one is TRUE (not false) as construction of a triangle allows using a protractor for angles (that's how R.D.Sharma and my teacher do it) and ANY such triangle can be constructed. In short, my answer is correct. I marked the same, but the olympiad trainer says that it is (B) --- all are false.

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Elena from NPS, Bnagalore
Subject :IMO    Class : Class 5

Ans 1:

Pranav M S from JSS Public school, Mysore
Class : Class 5
It is too easy 80-60+15-2=33

Ans 2:

Shruti Rajshree from NPS Indiranagar, Bengaluru
Class : Class 6
Yeah A is the answer

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Kaustubh Jha from Mount litera zee school, Patna
Subject :IMO    Class : Class 5

Ans 1:

Pranav M S from JSS Public school, Mysore
Class : Class 5
1836

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Aryaveer Agrawal from DELHI PUBLIC SCHOOL, Ahmedabad
Subject :IMO    Class : Class 8

Ans 1:

Khyathi Komalan from Vaels international school, Chennai
Class : Class 9
The answer is (B) Using Unitary Method- Angle for 15,000 rupees= 360 degrees Angle for x rupees=60 degrees If money spent increases, degree of angle used increases, Therefore it is direct variation- x/1500=60/360 x=1/6 x 15,000 x= 2500 rupees

Ans 2:

Abhigyan from ST MICHAEL SCHOOL, Durgapur
Class : Class 8
B. Is the correct answer

Ans 3:

sagar kumar from D A V public school , NOIDA
Class : Class 9
B

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Aryaveer Agrawal from DELHI PUBLIC SCHOOL, Ahmedabad
Subject :IMO    Class : Class 8

Ans 1:

Taes Padhihary from Disha Delphi Public School, Kota
Class : Class 9
A

Ans 2:

sagar kumar from D A V public school , NOIDA
Class : Class 9
A

Ans 3:

Labonyo Sen from Calcutta Girls High School, KOLKATA
Class : Class 4
A

Ans 4:

sagar kumar from D A V public school , NOIDA
Class : Class 9
A

Ans 5:

sagar kumar from D A V public school , NOIDA
Class : Class 9
A

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Ashutosh Sundresh from Global Indian International School, Pune
Subject :IMO    Class : Class 7

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Manvi Mundepi from Montfort School Roorkee, Roorkee
Subject :IMO    Class : Class 6

Ans 1:

Nivedhini from Vivekanada Vidyalaya Chitlapakkam, Chennai
Class : Class 7
The answer is c-18900

Ans 2:

Kumar Krishiv from Apeejay School, Noida
Class : Class 6
7*3*9=18900,So answer is C

Ans 3:

Prashasti Bhandari from Morning star hss, Ratlam
Class : Class 5
C

Ans 4:

Sushanth Sandesh Prabhu from Indira Priyadarshini School, Bangalore
Class : Class 6
7 ×3×900=18900 c is the correct answer.

Ans 5:

Nimmi Nancy from The Titan School, hosur
Class : Class 7
It's "C-18900"

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