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Ans 1:
Class : Class 8
Relative velocity of two trains is 384km/hr=320/3 m/sec.
Therefore,it can travel 1600m in 15 sec.
Therefore, the length of the second train is (1600-600)m=1000m
Ans 3:
Class : Class 8
Add up the speeds and multiply with time as trains are in opposite directions.Then subtract the length of the first train.
Ans -1000m
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Ans 1:
Class : Class 9
Let the ages of A, B and C be a years, b years and c years respectively.
(a + b) is 12 greater than (b + c)
=> 12 + b + c = a + b
=> 12 + c = a
=> 12 = a - c
So, C is younger than A by 12 years
Answer is A
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Ans 9:
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Ans 2:
Class : Class 4
Putting a = 4q and b = 3q in a * b = (3a 2b)/(3a – 2b). (4q * 3q) = [3(4q) 2(3q)]/ [3(4q) - 2(3q)] = (12q 6q) / (12q – 6q) = 18q/6q = 3 So, 5p * (4q * 3q) = 5p * 3 Put p= 1/5 in 5p * 3 we get 5 x 1/5 * 3 = 1 * 3 = [3(1) 2(3)]/ =[3(1) - 2(3)] = (3 6)/(3 – 6) = 9/-3 = - 3 Answer-(C) - 3
Ans 4:
Class : Class 6
SolutionPutting a = 4q and b = 3q in a * b = (3a 2b)/(3a – 2b).(4q * 3q) = [3(4q) 2(3q)]/ [3(4q) - 2(3q)]= (12q 6q) / (12q – 6q)= 18q/6q = 3So, 5p * (4q * 3q) = 5p * 3Put p= 1/5 in 5p * 3we get 5 x 1/5 * 3 = 1 * 3= [3(1) 2(3)]/ =[3(1) - 2(3)]= (3 6)/(3 – 6)= 9/-3 = - 3Answer-(C) - 3
Ans 11:
Class : Class 8
What happened to q=3 they didn’t do anything with that. They should have multiplied 4q and 3q by 3 before solving the question.