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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 9
https://www.sofolympiadtrainer.com/forum/user/467395 (i.e. ADMIN) from https://www.sofolympiadtrainer.com/user/home/usertestDetailsOfTest

Ans 2:

Class : Class 10
Sir please say the answer .

Ans 3:

Class : Class 9
Answer is D) 3.

Ans 4: (Master Answer)

Class : Class 1
Kindly mention your query

Ans 5:

Class : Class 7

Ans 6:

Class : Class 8

Ans 7:

Class : Class 6

Ans 8:

Class : Class 7

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Subject :IMO    Class : Class 2

Ans 1:

Class : Class 6
c is the answer

Ans 2: (Master Answer)

Class : Class 1
Kindly mention your query

Ans 3:

Class : Class 6
c is answer

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Subject :IMO    Class : Class 2

Ans 1:

Class : Class 2
225

Ans 2:

Class : Class 7
Please mention your query

Ans 3: (Master Answer)

Class : Class 1
Please mention your query

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Subject :IMO    Class : Class 2

Ans 1: (Master Answer)

Class : Class 1
Here, 462 + 199 = 661 So, the correct match is 462 + 199 - 661, which is option B.

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Subject :IMO    Class : Class 8

Ans 1:

Class :
Find the divisor given that the dividend is2200 remainder is 13 and the divisor is one third of the quotient

Ans 2:

Class :
Find the divisor given that the dividend is2200 remainder is 13 and the divisor is one third of the quotient

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Subject :IMO    Class : Class 10

Ans 1:

Class : Class 6
help

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Subject :IMO    Class : Class 2

Ans 1: (Master Answer)

Class : Class 1
Kindly mention your query

Ans 2:

Class : Class 2
B

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Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Class : Class 1
Here, the answer is A. 7 tenths is 7 over 10, if you divide 7 by 10 you get 7 tenths as a decimal which is 0.7 Similarly, 45 tenths is 45 over 10,if you divide 45 by 10 you get 45 tenths as a decimal which is 4.50 21 hundredths is 21 over 100, if you divide 21 by 100 you get 21 hundredths as a decimal which is 0.21 Hence, the sum of 7 tenths, 21 hundredths and 45 tenths is (0.7 + 0.21 + 4.50) = 5.41

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Subject :IMO    Class : Class 8

Ans 1:

Class : Class 9
a2 - 13a + 30 = a2 + 4a + 4 a - 10 a + 2 => (a2 - 13a + 30)(a + 2) = (a2 + 4a + 4)(a - 10) => a3 + 2a2 - 13a2 - 26a + 30a + 60 = a3 - 10a2 +4a2 + 4a - 40 => - 11a2 + 4a + 60 = - 6a2+ 4a - 40 => - 11a2 + 6a2 + 60 + 40 = 0 => - 5a2 + 100 = 0 => 5a2 = 100 => a2 = 20 => a = √20 Insert the value of'a'and you will get the answer.

Ans 2:

Class : Class 9
but that is not what we want

Ans 3:

Class : Class 8
By factorization process, we get a-3 = a 2, which is in fact a linear equation without a solution. On the other hand, by solving through cross multiplication method (as shown in the solution of this question), we get a²-8a-20 = 0, or (a 2)(a-10) = 0. By solving the quadratic equation, we get a as (-2) or (10), which, upon substituting in the formula given in the question, doesn't satisfy the equation. This is because the equation in the above question isn't even actually correct, as (a-3) is not equal to (a 2), as that would lead to the statement: 5 = 0, which is obviously not true.

Ans 4:

Class : Class 9
i got 5

Ans 5:

Class : Class 8

Ans 6:

Class : Class 10
The question is wrong.If A is the answer, solving this quadratic eqn, we get a=10 or -2since the answer is a simplified form of the question, these values of a should also hold for question also. But if we put these vales in the question either LHS or RHS denominator will become 0 making it undefined.the actual procedure is to factorize.=> [(a-3)(a-10)]/(a-10)=[(a 2)(a 2)]/(a 2)=> a-3 = a 2=> -3 = 2 which is absurd. so the question is wrong.

Ans 7:

Class : Class 9

Ans 8:

Class : Class 9
This question is completely wrong as when we factorise (a^2-13a 30) and (a^2 4a 4), we get (a-3)(a-10) and (a 2)^2 respectively. After calculating more, we get a-3=a 2 which has no solution as -3≠2

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Subject :IMO    Class : Class 4

Match the following.

Column 1----------Column 2

(i) 926543 (p) Smallest 5-digit number
(ii) 10000 (q) Place value of 2 is 2000
(iii) 962540 (r) 100039 when rounded off to nearest 100
(iv) 100000 (s) Successor of 926542


A (i) - (s), (ii) - (p), (iii) - (q), (iv) - (r)
B (i) - (q), (ii) - (r), (iii) - (s), (iv) - (p)
C (i) - (s), (ii) - (r), (iii) - (q), (iv) - (p)
D (i) - (q), (ii) - (p), (iii) - (s), (iv) - (r)


rd

Ans 1:

Class : Class 6

Ans 2:

Class : Class 4

Ans 3:

Class : Class 4

Ans 4:

Class : Class 5
aasefrfefsaxcfbt

Ans 5:

Class : Class 6
A

Ans 6:

Class : Class 8

Ans 7:

Class : Class 4
A is the answer.

Ans 8:

Class : Class 4

Ans 9:

Class : Class 3

Ans 10:

Class : Class 8
A

Ans 11:

Class : Class 5
a

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