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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 10
Answer: B
We have corrected the answer. Thanks for pointing out.

Solution
Perimeter of small square = 12 cm
Perimeter of big square = 18 cm
LCM of 12 and 18 = 36

Ans 2:

Class : Class 8
its 36 As the ant which walks around the square covers 12 cm in one round and the ant which walks around the rectangle covers 18 cm in one round. To find out when they will meet you can take the LCM of the distance they cover in one round. it is 36 so they will meet after both the ants cover 36 cm. Pravir

Ans 3:

Class : Class 8
its 36 As the ant which walks around the square covers 12 cm in one round and the ant which walks around the rectangle covers 18 cm in one round. To find out when they will meet you can take the LCM of the distance they cover in one round. it is 36 so they will meet after both the ants cover 36 cm. Pravir

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 7
wrong answer because the question says to include area of pathway as well as are of lawn

Ans 2:

Class : Class 7

Ans 3:

Class : Class 8
area of the shaded region Pravir

Ans 4:

Class : Class 8
solution let the side of the lawn(without the path) is xso the side of the lawn (with the path ) =x 2area =(x 2)^2 =x^2 4 4x40 =x^2 4 4x-x^2=40 =4 4x=40-4=4x=36=4x=x=36/4=x=9area of lawn=9*9=81area of lawn(including the path)=(9 2)*(9 2)=11*11=121

Ans 5:

Class : Class 7
but we had to find total area not area of lawn.....81 is only area of lawn.....the answer given is wrong

Ans 6:

Class : Class 9
area of the lawn is 81 sq mtr but your question says including the path which will be 121 sq mtr. this option is not there. You need to remove including path from the question.

Ans 7:

Class : Class 8
Correct answer is 40 (area of path) 81(area of lawn)=121 sq mtrs. This option is not given

Ans 8:

Class : Class 10
Answer : D

Solution
Let the length of one side of the path (outer square) be x.
Area of lawn + path = x2
Length of one side of the lawn = (x -2)
Area of path = x2 - (x-2)2 = 40
Solving the above equation x = 11
Side of lawn = 11 - 2 = 9
Area of lawn = 81 m2

Ans 9:

Class : Class 7
c

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 6
As mean of 5 number is 12. Therefore sum of the 5 number is 12x5=60 Mean of 4 number is 14 Sum=14x4=56. Therefore the removed no.is 60-56=4

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 8

Ans 2:

Class : Class 5
The answer should be 42

Ans 3:

Class : Class 9
the answer should be 42

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 5
( 25 * 110 ) + ( 32 * 120 ) =6590. So option A is correct.

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 8
answer is [A]

Ans 2:

Class : Class 8

Ans 3:

Class : Class 4

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 4
very tough pasina chhut gaya kisi ko ata he to solve karke dikhao

Ans 2:

Class : Class 6

Ans 3:

Class : Class 7
how do u solve this. Answer is not one of the options

Ans 4:

Class : Class 8

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 6

Ans 2:

Class : Class 8
answer is 10

Ans 3:

Class : Class 4
Yes you are rightI think

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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 5
question is incomplete

Ans 2:

Class : Class 9
I think the answer is D.

Ans 3:

Class : Class 9
I think the answer is D.

Ans 4:

Class : Class 4
Answer is B. school mugs=115.50 so mini bags=115.50-3=112.50 big bags=112.50+7.50=120 water jugs=476.25-(115.50+112.50+120)=128.25

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 9
ANS:D Because "5x+4=39" is an equation, not an expression. AND There is only one variable in OPTION A!

Ans 2:

Class : Class 8

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