International Maths Olympiad Forum By SOF Olympiad Trainer - Page 787
  1. Home
  2. /  Forum

User Forum

Ask Your Question
Rishit Sharma from Nehru World School, Ghaziabad
Subject :IMO    Class : Class 6

Ans 1:

Admin from SOF, Noida
Class : Class 10
Answer: B
We have corrected the answer. Thanks for pointing out.

Solution
Perimeter of small square = 12 cm
Perimeter of big square = 18 cm
LCM of 12 and 18 = 36

Ans 2:

Pravir Mishra from National Public School, Bengaluru
Class : Class 8
its 36 As the ant which walks around the square covers 12 cm in one round and the ant which walks around the rectangle covers 18 cm in one round. To find out when they will meet you can take the LCM of the distance they cover in one round. it is 36 so they will meet after both the ants cover 36 cm. Pravir

Ans 3:

Pravir Mishra from National Public School, Bengaluru
Class : Class 8
its 36 As the ant which walks around the square covers 12 cm in one round and the ant which walks around the rectangle covers 18 cm in one round. To find out when they will meet you can take the LCM of the distance they cover in one round. it is 36 so they will meet after both the ants cover 36 cm. Pravir

Post Your Answer

Rishit Sharma from Nehru World School, Ghaziabad
Subject :IMO    Class : Class 6

Ans 1:

Venneti Bhargav from gyan bharati, New Delhi
Class : Class 7
wrong answer because the question says to include area of pathway as well as are of lawn

Ans 2:

Allu Gowri sasaank from timpany school, Visakhapatnam
Class : Class 7

Ans 3:

Pravir Mishra from National Public School, Bengaluru
Class : Class 8
area of the shaded region Pravir

Ans 4:

VANSH Aggrawal from Surajkund International School, Faridabad
Class : Class 8
solution let the side of the lawn(without the path) is xso the side of the lawn (with the path ) =x 2area =(x 2)^2 =x^2 4 4x40 =x^2 4 4x-x^2=40 =4 4x=40-4=4x=36=4x=x=36/4=x=9area of lawn=9*9=81area of lawn(including the path)=(9 2)*(9 2)=11*11=121

Ans 5:

Mehreen Brar from Delhi Public School, Chandigarh
Class : Class 7
but we had to find total area not area of lawn.....81 is only area of lawn.....the answer given is wrong

Ans 6:

Ashwin Shridhar from Vidyashilp Academy, Bangalore
Class : Class 9
area of the lawn is 81 sq mtr but your question says including the path which will be 121 sq mtr. this option is not there. You need to remove including path from the question.

Ans 7:

Chaitanya L K from SKCHEC, bangalore
Class : Class 8
Correct answer is 40 (area of path) 81(area of lawn)=121 sq mtrs. This option is not given

Ans 8:

Admin from SOF, Noida
Class : Class 10
Answer : D

Solution
Let the length of one side of the path (outer square) be x.
Area of lawn + path = x2
Length of one side of the lawn = (x -2)
Area of path = x2 - (x-2)2 = 40
Solving the above equation x = 11
Side of lawn = 11 - 2 = 9
Area of lawn = 81 m2

Ans 9:

arvind kumar Singh from SUDHIR MEMORIAL INSTITUTE LILUAH HOWRAH, HOWRAH
Class : Class 7
c

Post Your Answer

Rishit Sharma from Nehru World School, Ghaziabad
Subject :IMO    Class : Class 6

Ans 1:

Sanjib ghosh from ,
Class : Class 6
As mean of 5 number is 12. Therefore sum of the 5 number is 12x5=60 Mean of 4 number is 14 Sum=14x4=56. Therefore the removed no.is 60-56=4

Post Your Answer

Sanjib ghosh from ,
Subject :IMO    Class : Class 6

Ans 1:

Sanket Kulkarni from Euroschool, Pune
Class : Class 8

Ans 2:

vaibhav jain  from bbps, New Delhi
Class : Class 5
The answer should be 42

Ans 3:

Abhjith S Kumar from Airport Senior Secondary school Karipur, Kozhikode Intl. Airport, Kozhikode Airport
Class : Class 9
the answer should be 42

Post Your Answer

Ankita Dharmani from Euroschool, Mumbai
Subject :IMO    Class : Class 4

Ans 1:

Darsh Jain from Advanced Academy, Indore
Class : Class 5
( 25 * 110 ) + ( 32 * 120 ) =6590. So option A is correct.

Post Your Answer

Ankita Dharmani from Euroschool, Mumbai
Subject :IMO    Class : Class 4

Ans 1:

Arihant kumar from Delhi public school,EOK, New Delhi
Class : Class 8
answer is [A]

Ans 2:

Arihant kumar from Delhi public school,EOK, New Delhi
Class : Class 8

Ans 3:

Mayank Raj from Litera velly, Patna
Class : Class 4

Post Your Answer

Sanjib ghosh from ,
Subject :IMO    Class : Class 6

Ans 1:

sachinthite@rocketmail.com from Sinhghad Public School Korti, Pandharpur
Class : Class 4
very tough pasina chhut gaya kisi ko ata he to solve karke dikhao

Ans 2:

Sayandeep Basu from Delhi Public School, Bengaluru
Class : Class 6

Ans 3:

Venneti Bhargav from gyan bharati, New Delhi
Class : Class 7
how do u solve this. Answer is not one of the options

Ans 4:

from , Bangalore
Class : Class 8

Post Your Answer

Renuka from Capstone High , Bengaluru
Subject :IMO    Class : Class 4

Ans 1:

Mannat Verma from Vivek High School , Chandigarh
Class : Class 6

Ans 2:

Apoorva from Blue Ridge Public School, Pune
Class : Class 8
answer is 10

Ans 3:

Parvanshu Sharma from Euro International School Gurgaon Sector-10, GURGAON
Class : Class 4
Yes you are rightI think

Post Your Answer

Dr. Rajeev Kumar Jha from ,
Subject :IMO    Class : Class 5

Ans 1:

palaksh goyal from ,
Class : Class 5
question is incomplete

Ans 2:

y rahaav karthikeyan from the indian public school, TIRUCHENGODE
Class : Class 9
I think the answer is D.

Ans 3:

y rahaav karthikeyan from the indian public school, TIRUCHENGODE
Class : Class 9
I think the answer is D.

Ans 4:

Ananya Singhal from Arwachin Bharti Bhawan Sr. Sec. School, Delhi
Class : Class 4
Answer is B. school mugs=115.50 so mini bags=115.50-3=112.50 big bags=112.50+7.50=120 water jugs=476.25-(115.50+112.50+120)=128.25

Post Your Answer

Sanjib ghosh from ,
Subject :IMO    Class : Class 6

Ans 1:

Taes Padhihary from Disha Delphi Public School, Kota
Class : Class 9
ANS:D Because "5x+4=39" is an equation, not an expression. AND There is only one variable in OPTION A!

Ans 2:

Nisarg Milan Salot from Narayana E-Techno School, Mumbai
Class : Class 8

Post Your Answer