Subject :IMO Class : Class 7
Subject :IMO Class : Class 7
Post Your Answer
Subject :IMO Class : Class 5
Ans 1:
Class : Class 6
oh my god. you have posted the easiest question in science olympiad foundation for grade 5 .
the ans is
july
Ans 4:
Class : Class 6
It is actually c because u should not count the cm in the month but in the before months increasing
Ans 6:
Class : Class 4
well the increase in height took place BETWEEN june and july so pls do explain which one shall i take
Ans 7:
Class : Class 5
D is the answer as increase in height in April is 10 cm.,May is 12 cm., June is 11 cm., and July is 13 cm.
So, the most increase in height took place in July.
Ans 8:
Class : Class 5
D is the answer as increase in height in April is 10 cm.,May is 12 cm., June is 11 cm., and July is 13 cm.
So, the most increase in height took place in July.
Ans 9:
Class : Class 8
yes, answer is C as the height was increased in June, not in July. The measure was taken on June 1st as mentioned. When you will read the question carefully, It will become really simple.Its not arduous at all.
Ans 10:
Class : Class 9
If anyone says July is the answer than you have told the wrong answer ,the answer is June
Ans 14:
Class : Class 7
If it is taken in the first month then it should be July..........................I think...................
Ans 17:
Class : Class 6
oh my god. you have posted the easiest question in science olympiad foundation for grade 5 .
the ans is
july
Post Your Answer
Subject :IMO Class : Class 5
Ans 5:
Class : Class 8
It should be Option C) because Obtuse Angle is always less than 180 but more than 90 and X shown in the figure is greater than 180 degree so it should be Reflex Angle
Ans 8:
Class : Class 5
I know you have this question from book of mtg imo class 5 chapter angles and question no. 10
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Subject :IMO Class : Class 5
Post Your Answer
Subject :IMO Class : Class 8
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Subject :IMO Class : Class 8
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Subject :IMO Class : Class 5
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Subject :IMO Class : Class 5
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Subject :IMO Class : Class 7
In the given figure, the area of the shaded portion is ________.
A308 cm2
B462 cm2
C154 cm2
D150 cm2
Ans 3:
Class : Class 9
TOTAL AREA OF FIGURE= 1/2 PI R^2= 1/2*14*14*22/7=308CM^2
AREA OF WHITE ARE= PI R^2 22/7*7*7=154 cm^2
THEREFORE RE O SHADED REGION= 308-154=154 CM^2 OPTION C IS CORRECT