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Vaishali Nair from Maneckji cooper, Mumbai
Subject :IMO    Class : Class 5

Ans 1:

Arkajyoti Das from techno, Cooch Behar
Class : Class 9

Ans 2:

Anusha from Npsk, Bangalore
Class : Class 8
Shaded area = Area of 4 small squares = 144m2Area of 1 small square = 144 ÷ 4 = 36m2Side of small square = = 6mWZ = XY = 3 x 6 = 18mWX = ZY = 4 x 6 = 24mPerimeter of rectangle = 2 x (18 24)= 84cm

Ans 3: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(A): Shaded area = Area of 4 small squares = 144 sq. m 
Area of 1 small square = 144 ÷ 4 = 36 sq. m
Side of small square = 6m
WZ = XY = 3 x 6 = 18m
WX = ZY = 4 x 6 = 24m
Perimeter of rectangle = 2 x (18 + 24)
= 84 m


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Tejashree Colvalcar from Sharda Mandir School, PANAJI GOA
Subject :IMO    Class : Class 8

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nikita dhingra from Delhi public school, Chandigarh, Chandigarh
Subject :IMO    Class : Class 9

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Harshdeep roy from Bhavans School , Nagpur
Subject :IMO    Class : Class 3

Ans 1:

Harshdeep roy from Bhavans School , Nagpur
Class : Class 7

Ans 2:

Arohan from VSV, Kolkata
Class : Class 3
2

Ans 3:

Tejas Kumar from Global Indian International School, Noida
Class : Class 5
pls explain solution

Ans 4:

KESHAV SINGHAL from AMITY INTERNATIONAL SCHOOL, NOIDA, NOIDA
Class : Class 3
how do we solve this?

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Aardev from Choithram School Manik Bagh, Indore
Subject :IMO    Class : Class 9

Ans 1:

q from s, v
Class : Class 9
It is 74 itself. Think of it like this: You have Rs. 9.7 with you and you want to buy as many chocolates as possible. In such a case, you can buy only 4 chocolates, as you are short of Rs. 0.3. Dividing 9.7 by 2 gives 4.85 that can be approximated to 5, which is wrong as 5 chocolates require Rs. 10 (you need Rs. 0.3 more). So, you can use the amount less than or equal to what you have with you.

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Akshat from BRIGHTON INTERNATIONAL SCHOOL, RAIPUR
Subject :IMO    Class : Class 5

Ans 1:

Sonakshi from APS Bolarum, Secunderabad
Class : Class 5
Hi

Ans 2:

Sonakshi from APS Bolarum, Secunderabad
Class : Class 5

Ans 3:

Chinmay Goyal from Gems Modern Academy, Gurgaon
Class : Class 5
how

Ans 4: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is option B. 


Ans 5:

Sarvottam Nayak from Kendriya Vidyalaya, Nagpur
Class : Class 6
The correct ans is C

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Yug from Vibgyor, Pune
Subject :IMO    Class : Class 1

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B): 68 < 70 < 75 < 86
Therefore, doll in option (B) has the minimum cost.


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Prateek Sethi from DAV PUBLIC SCHOOL NTPC TTPS THERMAL, THERMAL
Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(D): Number of pages Monika read = (1/3) x total number of pages

                                                        = (1/3) x 48 = 16

 


Ans 2:

Rohith from Hindustan international school, Chennai
Class : Class 4
1/31/3

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sankerths s from Shishya BELM public School, Bangalore
Subject :IMO    Class : Class 5

Ans 1:

Keshav from Step by step school sawai madhupur, Sawai madhopur
Class : Class 7

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(A): We have,
1567.79 × 100 + 634.76 × 100 -? = 110255
⇒ 156779 + 63476 -? = 110255
 ? = 110000
= 1.1 × 100000


Ans 3:

Satwik Dixit from Christ Academy, Bangalore
Class : Class 7
We have,1567.79 × 100 634.76 × 100 -? = 110255⇒ 156779 63476 -? = 110255 ? = 110000= 1.1 × 100000

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Aadvik saini from Mvn sector 17, Faridabad
Subject :IMO    Class : Class 5

Ans 1:

Sargun Maini from The Khaitan School, NOIDA
Class : Class 6

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(A): Number of students appeared in Hindi exam 
= 50
Number of students appeared in Science exam 
= 40
So, required fraction = 


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