Subject :IMO Class : Class 7
Ans 1:
Class : Class 8
a2+b2=c2
Ans 2:
Class : Class 7
(H)2=(P)2+(B) 2
Ans 3:
Class : Class 7
A2+B2=C2
Ans 4:
Class : Class 9
Hypotenuse^2= P^2 + B^2
Here, P=perpendicular height and B=base.
Ans 5:
Class : Class 7
Hypotenuse=base×base+hieght×height
Base=hypotenuse×hypotenuse -height ×height
Height=base×base - hypotenuse×hypotenuse
Ans 6:
Class : Class 9
square of hypotenuse=sum of square of other 2 legs in a right angled triangle
Ans 7:
Class : Class 8
Hypotenuse=(side1)*2+(side2)*2
Ans 8:
Class : Class 7
The pythagoras' theorem states that the square of the hypotenuse is equal to the sum of the square of the other 2 sides. The equation would be hyp2=S12+S22
note: the 2 is the power of two
Ans 9:
Class : Class 7
Square of hypotenuse=Square of its legs
Ans 10:
Class : Class 8
AB2+BC2=AC2
THIS MEANS THAT IN A TRIANGLE WHEN WE ADD THE SQUARE OF THE BASE AND PARALLEL ANGLE IT WILL ALWAYS BE EQUAL TO THE HYPOTENUSE.
Ans 11:
Class : Class 7
(H)2=(P)2+(B) 2
Ans 12:
Class : Class 8
Asquare+B square = C square (hypotenuse)
Ans 13:
Class : Class 7
(H)2=(P)2+(B) 2
Ans 14:
Class : Class 9
a = 1 side,
b = another side,
c = hypotenuse (the longest side).
The formula is:
a2 + b2 = c2
(the two means squared, not multiplied by two).
The formula only works in right-angled triangles.
Ans 15:
Class : Class 9
(H)2=(P)2+(B)2
Ans 16:
Class : Class 8
square of base + square of perpendicular side = square of hypoteneuse