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sankerths s from Shishya BELM public School, Bangalore
Subject :IMO    Class : Class 5

Ans 1:

Satwik Dixit from Vibgyor High, Bangalore
Class : Class 6
We have,1567.79 × 100 634.76 × 100 -? = 110255⇒ 156779 63476 -? = 110255 ? = 110000= 1.1 × 100000

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(A): We have,
1567.79 × 100 + 634.76 × 100 -? = 110255
⇒ 156779 + 63476 -? = 110255
 ? = 110000
= 1.1 × 100000


Ans 3:

Keshav from Step by step school sawai madhupur, Sawai madhopur
Class : Class 7

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Aadvik saini from Mvn sector 17, Faridabad
Subject :IMO    Class : Class 5

Ans 1:

Sargun Maini from The Khaitan School, NOIDA
Class : Class 6

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(A): Number of students appeared in Hindi exam 
= 50
Number of students appeared in Science exam 
= 40
So, required fraction = 


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Akash Mukhoti from Hiranandani Foundation School, Powai , Mumbai
Subject :IMO    Class : Class 6

Ans 1:

Prabhav Akar from Cambridge Court High School, Jaipur
Class : Class 1
It should be zero if they all are parallel.

Ans 2:

PRANAB KUMAR from MARIAS PUBLIC SCHOOL, Guwahati
Class : Class 6
OPTION A

Ans 3:

Aryav Gupta from BomBay Scottish Mumbai, Mumbai
Class : Class 6

Ans 4:

Rajendra Karwasra from BDIS, Sri Ganganagar
Class : Class 6
OPTION A

Ans 5:

Aryav Gupta from BomBay Scottish Mumbai, Mumbai
Class : Class 6
0 if they r parellel

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Kushal from Chirec, Hyderabad
Subject :IMO    Class : Class 7

Ans 1:

Shaman Amin from SDM school, Mangalore
Class : Class 10
According to me answer should be D

Ans 2:

Gauri Singh from St Johns School Marhauli, Varanasi
Class : Class 8
B is the answer

Ans 3:

Deepak Iyer from HFS Powai, Mumbai
Class : Class 7

Ans 4:

AADHYA AGRAWAL from VIBGYOR HIGH, MUMBAI
Class : Class 8

Ans 5:

Ishaan from ST. JUDE, Kerala
Class : Class 7

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Krisha from gurukul, pune
Subject :IMO    Class : Class 2

Ans 1:

Gaurika Bhasin from Genesis global school, Noida
Class : Class 2
Ignore

Ans 2:

Gaurika Bhasin from Genesis global school, Noida
Class : Class 2
Cost of 2 clocks = 2 x 97 = Rs 194Cost of 2 clocks and a watch = Amount he gave to cashier - Amount he received as change = 250 - 12 = 238Cost of watch = 238 – 194 = Rs 44Close

Ans 3:

Krisha from gurukul, pune
Class : Class 1
you are poty

Ans 4:

Gaurika Bhasin from Genesis global school, Noida
Class : Class 2
Cost of 2 clocks = 2 x 97 = Rs 194Cost of 2 clocks and a watch = Amount he gave to cashier - Amount he received as change = 250 - 12 = 238Cost of watch = 238 – 194 = Rs 44Close

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Krisha from gurukul, pune
Subject :IMO    Class : Class 2

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B): Number of hours Reema works = 9 hrs ( 1pm - 10pm )
Amount she earns altogether = 8+8+8+8+8+8+8+8+8 = Rs 72


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Krisha from gurukul, pune
Subject :IMO    Class : Class 2

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B): Time half an hour after 1:45 pm = 2:15 pm
2:15 is shown in clock  given in option B.  


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Maya Vijay from NPS Chennai, Chennai
Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B)

Order of rotational symmetry = 6 


Ans 2:

Joshua Sen from Montfort Senior Secondary School, Roorkee
Class : Class 9
but da hexagon is wonky

Ans 3:

Adhrit from CHSV, Chennai
Class : Class 8
How do we know if the hexagon is regular or not? It never mentions anything about that you really should make the questions less ambiguous

Ans 4:

Kumar Krishiv from Apeejay School, Noida
Class : Class 8
yes and in the figure too it seems like sides are not equal

Ans 5:

Vinayak Iyer from Podar International School Powai, Mumbai
Class : Class 9

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Sarah Nawalkar from Rajhans Vidhyalaya, Mumbai
Subject :IMO    Class : Class 4

Ans 1:

Nivritti Agarwal from National public school, Bangalore
Class : Class 7
A): Amount of money Bhavya saves in one month = ₹ (2550 - 1875) = ₹ 675∴ Her savings in one year= ₹ (12 × 675) = ₹ 8100Her savings in 3 years = 3 × 8100= ₹ 24300

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(A): Amount of money Bhavya saves in one month = ₹ (2550 - 1875) = ₹ 675
∴ Her savings in one year
= ₹ (12 × 675) = ₹ 8100
Her savings in 3 years = 3 × 8100
= ₹ 24300


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Sanchay Agarwal from Delhi Public School, Roorkee
Subject :IMO    Class : Class 8

Ans 1:

mukul from lancer, delhi
Class : Class 1
son

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