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rachana from delhi public school, NACHARAM
Subject :IMO    Class : Class 3

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rachana from delhi public school, NACHARAM
Subject :IMO    Class : Class 3

Ans 1:

AYUSHMAN from St Marys Convent Sr Sec School Jaipur, JAIPUR
Class : Class 6
D

Ans 2:

rachana from delhi public school, NACHARAM
Class : Class 3
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SHAUNAK from St Xaviers School, HAZARIBAG
Subject :IMO    Class : Class 3

Ans 1:

Tejaojas Abhilash from National Public School, malayalam
Class : Class 4

Ans 2:

from DPS, Secunderabad
Class : Class 3
to largest

Ans 3:

from DPS, Secunderabad
Class : Class 3
it's b option. but i thought it's a

Ans 4:

SHAUNAK from St Xaviers School, HAZARIBAG
Class : Class 3
B is the right answer.

Ans 5:

AYUSHMAN from St Marys Convent Sr Sec School Jaipur, JAIPUR
Class : Class 6
B

Ans 6:

R DAS. from TIGPS, SREERAMPUR
Class : Class 4

Ans 7:

from DPS, Secunderabad
Class : Class 3
and because i thought it's smallest

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Ayushree Barman from Sri Sri Academy, Kolkata
Subject :IMO    Class : Class 5

Ans 1:

Biju Pappachan from Rkc , Raipur
Class : Class 1
The correct answer is A. Because:Pieces of pizza =8. No.of children =5. So, 8-5=3. Hence the correct answer is 3/8.

Ans 2:

Arunava hury from KV1 saltlake , Kolkata
Class : Class 6
Option C)

Ans 3:

Nandini from Blue Ridge Public School, Pune
Class : Class 5
A. 3/8. 1/8 X 5 = 5/8. (One Whole) 8/8 - 5/8 = 3/8.

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Adawaya Dua from Delhi Public School, Roorkee
Subject :IMO    Class : Class 3

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Adawaya Dua from Delhi Public School, Roorkee
Subject :IMO    Class : Class 3

Ans 1:

Eklavya Gondule from DPS Bhilai, BHILAI
Class : Class 7

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Harsh Kumar from Maharishi Vidya Mandir, Guwahati
Subject :IMO    Class : Class 7

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TAVISHI BHATTACHARYA from PODAR INTERNATIONAL SCHOOL, AHMEDABAD
Subject :IMO    Class : Class 4

Ans 1:

Prachi from Holy child public school, Faridabad
Class : Class 7
Answer is C

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Sriyansh from Surabhi , Hosapete
Subject :IMO    Class : Class 8

The given figure is made up of a triangle and two identical semi-circles. P and Q are the centres of semicircles. If EP is the radius of the semicircle and measures 14 cm, then find the total shaded area.


A156 cm2
B108 cm2
C250 cm2
DNone of these


The solution to this question by sof Olympiad trainer is: Area of the 2 semi-circles = 2(½ π 142) cm2 = 22/7 x 14 x 14 = 616 cm2 So, the answer is - Dbut both the semicircles are not completely shaded???????

Ans 1:

CHIRAG from JINDAL VIDYA MANDIR, RATNAGIRI
Class : Class 10
The solution explanation is wrong.two semicircles are not shaded only.

Ans 2:

Naivedya Moondra from Lake Montfort, BANGALORE
Class : Class 8

Ans 3:

Aaryan from New horizons public school , Mumbai
Class : Class 8

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Sriyansh from Surabhi , Hosapete
Subject :IMO    Class : Class 8

Ans 1:

Inesh Dheer from Bhavan Vidyalaya, Chandigarh
Class : Class 8

Ans 2:

Tagore Tathagath Gedela from Dimensions international College, Singapore
Class : Class 8
help me

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