International Maths Olympiad Forum By SOF Olympiad Trainer - Page 422
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Ishat from DPS, GURUGRAM
Subject :IMO    Class : Class 8

Ans 1:

Arnav Raj Sharma from GEMS International School the ultra master mega, Gurgaon
Class : Class 7
should be option D

Ans 2:

Ayaan jamal from Dddddd, Delhi
Class : Class 5
yes true...cuz the last line which it is telling to construct is not the actual one

Ans 3:

Nishchay Gupta from Cambridge Court World School, Jaipur
Class : Class 6
Yes it should be Option (D) Step IV

Ans 4:

Ketaki Subhash Ghatol from CSA Satara, Satara
Class : Class 8

Ans 5:

Arnav Diwan from F.A.I.P.S Kuwait, Kuwait
Class : Class 10
4 and 3 both are wrong as in 3rd one it says to join diagonals which is useless and 4th one you know why

Ans 6:

Ambati Daivik from Kendriya Vidyalaya, Dharwad
Class : Class 10
yes the option is D

Ans 7:

Arnav Diwan from F.A.I.P.S Kuwait, Kuwait
Class : Class 10
Step 4 and 3 both are incorrect

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Shayan Bari from Kendriya Vidyalaya, Katihar
Subject :IMO    Class : Class 7

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Lakshmi from FPS, Bangalore
Subject :IMO    Class : Class 6

Ans 1:

Kavitharini Joseph from HUS, Chennai
Class : Class 6
how?

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Tamrashi Pani from National Public School, Bangalore
Subject :IMO    Class : Class 6

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RUKU from raj school , GAYA
Subject :IMO    Class : Class 10

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Shourya Bhushan from DPS Gurgaon, Gurgaon
Subject :IMO    Class : Class 5

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Rama Panda from tathva, tokyo
Subject :IMO    Class : Class 5

Ans 1:

Aditri Sultania from RBK Global School, Mumbai
Class : Class 5
answer is option C

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ARUSH RATHOD from GEMS Modern Academy, Dubai
Subject :IMO    Class : Class 6

Ans 1:

pranavramesh from sri chaitanya techno school, Chennai
Class : Class 6
erroror2ikopdfireso hggggr

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ARUSH RATHOD from GEMS Modern Academy, Dubai
Subject :IMO    Class : Class 6

Ans 1:

Aadvik saini from Mvn sector 17, Faridabad
Class : Class 8

Ans 2:

Arya Kiran from PSBB KK NAGAR, Chennai
Class : Class 9

Ans 3:

Arnav Nandan from ST PETERS COLLEGE AGRA, Agra
Class : Class 9
SOLUTION HAS A MISTAKE.420x100= 42000 not 4200.

Ans 4:

Ayansh Modi from Air Force Bal Bharti, Delhi
Class : Class 5

Ans 5:

Satwik Dixit from Christ Academy, Bangalore
Class : Class 7
Let the number of coins of ₹ 1 = 5xNumber of coins of 50 paise = 6xAnd number of coins of 25 paise = 8xAccording to question,5x × 100 6x × 50 8x × 25 = 420 × 100⇒ 500x 300x 200x = 4200⇒ 1000x = 42000 ⇒ x = 42∴ Number of coins of ₹ 1 = 5 × 42 = 210Number of coins of 50 paise = 6 × 42 = 252Number of coins of 25 paise = 8 × 42 = 336∴ Total number of coins= 210 252 336 = 798

Ans 6:

Arya from Global Indian International School, AHMEDABAD
Class : Class 7

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Shubhankar Vijay Dhondge from NPS Whitefield, Benagaluru
Subject :IMO    Class : Class 2

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