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Veda Walavalkar from Vibgyor, Goregaon(west)
Subject :IMO    Class : Class 1

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is B.

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Veda Walavalkar from Vibgyor, Goregaon(west)
Subject :IMO    Class : Class 1

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is C.

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Ruchi Khanna from strawberry fields high school , Chandigarh
Subject :IMO    Class : Class 5

Ans 1:

Maedhavi Bhargava from Maharaja Sawai Mansingh Vidyalaya, Jaipur
Class : Class 5
56/3÷8/3 56/3*3/8 56/8 =7

Ans 2:

Antareep from IVWS, Kolkata
Class : Class 6
A

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Arjun Adate from Pawar Public School , Pune
Subject :IMO    Class : Class 3

Ans 1:

JIYA GOSWAMI from DPS, Ranchi
Class : Class 6
Using Factorial for Class 3 seems difficult. I taught my daughter as under:- Step 1 - Put 7 at thousand place and how many different numbers we can get --She replied 6 Step 2- Put 5 at thousand place and how many different numbers we can get --She replied 6 Step 3 -Put 0 at thousand place , do we get four digit number --She replied NO Ste 4 - Put 2 at thousand place and how many different numbers we can get --She replied 6 Step 5 - Add numbers obtained in above steps we get 18

Ans 2:

Shaurya Tandon from Amity International, Noida
Class : Class 3

Ans 3:

Shaurya Tandon from Amity International, Noida
Class : Class 3
lol class 1 ha ha ha..

Ans 4:

Vibhuraman from NPS, Bangalore
Class : Class 3
n!-(n-1)! is the answer. n is number of digits here. (n-1)! is subtracted from n! since there is digit with 0. otherwise it is just n! Now How do you calculate n!. For example 4! here. 4! = 4x3x2x1 = 24 (4-1)! = 3! = 3x2x1 = 6 Hence the answer is n! - (n-1)! = 4! - (4-1)! = 4! - 3! = 24 -6 = 18 Option D is the answer.

Ans 5:

Tanishka from Gopalan International School, Bangalore
Class : Class 3
its so easy right

Ans 6:

Rudra Veer Singh from Delhi Public School Noida, Noida
Class : Class 4
TOUGH FOR CLASS 1

Ans 7:

Varesh Hemwani from R.D Public School Betul, betul
Class : Class 3
(D) 18

Ans 8:

Suyash Maurya from Chandresh Lodha Memorial School, Dombivali
Class : Class 3

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AKSHITA.KRISHNAN from DPS Noida, Noida
Subject :IMO    Class : Class 3

Ans 1:

Rajveer from DPS, Bengaluru
Class : Class 3
c

Ans 2:

Varesh Hemwani from R.D Public School Betul, betul
Class : Class 3
(C) 7 tables

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Siddharth from Kennedy Global The High, hydeabad
Subject :IMO    Class : Class 5

Ans 1:

PANAV TANEJA from Ivy world school, Jalandhar
Class : Class 5

Ans 2:

Paavak Miital from TMS HMEL, Bathinda
Class : Class 6
Rectangle have 2 line of symmetry only so answer should be C

Ans 3:

Nihal from Euro school, BANGALORE
Class : Class 7
D

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Sahil A from Head Start Educational Academy, Bengaluru
Subject :IMO    Class : Class 6

Ans 1:

Mobbassir jillany from D.A.V Publice school, Borako
Class : Class 6
The answer is (a) QSPBMFN

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Rehan Agrawal from Indian School Ghubra, Muscat
Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is A.

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Swastik from Aps jorhat, Jorhat
Subject :IMO    Class : Class 4

Ans 1:

Aaddya Deshmukh from Euro School Wakad, Pune
Class : Class 5
If your setup box is tata sky then I think 457

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nidhi from S M shetty HIgh school, MUMBAI
Subject :IMO    Class : Class 4

Ans 1:

Arav Aanand from Father Agnel School, Noida
Class : Class 6
It is B %100 sure 23+32=53=5.5 Even if it is confusing the answer is B itself.

Ans 2:

digamber12 from st francies xavier english medium school ajgaon, sawantwadi
Class : Class 4
B

Ans 3:

Arav Aanand from Father Agnel School, Noida
Class : Class 6
It is B %100 sure 23+32=53=5.5 Even if it is confusing the answer is B itself.

Ans 4:

shashwat from Podar international school, karad
Class : Class 2
Make the figures as complete fractions, then bring the denominator as the same values and then solve

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