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AKSHAT.PATHAK from DPS Sector 30, Noida
Subject :IMO    Class : Class 2

Ans 1:

AKSHAT.PATHAK from DPS Sector 30, Noida
Class : Class 2

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Devendra Negi from Air Force School Jamnagar , Jamnagar
Subject :IMO    Class : Class 4

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is B.

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SPANDITA PRADHAN from STEWART SCHOOL, CUTTACK
Subject :IMO    Class : Class 3

Ans 1:

SPANDITA PRADHAN from STEWART SCHOOL, CUTTACK
Class : Class 3

Ans 2:

Mayank from aneja public school, rewari
Class : Class 3
D 1 hr 40 mins

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SPANDITA PRADHAN from STEWART SCHOOL, CUTTACK
Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is A.

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SPANDITA PRADHAN from STEWART SCHOOL, CUTTACK
Subject :IMO    Class : Class 3

Ans 1:

SPANDITA PRADHAN from STEWART SCHOOL, CUTTACK
Class : Class 3
328

Ans 2:

nick Gupta from sky world , Panchkula
Class : Class 3

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SPANDITA PRADHAN from STEWART SCHOOL, CUTTACK
Subject :IMO    Class : Class 3

Ans 1:

Ashmi Narkar from VIBGYOR HIGH , Airoli, Navi Mumbai, NAVI MUMBAI
Class : Class 5
SolutionTotal no. of days in January 20XX = 31 Now, let’s see how many days’ leave Priya took in January. Priya takes a leave on 2nd Saturday and 4th Saturday in January. That means she takes leave on January 12 and January 26. That’s 2 days of leave. There are four Sundays in January – January 6, January 13, January 20 and January 27. Sundays are holidays. That’s 4 days of leave. Republic day is also a holiday. But Republic Day falls on January 26, which is 4th Saturday. And Priya has already taken leave on 4th Saturday. So, it has been counted in leave earlier. So, total no. of days when Priya took leave = 2 4 = 6 days. Working days in January 20XX = Total days – Leave days = 31 – 6 = 25 days So, the right answer is Option A.

Ans 2:

kendre vaishnavi mangesh from podar international school , latur
Class : Class 5

Ans 3: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is A.

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SPANDITA PRADHAN from STEWART SCHOOL, CUTTACK
Subject :IMO    Class : Class 3

Ans 1:

Ashmi Narkar from VIBGYOR HIGH , Airoli, Navi Mumbai, NAVI MUMBAI
Class : Class 5
SolutionLetter L (Option A), Letter N (Option C) and Letter V (Option D) are formed by straight lines only. But Letter D (Option B) is formed by a straight line and a curved line. So, Option B is the odd one out.

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is B.

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Mannan from Sherwood High, Bengaluru
Subject :IMO    Class : Class 3

Ans 1:

Mayank from aneja public school, rewari
Class : Class 3
CHART IS NOT GIVEN . YOU SHOULD GIVE THE CHART

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Gopi Krishna from Kendriya Vidyalaya, Gerukamukh
Subject :IMO    Class : Class 6

Ans 1:

Harshit from Dayawati Modi International, Meerut
Class : Class 6
See the pattern of the given answer Answer is First letter of second no. Then first letter of 1 No. And then goes on So Answer is C

Ans 2:

fadeel khan from gear innovative international school, Bengaluru
Class : Class 9
it is c

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Ashmi Narkar from VIBGYOR HIGH , Airoli, Navi Mumbai, NAVI MUMBAI
Subject :IMO    Class : Class 2

Ans 1:

Vedansh Lal from VVP, Bangalore
Class : Class 2
it is not written onion and cabbage not onions and cabbages. So the ans should be 400.

Ans 2:

ALICE from CENTRAL ACADEMY, UDAIPUR
Class : Class 4

Ans 3:

Ayushmaan Mishra from DePaul school , Berhampur
Class : Class 4
Total weight of onion and cabbage is 100 gm not onions and cabbages.answer will be 400 gm

Ans 4:

ALICE from CENTRAL ACADEMY, UDAIPUR
Class : Class 4
Total weight of the onion and cabbage =100gm.Total weight of 2 onions and 2 cabbages= 200gm, which is equivalent to the weight of one papaya. 1 papaya=200gm, hence 2 papayas= 400gm. Option B is the correct answer.

Ans 5: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The weight of 1 papaya is 100 gm. Hence, the correct answer is A.

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