International Maths Olympiad Forum By SOF Olympiad Trainer - Page 355

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Subject :IMO    Class : Class 7

Find the values of P, Q and R.
(i) A circular pond is surrounded by a 2 m wide circular path. If outer circumference of circular path is 44 m, then the area of the path is __p__.

(ii) A rectangular courtyard measuring 17 m by is to be covered by square slabs, each of side m. __Q__ slabs are required to cover the courtyard.

(iii) The minute hand of a circular clock is 15 cm long. The tip of the minute hand move __R__ cm in 1 hour? (π = 3.14)

P Q R
A 62.88 m2 348 100
B 75.43 m2 646 94.2
C 42.87 m2 200 44.5
D 18.14 m2 544 79.4


why is not any solution there

Ans 1:

Class : Class 7
answer is B

Ans 2:

Class : Class 8
Answer is B.. You can find it by finding the third answer.. circumference of minute hand's path = 2x3.14x15 = about 94..

Ans 3:

Class : Class 9
why is not there any solution

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Subject :IMO    Class : Class 7

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Subject :IMO    Class : Class 8

Ans 1:

Class : Class 8

Ans 2:

Class : Class 5

Ans 3:

Class : Class 7
There is a small error here

Ans 4:

Class : Class 7
90-v, slight printing error

Ans 5:

Class : Class 5
The answer should be d but the option is written wrong it should be 90-v not 90 v so i hope you get it

Ans 6:

Class : Class 5

Ans 7:

Class : Class 4
agree

Ans 8:

Class : Class 8
90 - v not 90v

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Subject :IMO    Class : Class 8

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Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Class : Class 1

Let Cost price be ‘x’.
Selling price = x – 15% of x = 85x /100
85x /100 = 1275
So, x(cost price) = 127500/85 = Rs. 1,500
So, new selling price = 1500 + 10% of 1500
= 1500 + 150 = Rs. 1650
Answer-(D) Rs 1650


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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 9

Ans 2:

Class : Class 6

Ans 3:

Class : Class 6
they are cheaters.i did c and they said i did b

Ans 4: (Master Answer)

Class : Class 1

(C): It is given that,
Area of rectangle = Area of square
⇒ l × b = side × side
Also, length of rectangle = perimeter of square


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Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Class : Class 1

(D): The pattern followed is


Ans 2:

Class : Class 8
Why no solution ??

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Subject :IMO    Class : Class 2

Ans 1: (Master Answer)

Class : Class 1

(C): 1 : 20 + 170 + 20 = 210
2 : 120 + 70 + 5  = 195
3 : 70 + 200 + 20  = 290
As, 290>210>195

So, 3 > 1 > 2


Ans 2:

Class : Class 2
1 : 2 x 10 17 x 10 20 x 1 = 2102 : 12 x 10 7 x 10 5 x 1 = 1953 : 7 x 10 20 x 10 20 x 1 = 2903 > 1 > 2Close1 : 2 x 10 17 x 10 20 x 1 = 2102 : 12 x 10 7 x 10 5 x 1 = 1953 : 7 x 10 20 x 10 20 x 1 = 2903 > 1 > 2Close1 : 2 x 10 17 x 10 20 x 1 = 2102 : 12 x 10 7 x 10 5 x 1 = 1953 : 7 x 10 20 x 10 20 x 1 = 2903 > 1 > 2Close1 : 2 x 10 17 x 10 20 x 1 = 2102 : 12 x 10 7 x 10 5 x 1 = 1953 : 7 x 10 20 x 10 20 x 1 = 2903 > 1 > 2Close

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Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Class : Class 1

(D): Second multiple of 12 = 12 x 2 = 24
Third multiple of 8 = 8 x 3 = 24
Multiplying the second multiple of 12 by the third multiple of 8 = 24 x 24 = 576
 


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Subject :IMO    Class : Class 4

Ans 1: (Master Answer)

Class : Class 1

(D):  A) XV - Fifteen
        B) XIX - Nineteen
       C) XXVI - Twenty six
       D) IXIV is meaningless.


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