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Subject :IMO    Class : Class 4

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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 6
IT SHOULD BE 1 NOT 2. 1/2 1/2 = 1

Ans 2:

Class : Class 5
It should be 1 not 2 because half half = 1

Ans 3:

Class : Class 6
D)

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Subject :IMO    Class : Class 8

Fill in the blanks.
(i) The perimeter of circle and its diameter vary __P__ with each other.
(ii) If two quantities p and q vary inversely with each other then __Q__ of their corresponding values remain constant.
(iii) When x and y are in indirect proportion and if y doubles then x becomes __R__

P Q R
A Inversely Ratio Double
B Directly Product Half
C Inversely Ratio Double
D Directly Product Half


A and c , b and d are same.

Ans 1:

Class : Class 8
B and D are identical

Ans 2:

Class : Class 9
answer is both B and D

Ans 3:

Class : Class 8
How can they give they two same options and mark one wrong

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 7
it is very simple and can be solved with Pythagoras.Length=2y Breadth=yroot of [(2y)square ysquare]=9 x root of 5root of [4ysquare ysquare]=9 x root of 5root of 5ysquare=9 x root of 5 = y x root of 5thus y = 9 and 2y = 18p=54

Ans 2:

Class : Class 8
pl give solution, very confusing question

Ans 3:

Class : Class 7
This can be solved like this: take length as 2x and breadth as x. Applying the pythagoras theorem, (x)^2 (2x)^2 = (9 * root 5)^2. Equal to x squared 4x squared = 9 squared * root 5 squared 5x squared = 81 * 5. 5 and 5 cancel on both sides. x squared = 81 x = 9 = breadth 2x = 18 = length perimeter = 2 (l b) 2 * 27 = 54

Ans 4:

Class : Class 7
First of all,diagonal of a rectanhle=square root of l^2 b^2,so 9×square root of 5 is square root of 81 × 5 that is 405 so here 2x is l and x is b.if i m taking l is 18 and b is 9 and squaring them we get 405 so perimeter of the rectangle is 2(18 9) that is 54.

Ans 5:

Class : Class 6

Ans 6:

Class : Class 9
explaination of answer not provide....how to check the solution??

Ans 7:

Class : Class 7
w=xl=2xd=9root52(l b)=?2(x 2x)=?using pythogras theorem,xsquare 4 x square=(9root5)squared5xsquare=405x square=81x=9hence substitute values with x,perimeter=54

Ans 8:

Class : Class 7
Sorry diagonal of a rectangle is l^2 b^2

Ans 9:

Class : Class 7
please provide explanation soon

Ans 10:

Class : Class 9
give explanation please.

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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 6
C)

Ans 2:

Class : Class 6
C)

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Subject :IMO    Class : Class 6

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Subject :IMO    Class : Class 6

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 5

Ans 2:

Class : Class 4
c

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 6

Ans 2:

Class : Class 6
the answer should be equilateralbecause we have studied everywhere that two equilateral triangle(with same length) are kept such as there one side of both the triangle are adjacent , is a square

Ans 3:

Class : Class 6
is this answer correct ?what is the answer.....correct or no

Ans 4:

Class : Class 6

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Subject :IMO    Class : Class 3

Ans 1:

Class : Class 6
aarav parikh take every box from right and solve the answer436 B

Ans 2:

Class : Class 5

Ans 3:

Class : Class 4
436 B

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