# User Forum Subject :IMO    Class : Class 4

Subject :IMO    Class : Class 5

## Ans 1:

Class : Class 6
IT SHOULD BE 1 NOT 2. 1/2 1/2 = 1

## Ans 2:

Class : Class 5
It should be 1 not 2 because half half = 1

## Ans 3:

Class : Class 6
D)

Subject :IMO    Class : Class 8

## Ans 1:

Class : Class 8
B and D are identical

## Ans 2:

Class : Class 9
answer is both B and D

## Ans 3:

Class : Class 8
How can they give they two same options and mark one wrong

Subject :IMO    Class : Class 7

## Ans 1:

Class : Class 7
it is very simple and can be solved with Pythagoras.Length=2y Breadth=yroot of [(2y)square ysquare]=9 x root of 5root of [4ysquare ysquare]=9 x root of 5root of 5ysquare=9 x root of 5 = y x root of 5thus y = 9 and 2y = 18p=54

## Ans 2:

Class : Class 8
pl give solution, very confusing question

## Ans 3:

Class : Class 7
This can be solved like this: take length as 2x and breadth as x. Applying the pythagoras theorem, (x)^2 (2x)^2 = (9 * root 5)^2. Equal to x squared 4x squared = 9 squared * root 5 squared 5x squared = 81 * 5. 5 and 5 cancel on both sides. x squared = 81 x = 9 = breadth 2x = 18 = length perimeter = 2 (l b) 2 * 27 = 54

## Ans 4:

Class : Class 7
First of all,diagonal of a rectanhle=square root of l^2 b^2,so 9Ãsquare root of 5 is square root of 81 Ã 5 that is 405 so here 2x is l and x is b.if i m taking l is 18 and b is 9 and squaring them we get 405 so perimeter of the rectangle is 2(18 9) that is 54.

Class : Class 6

## Ans 6:

Class : Class 9
explaination of answer not provide....how to check the solution??

## Ans 7:

Class : Class 7
w=xl=2xd=9root52(l b)=?2(x 2x)=?using pythogras theorem,xsquare 4 x square=(9root5)squared5xsquare=405x square=81x=9hence substitute values with x,perimeter=54

## Ans 8:

Class : Class 7
Sorry diagonal of a rectangle is l^2 b^2

Class : Class 7

## Ans 10:

Class : Class 9

Subject :IMO    Class : Class 5

Class : Class 6
C)

## Ans 2:

Class : Class 6
C)

Subject :IMO    Class : Class 6

Subject :IMO    Class : Class 6

Subject :IMO    Class : Class 4

Class : Class 5

## Ans 2:

Class : Class 4
c

Subject :IMO    Class : Class 6

Class : Class 6

## Ans 2:

Class : Class 6
the answer should be equilateralbecause we have studied everywhere that two equilateral triangle(with same length) are kept such as there one side of both the triangle are adjacent , is a square

Class : Class 6

## Ans 4:

Class : Class 6

Subject :IMO    Class : Class 3

## Ans 1:

Class : Class 6
aarav parikh take every box from right and solve the answer436 B

Class : Class 5

Class : Class 4
436 B