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Aditya vardhan roy from Bharatiya vidya bhavan vidyashram jaipur , Jaipur
Subject :IMO    Class : Class 7

Ans 1:

Harsh Shukla from DPS Bangalore East, Bengaluru
Class : Class 9
This can be solved like this: take length as 2x and breadth as x. Applying the pythagoras theorem, (x)^2 (2x)^2 = (9 * root 5)^2. Equal to x squared 4x squared = 9 squared * root 5 squared 5x squared = 81 * 5. 5 and 5 cancel on both sides. x squared = 81 x = 9 = breadth 2x = 18 = length perimeter = 2 (l b) 2 * 27 = 54

Ans 2:

Karthikeyan from Velammal bodhi campus, Thanjavur
Class : Class 7
First of all,diagonal of a rectanhle=square root of l^2 b^2,so 9×square root of 5 is square root of 81 × 5 that is 405 so here 2x is l and x is b.if i m taking l is 18 and b is 9 and squaring them we get 405 so perimeter of the rectangle is 2(18 9) that is 54.

Ans 3:

S SAHITHYAA RAMAN from Padma Seshadri T Nagar, Chennai
Class : Class 7
please provide explanation soon

Ans 4:

Rishith Sunil from BVM global, CHENNAI
Class : Class 6

Ans 5:

Karthikeyan from Velammal bodhi campus, Thanjavur
Class : Class 7
Sorry diagonal of a rectangle is l^2 b^2

Ans 6:

S SAHITHYAA RAMAN from Padma Seshadri T Nagar, Chennai
Class : Class 7
w=xl=2xd=9root52(l b)=?2(x 2x)=?using pythogras theorem,xsquare 4 x square=(9root5)squared5xsquare=405x square=81x=9hence substitute values with x,perimeter=54

Ans 7:

Roy N from DSB Rishikesh, Dehradun
Class : Class 8
pl give solution, very confusing question

Ans 8:

Mehul Bansal from Pawar Public School, mumbai
Class : Class 7
it is very simple and can be solved with Pythagoras.Length=2y Breadth=yroot of [(2y)square ysquare]=9 x root of 5root of [4ysquare ysquare]=9 x root of 5root of 5ysquare=9 x root of 5 = y x root of 5thus y = 9 and 2y = 18p=54

Ans 9:

Ashwin Shridhar from Vidyashilp Academy, Bangalore
Class : Class 9
give explanation please.

Ans 10:

Mehak Narang from Bluebells School International, New Delhi
Class : Class 9
explaination of answer not provide....how to check the solution??

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Trijal Kaushik from DPS Numaligarh, Golaghat
Subject :IMO    Class : Class 5

Ans 1:

Arunava hury from KV1 saltlake , Kolkata
Class : Class 6
C)

Ans 2:

Arunava hury from KV1 saltlake , Kolkata
Class : Class 6
C)

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Bhoomika from Cornerstone, Hyderabad
Subject :IMO    Class : Class 6

Ans 1:

shubh kailash chandak from poddar, washim
Class : Class 6
Answer is a

Ans 2:

Shreyasi Padihary from The Cambridge International School , Bangalore
Class : Class 7

Ans 3:

Chhavi from ,
Class : Class 6

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Bhoomika from Cornerstone, Hyderabad
Subject :IMO    Class : Class 6

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Daksh from Greenwood High, Bengaluru
Subject :IMO    Class : Class 4

Ans 1:

Ayush Ku Pal from Delhi Public School, Nalconagar Angul
Class : Class 8
c

Ans 2:

Advait Khanolkar from Vibhgyor, Mumbai
Class : Class 4

Ans 3:

Pranav Preetham from APL Global School, Chennai
Class : Class 8

Ans 4:

Nishka Agarwal from NMAJS Mumbai, Mumbai
Class : Class 4
D

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Mehaan Bhatt from Pawar Public School , Mumbai
Subject :IMO    Class : Class 6

Ans 1:

Aaditva from Vasant Valley School, New Delhi
Class : Class 8
I don't think the answer is correct

Ans 2:

Mehaan Bhatt from Pawar Public School , Mumbai
Class : Class 6

Ans 3:

Ashwak from Cambridge, Jalandhar
Class : Class 9

Ans 4:

ARUNAV from DPS VINDHYANAGAR, VINDHYANAGAR
Class : Class 10
the answer should be equilateralbecause we have studied everywhere that two equilateral triangle(with same length) are kept such as there one side of both the triangle are adjacent , is a square

Ans 5:

Aayansh baldota from Gk gurukul, Pune
Class : Class 5
is this answer correct ?what is the answer.....correct or no

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Vijay s from Sophia high school, Bengaluru
Subject :IMO    Class : Class 3

Ans 1:

Kristina Salmon from S M Shetty International School and Junior Collage, Mumbai
Class : Class 7

Ans 2:

Teja athreya c v from Sai Angeles , Chikkamagaluru
Class : Class 4
436 B

Ans 3:

Aarav Hitesh Parikh from Gopal Sharma International School, Mumbai
Class : Class 8
aarav parikh take every box from right and solve the answer436 B

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VAIBHAV CHAUDHARY from DPS gwalior, gwalior
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

Ans 2:

Pritha Vikrant Palyekar from Dhruv International School Sus , Pune
Class : Class 5

Ans 3:

Pratham Dave from GNS, Bangalore
Class : Class 7
B is the answer to this question

Ans 4:

Yushika from Navrachana sama, Vadodara
Class : Class 3
cool

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Aryan Priyadarshi from Chinmaya Vidyalaya EM, Rourkela
Subject :IMO    Class : Class 4

Ans 1:

Shaurya Shrivastava from Amanora school, Pune
Class : Class 6
but if we look carefully the circle has a horizontal line that is not in the centre

Ans 2:

REYANSH MALHOTRA from TAGORE INTERNATIONAL SCHOOL, DELHI
Class : Class 4
the horizontal line on the circle is not in the centre

Ans 3:

Sreejith from St.Mary High school, Gajwel Telanagna
Class : Class 6
Sreejith kingswood from UK: There are 3 figures have ahttps://www.sofolympiadtrainer.com/user/endTest/resultReport

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Shashank Jain from VCA, Dewas
Subject :IMO    Class : Class 10

Ans 1:

Srishti Rao from Global Indian International School , singapore
Class : Class 10

Ans 2:

Nikharv from Zebar, Ahmedabad
Class : Class 10
Only Π is irrational because 22/7 is a fraction in p/q form.

Ans 3:

Nikharv from Zebar, Ahmedabad
Class : Class 10
Only Π is irrational because 22/7 is a fraction in p/q form.

Ans 4:

Sachin from Shri Krishna , Mahendergarh
Class : Class 10
Yes the correct answer is π because 22/7 is of the form p/q and if we use π the its value will be 3.14 appox it doesn't have proper value by this we can say that 22/7 is rational number and π is an irrational number

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