International Maths Olympiad Forum By SOF Olympiad Trainer - Page 654

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 9
C is the ans

Ans 2:

Class : Class 7
Wrong

Ans 3:

Class : Class 7
No idea

Ans 4:

Class : Class 7
no idea

Ans 5:

Class : Class 7
No idea

Ans 6:

Class : Class 6
C is the Answer

Ans 7:

Class : Class 6
C IS THE ANSWER

Ans 8:

Class : Class 7
No idea

Ans 9:

Class : Class 7
either a or d

Ans 10:

Class : Class 7
C is the answer...

Ans 11:

Class : Class 6
no idea bruh

Ans 12:

Class : Class 6
The first and third letters are interchanged, and their immediate next letter is taken. The 2nd, 4th and 6th letter are directly written without any change. Same happens to 5th and 7th letters. This is the pattern here.

Ans 13:

Class : Class 6

Ans 14:

Class : Class 6
Question is irrelevant?

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 8
very easy bro! the answer is a (all sports)

Ans 2:

Class : Class 4
all sports

Ans 3:

Class : Class 5
Check the numbers then find the 4 in the ten thousand place

Ans 4:

Class : Class 9
All sports

Ans 5:

Class : Class 6
A

Ans 6:

Class : Class 4
the answer is a

Ans 7:

Class : Class 2
ya answer is A

Ans 8:

Class : Class 4
its C

Ans 9:

Class : Class 9
all sports

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Subject :IMO    Class : Class 5

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Subject :IMO    Class : Class 2

Ans 1:

Class : Class 7

Ans 2:

Class : Class 7
The correct answer is A

Ans 3: (Master Answer)

Class : Class 1

The correct answer is A.

Fourth from the left end is  .

Third to the right of  is .


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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 5
C

Ans 2:

Class : Class 5
wasnt it written clock wise in the question

Ans 3:

Class : Class 6
c

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Subject :IMO    Class : Class 8

Ans 1:

Class : Class 8
@abin jose i agree

Ans 2:

Class : Class 3
Raunak Pandey yr answer is wrong , diagonals of a rectangle are not perpendicular

Ans 3:

Class : Class 3
First option is wrong because a parallelogram is not always necessary to be a square or a rectangle ,as they only have diagonals equal. Second option is wrong because rectangle does not follow this property which can be checked by using SAS congruence criteria. Third option is wrong because if the diagonals of a quadrilateral intersect at right angles then it is necessarily a rhombus, if u are thinking that square also have this property then add up a point that every square is a rhombus. Fourth option is wrong because every quadrilateral is not necessarily be a trapezium, a parallelogram or a kite as concave quadrilaterals are none of them.

Ans 4:

Class : Class 10

Ans 5:

Class : Class 9
2nd option

Ans 6:

Class : Class 3
I feel all options are wrong

Ans 7:

Class : Class 8
c

Ans 8:

Class : Class 10
third option is correct since in a kite, diagonals intersect at right angles and kite is not a rhombus. it does not talk about bisecting.

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Subject :IMO    Class : Class 3

Ans 1:

Class : Class 4

Ans 2:

Class : Class 10
Please mind the arrows. Find ways only that follows the arrows. So Ans will be 5

Ans 3:

Class : Class 3
There are 6

Ans 4:

Class : Class 3
There are 6

Ans 5:

Class : Class 3
6

Ans 6:

Class : Class 8
THERE COULD BE MORE THAN 10

Ans 7:

Class : Class 4
I know the answer is C but explain the solution

Ans 8:

Class : Class 5
If I follow the arrows I get 5

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Subject :IMO    Class : Class 6
ggg

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 5
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Ans 2:

Class : Class 5
The master answer didn't solve my problem. Plss can somebody tell me the explanation and the answer?

Ans 3: (Master Answer)

Class : Class 1
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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 8

Ans 2:

Class : Class 7
What that is not the answer , answer is D

Ans 3:

Class : Class 7
bro the answer is legit c

Ans 4:

Class : Class 8
The answer is C

Ans 5:

Class : Class 9
the answer is B

Ans 6:

Class : Class 8
answer is c

Ans 7:

Class : Class 8
Answer is C!!!

Ans 8:

Class : Class 7
What that is not the answer , answer is D

Ans 9:

Class : Class 7
c is the answer because 1 mother 3 unmarried daughters 2 sons have 4 daughters in total and two sons have two daughters in total and we also have to count the wives of the four sons. so altogether the female members are 14

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