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from ,
Subject :IMO    Class : Class 2

Ans 1:

Aashir Bhattacharya from Hiranandani Foundation School, Mumbai
Class : Class 7
there is curve at the top of rectangle shape of lantern hence thats not a rectangle. so total is 4

Ans 2:

ADYASHA SOURAV PANI from St.Helena's Pune, PUNE
Class : Class 2
Answer should be 6

Ans 3:

Nikhita from Baldwin girls High school, bangalore
Class : Class 2

Ans 4:

Nikhita from Baldwin girls High school, bangalore
Class : Class 2
6 is the answer

Ans 5:

Wrik Chatterjee from DELHI PUBLIC SCHOOL NOIDA, Noida
Class : Class 5

Ans 6:

Abhinha Ajay Ovhal from Podar International School, Latur
Class : Class 8

Ans 7:

Wrik Chatterjee from DELHI PUBLIC SCHOOL NOIDA, Noida
Class : Class 5
4

Ans 8:

Ayush Aravindan from Unicent School Miyapur, Hyderabad
Class : Class 6
Ok ok

Ans 9:

Abhinha Ajay Ovhal from Podar International School, Latur
Class : Class 8

Ans 10:

Divyam from Delhi Public School, Noida, Noida
Class : Class 5

Ans 11:

ayush kumar from dps noida, delhi
Class : Class 8
6

Ans 12:

Iksha from Vibgyorhigh, Pune
Class : Class 1
The answer should be 6 D.1. the door 2. the big rectangle in the middle 3. one corner of the big rectangle4. second corner of the big rectangle5. one lantern lit 6. another lantern lit

Ans 13:

Vyan Badoni from jns , Mumbai
Class : Class 2
6

Ans 14:

Wrik Chatterjee from DELHI PUBLIC SCHOOL NOIDA, Noida
Class : Class 5

Ans 15:

Abhinha Ajay Ovhal from Podar International School, Latur
Class : Class 8
6

Ans 16:

Divyam from Delhi Public School, Noida, Noida
Class : Class 5

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Garv Agarwal from Somerville School Noida, Noida
Subject :IMO    Class : Class 6

Ans 1:

Sahil Tejam from NPS Indiranagar, Bengaluru
Class : Class 6

Ans 2:

Kavitharini Joseph from HUS, Chennai
Class : Class 6
how?

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Garv Agarwal from Somerville School Noida, Noida
Subject :IMO    Class : Class 6

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from ,
Subject :IMO    Class : Class 6

Ans 1:

Dheer Pandey from Sentia The Global School, Hyderabad
Class : Class 10
its d 1\15

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Manvi Mundepi from Montfort School Roorkee, Roorkee
Subject :IMO    Class : Class 6

Ans 1:

Nivedhini from Vivekanada Vidyalaya Chitlapakkam, Chennai
Class : Class 9
INDIA invented zero and its inventor is Bramagupta or Aryabhatta

Ans 2:

Gauri Singh from St Johns School Marhauli, Varanasi
Class : Class 8
India invented 0 and its inventor is Aryabhatta.

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Manvi Mundepi from Montfort School Roorkee, Roorkee
Subject :IMO    Class : Class 6

Ans 1:

Shreyansh Gupta from MVN, faridabad
Class : Class 7
okk

Ans 2:

Aryan Mohapatra from DAV PUBLIC SCHOOL,UNIT-8, Bhubaneswar
Class : Class 8
The answer is A

Ans 3:

Aryan Mohapatra from DAV PUBLIC SCHOOL,UNIT-8, Bhubaneswar
Class : Class 8

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Rs from DPS, Delhi
Subject :IMO    Class : Class 4

Ans 1:

Saipriya from Sankara, Chennai
Class : Class 9
ans is be b ma because holidays till 13th but he will join on 14th only

Ans 2:

Vedang Bhardwaj from Lotus Valley, Gurgaon
Class : Class 4
no b

Ans 3:

IAMLOST from ABC, Pune
Class : Class 8
ans will be b because holidays till 13th but he will join on 14th

Ans 4:

Kaustubh M Sawale from Campion school, Bhopal
Class : Class 6
B is the right answer as the date he will join is 14th Oct

Ans 5:

Manasvi pandey from Dps haldwani, Haldwani
Class : Class 3
B is the correct

Ans 6:

Vedang Bhardwaj from Lotus Valley, Gurgaon
Class : Class 4
I did A but then I understood that holidays end at 13 but he will join on 14

Ans 7:

Rachel from Mount litera Zee School Goa, Goa
Class : Class 7
b is the correct answer

Ans 8:

Vania Aravindan from Unicent School , Miyapur Hyderabad
Class : Class 8
A is the right one

Ans 9:

from ,
Class :
A is the correct answer.

Ans 10:

Vedang Bhardwaj from Lotus Valley, Gurgaon
Class : Class 4

Ans 11:

Vedang Bhardwaj from Lotus Valley, Gurgaon
Class : Class 4
Class:

Ans 12:

DAIWIK SAHA from DUDES N DOLLS, FARIDABAD
Class : Class 8
a is the correct answer

Ans 13:

Aviya Daniel from HIM ACADEMY PUBLIC SCHOOL, Hamirpur
Class : Class 4

Ans 14:

Sameer Anand from ST MICHAEL'S HIGH SCHOOL, PATNA
Class : Class 8
A is the right answer

Ans 15:

Kaustubh M Sawale from Campion school, Bhopal
Class : Class 6
A is the right answer

Ans 16:

Aaryaman Pradhan from De paul School , Berhampur
Class : Class 5
a is the correct answer

Ans 17:

Manasvi pandey from Dps haldwani, Haldwani
Class : Class 3
B is correct

Ans 18:

Vania Aravindan from Unicent School , Miyapur Hyderabad
Class : Class 8

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from ,
Subject :IMO    Class : Class 2

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Champ from Reliance Foundation School, Mumbai
Subject :IMO    Class : Class 7

Ans 1:

from ,
Class :

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Champ from Reliance Foundation School, Mumbai
Subject :IMO    Class : Class 7

Ans 1:

from ,
Class :
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

Ans 2:

from ,
Class :
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

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