International Maths Olympiad Forum By SOF Olympiad Trainer

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Subject :IMO    Class : Class 6

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Subject :IMO    Class : Class 8

## Ans 1:

Class : Class 8
Let the measure of the breadth =10 Let the measure of the length = 10 original area=10 x 10 =100 new length=9.5 new breadth=10.5 new area = (100-5)(100+5)/100 new area=99.75 percent change=100-99.75 =(0,25/100) x 100=0.25% decrease

Subject :IMO    Class : Class 4

## Ans 1:

Class : Class 1

Subject :IMO    Class : Class 6

## Ans 1:

Class : Class 6
As the answer will be like this(-3/5 -(-2 3/5)) * 5 1/5= 2*5 1/5/ = 10 2/5

## Ans 2:

Class : Class 6
Yes the answer is 10.4 or10 2/5

## Ans 3:

Class : Class 5
what is the correct answer?

## Ans 4:

Class : Class 6
how did you get this answer

## Ans 5:

Class : Class 6
answer should be 10 2/5

## Ans 6:

Class : Class 7
yes, the ans is 10 2/5 only....

Class : Class 6

## Ans 8:

Class : Class 7
yes what is the solution to this question?

Subject :IMO    Class : Class 5

## Ans 1:

Class : Class 6
b

Subject :IMO    Class : Class 6

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Subject :IMO    Class : Class 7

## Ans 1:

Class : Class 7
d

Subject :IMO    Class : Class 7

Class : Class 7

## Ans 2:

Class : Class 8
option a is correct. if you modify the diagram then yes d is correct.

Subject :IMO    Class : Class 7

## Ans 1:

Class : Class 8
area of rectangle = l*b = 15*21 = 315 sq m area of semi - circle = 1/2 * 22/7*r^2 =1/2* 22/7* 10.5^2=173.25 sq m area of shaded region = area of rectangle - area of circle = 315 - 173.25 = 141.75 sq m

Subject :IMO    Class : Class 3

Class : Class 3

Class : Class 3
ans is 24