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Tavish172 from SXSBTI, Bathinda
Subject :IMO    Class : Class 3

Ans 1:

Sun from PSBB , Chennai
Class : Class 5
Full question please

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tanmay srivastava from DPS Noida, Noida
Subject :IMO    Class : Class 4

Ans 1:

Ankit Kumar Mistry from Kalyani Public School, Kolkata
Class : Class 4
The answer is B because CM=C-M=C(100)-M(1000)We cannot subtract 100-1000 So the formula should be 1000-100 l Therefore, TH H T O 1 0 0 0 - 1 0 0 ----------------------- 9 0 0 So, B is the right answer.

Ans 2:

Supreeth from Vssips Bangalore, Bangalore
Class : Class 4
A

Ans 3:

Supreeth from Vssips Bangalore, Bangalore
Class : Class 4
A

Ans 4:

MANDAR PALKAR from KV DRDO, Bengaluru
Class : Class 2
CM=1000-100

Ans 5: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correcr answer is B

CM = 1000 – 100.


Ans 6:

Swarit from Indian School Wadi kabir, Muscat
Class : Class 5
The correcr answer is B CM = 1000 – 100.

Ans 7:

Vanishi Jain from DELHI PUBLIC SCHOOL, Noida
Class : Class 4
If there is C before M that means that we are subtracting 100 from 1000 . We write it as 1000 - 100. Answer : B

Ans 8:

KALLOL PAL from TIGPS Mankundu , CHANDANNAGAR
Class : Class 5
c=100,M=1000 so cm =100-1000 (answer. c)

Ans 9:

Prerna Singh from Loyola School, Jamshedpur
Class : Class 5
The correct answer would be option C because CM = 900. C=100, M=1000. So, the smaller no. is in the beginning, it will be minus. So, 1000-100 is the correct ans.

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Arjun from chirec heydrabad, heydrabad
Subject :IMO    Class : Class 2

Ans 1:

Shrihan Modi from Delhi Public School Noida , Noida
Class : Class 2
C

Ans 2:

Anshul Sameer Darne from Ryan International School, Masdar
Class : Class 3
C40 is the answer.

Ans 3: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is C

363 - 323 = 40


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Atharva Panjabi from BAL BHARATI PUBLIC SCHOOL DWARKA, New Delhi
Subject :IMO    Class : Class 5

Ans 1:

Atharva Panjabi from BAL BHARATI PUBLIC SCHOOL DWARKA, New Delhi
Class : Class 5
please show the correct explaination.

Ans 2:

Aarya Teja from Bharatiya Vidya Bhavans Public School, Hyderabad
Class : Class 5
(D) 1 1st number=(8*5)-(4*3) =40-12 =28 2nd number (12*7)-(9*8) =84-72 =12 Therefore, 3rd number=(5*5)-(6*1) =25-6 =19

Ans 3:

Viggya Sutradhar from New look Senior Secondary school, Banswara
Class : Class 5
8*5-3*4=28 12*7-9*8=12 5*5-1*6=19 So correct and is 1 D option

Ans 4:

Atharva Panjabi from BAL BHARATI PUBLIC SCHOOL DWARKA, New Delhi
Class : Class 5

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Shiven Dinkar from DPS NOIDA Sector 30, Delhi
Subject :IMO    Class : Class 3

Ans 1:

Urvee Sarang Gokhale from Sri Sri Ravi Shankar Vidya Mandir, Pune
Class : Class 3
B is the correct answer.

Ans 2:

Aditya Raj from Kairali School, Ranchi
Class : Class 6
B

Ans 3:

Girish Garg from Delhi public school, Bathinda
Class : Class 3
B

Ans 4:

Girish Garg from Delhi public school, Bathinda
Class : Class 3
B

Ans 5:

Adya gupta from DPS, RKP
Class : Class 2
B

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AADRIKA KUMAR from MOUNT LITERA ZEE SCHOOL, Kanpur
Subject :IMO    Class : Class 2

Ans 1:

Admin from revisewise, Noida
Class : Class 1

The correct answer is D.

  

So, Number of cards Neha has = 300 
Number of cards Rajni has = 250 
Number of cards Latika has = 400 
Number of cards Varsha has = 200


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Ram Deshmukh from Potdar international school, Aurangabad
Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

Kindly repost the correct question


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Swapnil Ganguly from Salt Lake School , Kolkata
Subject :IMO    Class : Class 9

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is A.

Given a right angled ΔABC,
where AB = AC and CD is the bisector of ∠C. 
 


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Kushagra Gupta from Manav Rachna, Faridabad
Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is D.


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Seshasayee sudharsan from Rajagiri Public School, Doha
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

In mathematics, 'e' is a constant that is the base of the natural logarithm. It is the unique number whose natural logarithm is equal to one and its value is approximately 2.71828.


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