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Subject :IMO    Class : Class 4

Ans 1: (Master Answer)

Class : Class 1

(C):

First count the number of sides of the small squares in the outline of the given figure.
There are 28 sides. Each side is 2 cm.
Therefore, Perimeter of the given figure = 28 x 2 = 56 cm
So, the correct answer is Option C.


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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 6
C is the correct answer

Ans 2:

Class : Class 7
C is the answer to this question

Ans 3:

Class : Class 5
c is the correct answer

Ans 4:

Class : Class 6

Ans 5:

Class : Class 6
c

Ans 6:

Class : Class 5
c

Ans 7:

Class : Class 5
Cccccccc

Ans 8:

Class : Class 5
c is the correct answer

Ans 9: (Master Answer)

Class : Class 1

The correct answer is option C. 


Ans 10:

Class : Class 6
C is the correct answer.

Ans 11:

Class : Class 6
C

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Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Class : Class 1

(D):

A. 4th multiple of 52 = 208
B. 8th multiple of 37 = 296
C. 5th multiple of 25 = 125
D. 7th multiple of 50 = 350
So, 350 is the greatest value amongst all.


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Subject :IMO    Class : Class 3

Ans 1:

Class : Class 4
Seee

Ans 2:

Class : Class 4
This question is wrong as 7x9 is 63 and that is also bigger than 37.

Ans 3: (Master Answer)

Class : Class 1

(D): To tip the scale below to the right, the weight of chocolates should be greater than 37kg.
Weight of 5 chocolates = 5 x 7 = 35kg
Weight of 6 chocolates = 6 x 7 = 42kg
 As, 42kg > 37kg
So, minimum number of chocolates needed = 6


Ans 4:

Class : Class 3
(D):To tip the scale below to the right,the weight ofchocolates should be greater than 37kg.Weight of 5 chocolates =5 x 7=35kgWeight of 6 chocolates=6x7=42kgSo,minimum number of chocolates needed = 6

Ans 5:

Class : Class 4

Ans 6:

Class : Class 3
its 7

Ans 7:

Class : Class 4

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 6
not very difficult

Ans 2:

Class : Class 5

Ans 3:

Class : Class 5

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 8

Ans 2:

Class : Class 7

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Subject :IMO    Class : Class 9

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Subject :IMO    Class : Class 7

A number consists of two digits whose sum is 9. If 27 is added to the number, its digits are interchanged. Which of the given steps is CORRECT to find the number?
Step 1 :Let the unit’s digit be x
Step 2 :Then, ten’s digit = (9 – x)
∴ Number = 10 × (9 – x) + x
⇒ 90 – 10x + x = (90 – 9x)
Step 3 :Adding 27 to the number 90 – 9x, we get 117 – 9x
Step 4 :Number with digits interchanged is 10x + (9 – x) = 9x + 9
Step 5 :117 – 9x = 9x + 9
Step 6 :Therefore unit’s digit = 6 and ten’s digit = 3
Step 7 :Hence the number = 36.

A Only Step 4
B Both Step 1 and Step 2
C Step 1, 2, 3 and 4
D All steps are correct


how to find the solution

Ans 1:

Class : Class 7
Nitin , I think you forgot that the sum of the digits of a number should be 9 , As in teh question. All teh other nummbers given by you except 36 is wrong because their digits do nto sum up to 9

Ans 2:

Class : Class 7

Ans 3:

Class : Class 6

Ans 4:

Class : Class 6
*x 3=y

Ans 5:

Class : Class 6
The space means addition

Ans 6:

Class : Class 6
The number is not only 36 (It is a number , but there are other numbers) . If you keep x as the ten's digit of the original number and y as the unit's digit of the number , any number following : x 3=y , will follow this rule .The numbers following this rule is 14 27=41 , 25 27=52 , 36 27=63 , 47 27=74 , 58 27=85 , 69 27=96 .

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Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Class : Class 1

(B):

(a) Total number of books in both  the libraries = 284683 + 371805
= 656488

(b) Number of more books in second library than the  first library = 371805 - 284683
= 87122


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Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Class : Class 1

(C): Quantity of syrup Mrs. Preeti had = 5 litres = 5000 ml

Quantity of Syrup she poured in each bottle = 300 ml

Number of bottles needed = 5000 ÷ 300 = 16.67
Therefore, 17 bottles are needed. 


Ans 2:

Class : Class 5

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