# User Forum Subject :IMO    Class : Class 5

## Ans 1:

Class : Class 7
there are so many wrong questions like this in sof. i request all to contact all to sof

Subject :IMO    Class : Class 3

## Ans 1:

Class : Class 10

There was a mistake in the options. It has been corrected now.
Solution
1535+279 = 1814
1984-164 = 1820
Even number between 1814 and 1820 are 1816 and 1818
Sum of 1816 + 1818 = 3634

## Ans 2:

Class : Class 10

There was a mistake in the options. It has been corrected now.
Solution
1535+279 = 1814
1984-164 = 1820
Even number between 1814 and 1820 are 1816 and 1818
Sum of 1816 + 1818 = 3634

Subject :IMO    Class : Class 3

Class : Class 5

Class : Class 6

Class : Class 5

## Ans 4:

Class : Class 3
Yes I agree with Sanjivani Saha that Kushan is correct The answer given by SOF is wrong

## Ans 5:

Class : Class 3
only A is correct as term respectively is used

Class : Class 5

## Ans 7:

Class : Class 4
It is very horrified that answer given is wrong..............should be B.

## Ans 8:

Class : Class 2
Answer is B only as it is written respectively and accordingly and - signs are shown.

Class : Class 5
(B)

Class : Class 5

Class : Class 3

Class : Class 4

Class : Class 6

## Ans 14:

Class : Class 3
Answer is A because it is written respectively

## Ans 15:

Class : Class 3
it was a trick question and answer should be D only

## Ans 16:

Class : Class 3
answer is wrong because given term respectively is givenabhishree singh lucknow india

## Ans 17:

Class : Class 1
The answer is "B".sofor is wrong

Subject :IMO    Class : Class 5

Class : Class 1
There are 25 hexagons in the figure. For 2/5 to be left unshaded, 3/5 of them must be shaded. Now, total no. of hexagons which must be shaded are:- (3/5)x25=15

Subject :IMO    Class : Class 3

## Ans 1:

Class : Class 6
Correct Answer is D. Q is 4, hence, 6 less than 10.

## Ans 2:

Class : Class 5
The answer is D. Value of Q is 4 and 4 is 6 less than 10.

## Ans 3:

Class : Class 4
4 shouldâ ve been the answer given by them

Class : Class 4

## Ans 5:

Class : Class 4

Subject :IMO    Class : Class 3

## Ans 1:

Class : Class 3
The logic is simple here.. Rohan delivers newspapers on weekdays (i.e) Monday to Friday. The only condition that would address the number of papers delivered on Sunday is if he deliver's 14 more papers on Sunday than on weekdays. So the answer is 1.

## Ans 2:

Class : Class 4
good

Subject :IMO    Class : Class 4

Class : Class 4
3/10

## Ans 2:

Class : Class 8
2/8 (=10/40) in the morning left only 6/8 3/5 of 6/8 = 18/40 leftover milk is = 1-(10/40) - (18/40) = 12/40 = 3/10

Class : Class 5

## Ans 4:

Class : Class 5
blah blah blahwhatever

Class : Class 5
3/20

Class : Class 5

## Ans 7:

Class : Class 4
Answer is option B or 3/10

## Ans 8:

Class : Class 10
Milk left for the evening = 1 - 2/8 = 6/8
Milk consumed in the evening = 3/5 of 6/8 = 3/5 x 6/8 = 18/40
Total milk consumed = 2/8 + 18/40 = 28/40
Milk left = 1 -28/40 = 12/40 = 3/10

## Ans 9:

Class : Class 6
It is 3/20 because- if you add 2/8 and 3/5 =17/20 which he drank =20/20-17/20=3/20

Class : Class 2

Class : Class 4
3/20 is correct

## Ans 12:

Class : Class 6
3/20Thank you Priti Srivastav

## Ans 13:

Class : Class 8
3/10

Subject :IMO    Class : Class 7

## Ans 1:

Class : Class 7
a

Subject :IMO    Class : Class 8

## Ans 1:

Class : Class 8
D part

Subject :IMO    Class : Class 8