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Ojas Golyan from Indian school Sohar, Sohar
Subject :IMO    Class : Class 8

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is C.

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Ojas Golyan from Indian school Sohar, Sohar
Subject :IMO    Class : Class 8

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is D.

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Suraj Ramanan Gopal from BVM Global, bangalore
Subject :IMO    Class : Class 5

Ans 1:

OISHIK KUNDU from Delhi Public school North kolkata, baranagar
Class : Class 4
Let’s name the three set of numbers as Set P, Q and R. Now, first observe the numbers in Set P. If we multiply the top two numbers and then subtract the sum of them, we get the bottom number. (12 x 8) - (12 8) = 96 – 20 = 76. 76 is the bottom number. Let’s see if numbers in Set Q will also follow the same rule. (13 x 9) – (13 9) = 117 – 22 = 95. 95 is the bottom number. So, the rule is correct. That means the numbers in Set R will also follow the same rule. (7 x 6) – (7 6) = 42 – 13 = 29. 29 is the missing bottom number. Hence, the right answer is Option B.

Ans 2:

OISHIK KUNDU from Delhi Public school North kolkata, baranagar
Class : Class 4
The answer is b as when we add 12 and 8 it is 20. Then, we multiply 12 by 8 it becomes 96. So 96- 76 is 20. Then let's add 13 and 9=22. Then multiply 13 by 9 the answer is 117. Subtract 117 by 95 =22. Then add 7 and 6 it makes 13. Then multiply 7 by 6 the answer is 42. Then 42 - 13 is 29. So the answer is 29.

Ans 3:

Nidhi from Vikas the concept, Hyderabad
Class : Class 6
A and C are also correct

Ans 4:

Debarpan Das from Delhi Public School , Durgapur
Class : Class 6

Ans 5:

Time to Learn from Hirananandani Foundation School, Thane,Mumbai
Class : Class 5
The answer is b as when we add 12 and 8 it is 20. Then, we multiply 12 by 8 it becomes 96. So 96- 76 is 20. Then let's add 13 and 9=22. Then multiply 13 by 9 the answer is 117. Subtract 117 by 95 =22. Then add 7 and 6 it makes 13. Then multiply 7 by 6 the answer is 42. Then 42 - 13 is 29. So the answer is 29.

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rbaiswar25@gmail.com from Somerville International School, Noida
Subject :IMO    Class : Class 2

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Prabhakar H.S. from ,
Subject :IMO    Class : Class 5

Ans 1:

Prabhakar H.S. from ,
Class : Class 1

Ans 2:

Prabhakar H.S. from ,
Class : Class 1
IT IS SO HARD TO DO

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monica jindal from British Co Ed high school, Patiala
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The rea of the square is 196 sq units. Hence, the side of the square will be the square root of 196 i.e 14 units Now, from the figure, we can see that each square cell is of 7 units Hence, the side EH is of 21 units and the side EF is of 28 units. Now, the perimeter will be 2(L+B) = 49 cm.

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monica jindal from British Co Ed high school, Patiala
Subject :IMO    Class : Class 5

Ans 1:

Devesh Kumar Shrivastava from St Mary's School, New Delhi
Class : Class 6

Ans 2:

Devika PARAMBIKATTIL from Rustomjee Cambridge International School , Thane
Class : Class 6
As option bcd have triangular edges at the end, and option a do not have triangular edges option a is the answer

Ans 3:

nidhi from S M shetty HIgh school, MUMBAI
Class : Class 6

Ans 4:

Nishant Doshi from new era senior secondary school nizampura vadodara, Vadodara
Class : Class 7

Ans 5:

SJ HARITHA from PSBS, Bengaluru
Class : Class 6
HOW IS IT B DURAV

Ans 6:

Tamrashi Pani from Sof Olympiad trainer international school, Bangalore
Class : Class 7
A is the correct answer ... I agree with devika

Ans 7:

Debarpan Das from Delhi Public School , Durgapur
Class : Class 6

Ans 8:

Shreyas Singh from Podar International School, Pune
Class : Class 6

Ans 9:

Dhruv from salwan junior school, New Delhi
Class : Class 5
b

Ans 10:

Prapti Kumar from GD Birla Center For Education, Kolkata
Class : Class 6

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Bharsha from OXEBOW ENGLISH SCHOOL, Gobordanga
Subject :IMO    Class : Class 1

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Bharsha from OXEBOW ENGLISH SCHOOL, Gobordanga
Class : Class 3
how can i understand 1 is more than 56 by abacus fromula

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Rahul from , NOIDA
Subject :IMO    Class : Class 4

Ans 1:

Dhairya Godbole from KLE Eng Medium School, SOLAPUR
Class : Class 6
what is the shortest method to solve this question

Ans 2:

Mohnish S from CMR National Public School, Bengaluru
Class : Class 4
Can you please help with solving this question

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Rahul from , NOIDA
Subject :IMO    Class : Class 4

Ans 1:

BISWADITYA TRIPATHY from Delhi public school Bangalore east, Bangalore
Class : Class 4
i think instead of length , perimeter should have been mentioned

Ans 2:

ASMI KUMAT from SHISHUKUNJ INTERNATIONAL SCHOOL, INDORE
Class : Class 6

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