Ans 5:
Class : Class 7
Option C is correct ,as , area of big semi circle = 14 * 14 * 22/(7*2) = 14 * 22 = 308 then we will subtract the area of unshaded 2 semi circle(which is a whole circle ), = 7 * 7 * 22/7 = 7*22 = 154 ,Hence , area of shaded portion is , = area of big semi circle - are of two small semi circle = 308 - 154 = 154 sq. cm
Ans 8:
Class : Class 8
Answer is (C)Diameter of bigger circle=28 cmradius=28/2=14 cmArea of semicircle=1/2*22/7*14*14=4312/14=308 sq.cm2 semicircle=circleArea=22/7*7*7=1078/7=154 sq.cmArea left=308-154=154 cm
Ans 28:
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Ans 1:
Class : Class 7
let the price of object B be x
the the price of object A is (6x-100)
now ATP,
1(6x-100) + 4*x=1400
=>6x-100 + 4x=1400
=>10x -100=1400
=>10x=1500
=>x=1500/10
=>x=150
now the price of object A=150*6-100
=800(d)
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Ans 2:
Class : Class 10
Answer is 3abc cause'.
Centroid in coordinate geometry is equal tO X1+X2+X3/2 , Y1+Y2+Y3/2
THEREFORE 0 EQUAL TO X CORDINATE ANT SO A+B+C EQUAL TO ZERO