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Sarakshi Pani from JHTS, JAMSHEDPUR
Subject :IMO    Class : Class 1

Ans 1:

Harsh Kumar from Maharishi Vidya Mandir, Guwahati
Class : Class 8
Smallest odd number = 1 4 more than the smallest odd number is 5 ∴ First digit is 5 Factors of 2 are 1, 2 Factors of 11 are 1, 11 Common factor of 2 and 11 is 1 ∴ Second digit is 1 Product of first two digits = 1 × 5 = 5 ∴ Third digit is 5 Single digit multiple of 6 is 6 itself. ∴ Fifth digit is 6 Now, sum of fourth digit and fifth digit is 9. ∴ Fourth digit = 9 - 6 = 3 ∴ Required number = 51536

Ans 2:

Sarakshi Pani from JHTS, JAMSHEDPUR
Class : Class 5
hi

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Advay Jain from DPS Noida, Noida
Subject :IMO    Class : Class 5

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Advay Jain from DPS Noida, Noida
Subject :IMO    Class : Class 5

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ranjani from sancta maria, Hyderabad
Subject :IMO    Class : Class 8

Ans 1:

Ansh Goel from DAV public school, Delhi
Class : Class 9
Answer is option c because rational no.s are associative under additional and multiplication only

Ans 2:

Arnab Jana from KTPP High School, KTPP
Class : Class 9
c

Ans 3:

rishu Raj from dav public school dhanupura ara , ara
Class : Class 8
answer c

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samik from Sri Sri Ravishankar Vidya Mndir, Mumbai
Subject :IMO    Class : Class 7

Study the statements carefully.
(1) Every integer is a rational number and every fraction is a rational number.
(2) A rational number is positive, if p and q are either both positive or both negative.
(3) A rational number is negative, if one of p and q is positive and other is negative.
(4) If there are two rational numbers with common denominator, then the one with the larger numerator is larger than the other.Which of the following options hold?

ABoth (1) and (4) are incorrect
BBoth (2) and (3) are incorrect
COnly (1) is incorrect
DAll are correct


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student from school, city
Subject :IMO    Class : Class 6

Ans 1:

Subharsish Kashyap from Carmel school, Jorhat
Class : Class 7
option b is correct because there are 5 obtuse angles : ROS, QOS, POS, ROT, QOT

Ans 2:

Siddhanth Subramanian from Global Indian International School , Singapore
Class : Class 7

Ans 3:

Prabhav Kaushik from DPS Noida, Noida
Class : Class 7

Ans 4:

Ishayu Poddar from NPS Whitefield, Bangalore
Class : Class 6
there are 5

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Pagadala Sri Pranya from Bharatiya Vidya Bhavans Public School Vidyashram, HYDERABAD
Subject :IMO    Class : Class 5

Ans 1:

Pagadala Sri Pranya from Bharatiya Vidya Bhavans Public School Vidyashram, HYDERABAD
Class : Class 5
AL=2,KJ=2,IH=2,GF=2,ED=2.SO,2 2 2 2 2=10.BC=10so10 10=20breadth=7x2=14so20 14=34how can option C be correct

Ans 2:

S Tharuni from Sanskriti, Hyderabad
Class : Class 7
the correct answer is (c)

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Ashmi Narkar from VIBGYOR High, Airoli, Navi Mumbai
Subject :IMO    Class : Class 3

Ans 1:

Ashmi Narkar from VIBGYOR High, Airoli, Navi Mumbai
Class : Class 6
SolutionExcept (B) all the three are spherical balls.

Ans 2:

Ashmi Narkar from VIBGYOR High, Airoli, Navi Mumbai
Class : Class 6

Ans 3:

Abhijay Saha from Delhi Public School, Megacity, Kolkata
Class : Class 3

Ans 4:

Tavish Singh from Sanskriti School, Hyderabad
Class : Class 3
ball

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Ashmi Narkar from VIBGYOR High, Airoli, Navi Mumbai
Subject :IMO    Class : Class 3

Ans 1:

Nihira Tiwari from Delhi public school electronic city, Bengaluru
Class : Class 4
Focus on numbers

Ans 2:

Shivani Sharma from Holy Angels ISC school , Thiruvananthapuram
Class : Class 3
Lalita is first then how can Piyush stood after Lalita

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Ashmi Narkar from VIBGYOR High, Airoli, Navi Mumbai
Subject :IMO    Class : Class 3

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