Ans 1:
Class : Class 6
(C): After replacing the symbols, the given equation becomes,15 × 3 – 10 ÷ 5 5= 15 × 3 – 2 5 = 45 – 2 5 = 48
Ans 3: (Master Answer)
Class : Class 1
(C): After replacing the symbols, the given equation becomes,
15 × 3 – 10 ÷ 5 + 5
= 15 × 3 – 2 + 5 = 45 – 2 + 5 = 48
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Ans 1: (Master Answer)
Class : Class 1
(A): Total number of books borrowed = 0 x 18 + 1 x 26 + 2 x 84 + 3 x 75 + 4 x 38
= 0 + 26 + 168 + 225 + 152
= 571
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Post Your Answer
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Ans 1: (Master Answer)
Class : Class 1
(C):
Distance travelled by Latika = (145 + 126)
= 271 km
Distance travelled by Garima = ( 68 + 145) x 2
= 213 x 2 = 426 km
Therefore, Garima travelled a longer distance .
Difference = 426 – 271 = 155 km
Ans 2: (Master Answer)
Class : Class 1
(C):
Distance travelled by Latika = (145 + 126)
= 271 km
Distance travelled by Garima = ( 68 + 145) x 2
= 213 x 2 = 426 km
Therefore, Garima travelled a longer distance .
Difference = 426 – 271 = 155 km