International Maths Olympiad Forum By SOF Olympiad Trainer - Page 142

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Subject :IMO    Class : Class 5

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Class : Class 7
D

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Subject :IMO    Class : Class 8

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Class : Class 8
Let us say that the total sum of weight is x x/120 = 56 x = 6720 Now, let us say that the number girls is z We know that the sum of the weight of the girls will be the sum of weight of the boys subtracted from the total sum.Let us say that the sum of weights of boys is y. So now girls total weight sum will be : 6720-y/z = 50 6720-y = 50z 6720 = 50z + y 6720 - 50z = y(Equation 1) Total sum of weight of boys will be y/120 - z = 60 y = 7200 - 60z(Equation 2) Subtracting both equations(1 and 2) : y-y = 7200-60z - 6720z + 50z 0 = 480-10z 10z = 480 z = 48 Number of girls is 48.So, the number of boys will be 120-48 = 72

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Subject :IMO    Class : Class 2

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Class : Class 4

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Class : Class 7

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Subject :IMO    Class : Class 5

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Subject :IMO    Class : Class 8

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Subject :IMO    Class : Class 6

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Subject :IMO    Class : Class 8

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Subject :IMO    Class : Class 5

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Subject :IMO    Class : Class 6

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Subject :IMO    Class : Class 9

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Class : Class 9
Coordinates of the points- P(-6, 0) Q(0, -3) R(6, 0) S(0 ,3) Now, T is 5 units to the right and 2 units above S, so its coordinates are T(0+5, 3+2)= T(5, 5) i) Sum of abscissae (x-axis coordinate) of P and T = -6+5= -1 ii) Sum of the ordinates (y-axis coordinate) of Q, R and T= -3+0+5= 2 Hence, the correct answer is option A) (i) -> -1, (ii) -> 2

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