International Maths Olympiad Forum By SOF Olympiad Trainer - Page 657
  1. Home
  2. /  Forum

User Forum

Ask Your Question
Samarth from DPS, Noida, GAUTAMBUDH NAGAR
Subject :IMO    Class : Class 3

Ans 1:

IAMLOST from ABC, Pune
Class : Class 8
Please explain

Ans 2:

Rajveer from DPS, Bengaluru
Class : Class 3
C

Ans 3:

Arshia Kochhar from Delhi Public School Dwarka , New Delhi, Dwarka
Class : Class 7
red circle= * =5*5 =25, o*o=4*4=16multiply each number in column. Answer will be 6*2=12

Ans 4:

Pavani Chetan Kurawatti from Universal High School, Mumbai
Class : Class 3

Ans 5:

Ashmi Narkar from The Shishukunj International School, Jhalaria Campus, Indore
Class : Class 8
I didn't understand . Someone explain. I want master answer or simple answer of Question 31 by Shiven .

Ans 6:

Arihant Medhi from Maharishi Vidya Mandir, Rangia
Class : Class 6
Don't just shout . See the answer.

Ans 7:

AJAY LAHOTI from SPRINGDALES DUBAI, Dubai
Class : Class 6
How? Can you explain?

Ans 8:

Advika Narkar from The Shishukunj International School, Jhalaria Campus, Indore
Class : Class 7
Oh! Now I know! answer is C as 6 * 2 = 12! (Key - * - Multiplication sign)

Post Your Answer

B Murali Srinivas from ,
Subject :IMO    Class : Class 6

Ans 1:

JIVESH KUMAR from Cochin refineries school , Kochi
Class : Class 6
every natural number is a whole number

Post Your Answer

Thamognya from nps, Singapore
Subject :IMO    Class : Class 5

Ans 1:

Gauri Singh from St. John's School, Marhauli, Varanasi
Class : Class 10
A. 0

Ans 2:

Ayush Kumar from Maria Assupta Sr. Sec. Convent School, KASHIPUR
Class : Class 5
The answer is option B.

Post Your Answer

Shaurya Manjkhola from St Kabir Public School Chandigarh, Chandigarh
Subject :IMO    Class : Class 6

Ans 1:

Aditya Sai Vemparala from Amanora school, Pune
Class : Class 10

Ans 2:

Aditya Sai Vemparala from Amanora school, Pune
Class : Class 10
27

Ans 3:

JIVESH KUMAR from Cochin refineries school , Kochi
Class : Class 6
12 days

Ans 4:

Naumaan ahmed from Oyesters international, Pune
Class : Class 6
12 days

Post Your Answer

Ojas Golyan from Indian school Sohar, Sohar
Subject :IMO    Class : Class 8

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is C.

Post Your Answer

Ojas Golyan from Indian school Sohar, Sohar
Subject :IMO    Class : Class 8

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is D.

Post Your Answer

Suraj Ramanan Gopal from BVM Global, bangalore
Subject :IMO    Class : Class 5

Ans 1:

Time to Learn from Hirananandani Foundation School, Thane,Mumbai
Class : Class 5
The answer is b as when we add 12 and 8 it is 20. Then, we multiply 12 by 8 it becomes 96. So 96- 76 is 20. Then let's add 13 and 9=22. Then multiply 13 by 9 the answer is 117. Subtract 117 by 95 =22. Then add 7 and 6 it makes 13. Then multiply 7 by 6 the answer is 42. Then 42 - 13 is 29. So the answer is 29.

Ans 2:

OISHIK KUNDU from Delhi Public school North kolkata, baranagar
Class : Class 4
The answer is b as when we add 12 and 8 it is 20. Then, we multiply 12 by 8 it becomes 96. So 96- 76 is 20. Then let's add 13 and 9=22. Then multiply 13 by 9 the answer is 117. Subtract 117 by 95 =22. Then add 7 and 6 it makes 13. Then multiply 7 by 6 the answer is 42. Then 42 - 13 is 29. So the answer is 29.

Ans 3:

OISHIK KUNDU from Delhi Public school North kolkata, baranagar
Class : Class 4
Let’s name the three set of numbers as Set P, Q and R. Now, first observe the numbers in Set P. If we multiply the top two numbers and then subtract the sum of them, we get the bottom number. (12 x 8) - (12 8) = 96 – 20 = 76. 76 is the bottom number. Let’s see if numbers in Set Q will also follow the same rule. (13 x 9) – (13 9) = 117 – 22 = 95. 95 is the bottom number. So, the rule is correct. That means the numbers in Set R will also follow the same rule. (7 x 6) – (7 6) = 42 – 13 = 29. 29 is the missing bottom number. Hence, the right answer is Option B.

Ans 4:

Vihaan Tyagi from Vikas the concept, Hyderabad
Class : Class 9
A and C are also correct

Ans 5:

Aditya Sai Kedarisetty from Sri Kumarans childrens Academy DKS, Bangalore
Class : Class 7

Ans 6:

Aryan Yadav from National Public School Sarjapur Road, Karnataka Bangalore
Class : Class 6
Dude Itcant be more than one answer

Ans 7:

Debarpan Das from Delhi Public School , Durgapur
Class : Class 9

Post Your Answer

rbaiswar25@gmail.com from Somerville International School, Noida
Subject :IMO    Class : Class 2

Post Your Answer

Prabhakar H.S. from ,
Subject :IMO    Class : Class 5

Ans 1:

Prabhakar H.S. from ,
Class : Class 1

Ans 2:

Prabhakar H.S. from ,
Class : Class 1
IT IS SO HARD TO DO

Post Your Answer

monica jindal from British Co Ed high school, Patiala
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The rea of the square is 196 sq units. Hence, the side of the square will be the square root of 196 i.e 14 units Now, from the figure, we can see that each square cell is of 7 units Hence, the side EH is of 21 units and the side EF is of 28 units. Now, the perimeter will be 2(L+B) = 49 cm.

Post Your Answer