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JIVESH KUMAR from Cochin refineries school , Kochi
Subject :IMO    Class : Class 6

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Eera from Millenium, Pune
Subject :IMO    Class : Class 6

Ans 1:

pranjal kaur from SVISG, DELHI
Class : Class 6
option c

Ans 2:

JIVESH KUMAR from Cochin refineries school , Kochi
Class : Class 6
Option C

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anay rungta from national public school yeshwanthpur, bengaluru
Subject :IMO    Class : Class 7

Ans 1:

D VISHNU from NARAYANA SCHOOL, CHENNAI
Class : Class 7
(1-1/2)*(1-1/3)*(1-1/4)*(1-1/5)*(1-1/6)*(1-1/7)*(1-1/8)*(1-1/9)*(1-1/10), first solve the brackets, we will get 1/2*2/3*3/4*4/5*5/6*6/7*7/8*8/9*9/10, cancel 2 in 1/2 and 2/3, cancel 3 in 2/3 and 3/4, cancel 4 in 3/4 and 4/5, cancel 5 in 4/5 and 5/6, cancel 6 in 5/6 and 6/7, cancel 7 in 6/7 and 7/8, cancel 8 in 7/8 and 8/9, cancel 9 in 8/9 and 9/10, now we will get 1/1*1/1*1/1*1/1*1/1*1/1*1/1*1/1*1/1*1/10, then multiply1*1*1*1*1*1*1*1*1*1/1*1*1*1*1*1*1*1*1*10, then we will get the answer as 1/10, so option C is correct.

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Aviral Shukla from Apeejay School Sheikh Sarai, New Delhi
Subject :IMO    Class : Class 4

Ans 1:

AREEN from BOLTON SCHOOL, Secunderabad
Class : Class 5
Answer is D as the question says to find the perimeter, which is (7*2) cm+4 cm+(9*2) cm+15 cm+8 cm+5 cm+(4+5+9) cm=14 cm+4 cm+18 cm+15 cm+8 cm+5 cm+18 cm=82 cm.

Ans 2:

Avantika Jain from Greenwood High International School, Bengaluru
Class : Class 4
Easy! It's D

Ans 3:

Arya Prabhughate from Narayana E Techno School, NALASOPARA
Class : Class 5
ans is d

Ans 4:

Shreeraj from ISWK, Muscat, Muscat
Class : Class 4
Option D

Ans 5:

Arhan Shri Gupta from MPS , Abu Dhabi
Class : Class 4

Ans 6:

JESHAL MOHAPATRA from GEMS MODERN ACADEMY, Dubai
Class : Class 4
missing is 9cm and 18cm which goes accoording to D!

Ans 7:

Shreeya Mangla from ASN International School, New Delhi
Class : Class 4
The correct answer is D

Ans 8:

Deepayan Das from South Point High School, Kolkata
Class : Class 6
oh! yeah it's D

Ans 9:

ikshika kumar from MVN SCHOOL, FARIDABAD
Class : Class 7
D) 82 cm

Ans 10:

Ashwak from Cambridge International School, Saudi Al Dera
Class : Class 8
The answer is D

Ans 11:

Aaditya Kant from DPS, Nerul, Navi Mumbai
Class : Class 4
d

Ans 12:

LAVANYA DADHWAL from BLOOM PUBLIC SCHOOL, South West Delhi
Class : Class 4
The correct answer is D

Ans 13:

Ira Agrawal from Sancta Maria International School, Hyderabad
Class : Class 3
It’s obviously D!!!

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Omayr from Army Public School Yol Cantt, Dharamshala
Subject :IMO    Class : Class 8

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is D.

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Kabir Bajaj from P G Garodia School ICSE, Mumbai
Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is A.

Ans 2:

saina from dps, INDIRAPURAM
Class : Class 2

Ans 3:

Darshini Chakravarty from Pinnacle High International School, Mumbai
Class : Class 4

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Omayr from Army Public School Yol Cantt, Dharamshala
Subject :IMO    Class : Class 8

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Omayr from Army Public School Yol Cantt, Dharamshala
Subject :IMO    Class : Class 8

Ans 1:

Rgdn from SDIS, Gandhinagar
Class : Class 8
Answer is C. a^2 ÷ 2 Because diagonals of a square are equal. And area of rhombus formula can be used here because both have all sides equal. Area of rhombus= 1/2(diagonal 1 × diagonal 2) Because diagonals are equal, we write it as : a × a÷ 2 =a^2 ÷2

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Shantanu P Yadav from ST. Vincent Pallotti Nagpur, Nagpur
Subject :IMO    Class : Class 6

Ans 1:

from ,
Class :
B: New number is smaller than original number.

Ans 2:

pranjal kaur from SVISG, DELHI
Class : Class 6
option B

Ans 3:

Nisarg Milan Salot from Narayana E-Techno School, Mumbai
Class : Class 8
option B

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Aadithya John Gejo from Airforce school AV camp, Bangalore
Subject :IMO    Class : Class 4

Ans 1:

Dhanshree from Sunshine school, Karanja
Class : Class 4
The answer is C

Ans 2:

AREEN from BOLTON SCHOOL, Secunderabad
Class : Class 5
Answer is C as the question says 3098+1427<5420+2018 and we have to find how much less 3098+1427<5420+2018, which is 5420+2018-3098+1427 and to get this we have to follow the BODMAS rule, which is 7438-4525=2913.

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