# User Forum

Subject :IMO    Class : Class 3

Class : Class 3
30

## Ans 2:

Class : Class 3
30

Subject :IMO    Class : Class 3

## Ans 1:

Class : Class 4
The correct answer is 15,as 22 contains 2 times 2

## Ans 2:

Class : Class 3
j,bhkn,.j.jk,jj.kjmjkjkjkjk

## Ans 3:

Class : Class 3
I am also getting 14 but I did wrongÃ°ÂŸÂ˜Â Ã°ÂŸÂ˜Â Ã°ÂŸÂ˜Â Ã°ÂŸÂ‘Â¹Ã°ÂŸÂ‘Â¹Ã°ÂŸÂ‘Â¹Ã°ÂŸÂ‘Â¹Ã°ÂŸÂ‘Â¹

Class : Class 3

## Ans 5:

Class : Class 3
the answer should 14 because as the numbers would be -2 12 21 22 23 24 25 26 27 28 32 42 -14 0nly because it cannot go after 50

Class : Class 4

Class : Class 4
should be 14

Class : Class 3
15

## Ans 9:

Class : Class 3
It should be 14. Not 15. As the numbers would be-2,12,20,21,22,23,24,25,26,27,28,29,32,42.

## Ans 10:

Class : Class 3
It should be 15 because numbers are2,12,20,21,22,23,24,25,26,27,28,29,32,42.

## Ans 11:

Class : Class 7
14

Subject :IMO    Class : Class 3

Class : Class 4
C

## Ans 2:

Class : Class 3
C

Subject :IMO    Class : Class 3

Class : Class 4

Class : Class 3

Class : Class 3

Class : Class 3

## Ans 5:

Class : Class 3
the answer is six because 10-4

## Ans 6:

Class : Class 3

Subject :IMO    Class : Class 4

## Ans 1:

Class : Class 5

Subject :IMO    Class : Class 5

Class : Class 5
Option B)

## Ans 2:

Class : Class 5
Ans is B because 3645279+2153467=5798746. 5798746 will be rounded to its nearest ten thousand, which is 5800000, since 98746 will be rounded to nearest ten thousand, which is 100000, 1 will be carried to the lakhs place, or, you can say that 3645279 and 2153467 will be rounded to the nearest ten thousand, which will be 3650000 and 2150000, respectively. 3650000+2150000=5800000.

Subject :IMO    Class : Class 8

## Ans 1:

Class : Class 8
The answer is 3. When you solve the equation you get 3*3*1*1*2*14/1*1*1. Now we see that the prime numbers left are 3,3 and 2. Therefore there are 3 prime numbers.

Class : Class 4

Class : Class 8

Class : Class 8

## Ans 5:

Class : Class 6
the solution of the equation is 3*3*5*5*5*2*7 which has seven prime factors

## Ans 6:

Class : Class 8
The answer is 3. When you solve the equation you get 3*3*1*1*2*14/1*1*1. Now we see that the prime numbers left are 3,3 and 2. Therefore there are 3 prime numbers.

## Ans 7:

Class : Class 8

Subject :IMO    Class : Class 3

Subject :IMO    Class : Class 3