Subject :IMO Class : Class 4
Subject :IMO Class : Class 4
Fill in the blanks.
• There were 40 children at a party. 14 of them were boys. __P__ fraction of children were girls.
• Cost of a teddy bear is 
of the cost of a doll. If cost of the teddy bear is ₹ 114, then cost of the doll is ₹ __Q__ .
• Difference between 
is __R__.
• If 
then x = __S__.
| P | Q | R | S | |
| A | 7/20 | 76 | 5/8 | 1/4 |
| B | 13/20 | 76 | 7/8 | 1/4 |
| C | 7/20 | 171 | 5/8 | 3/4 |
| D | 13/20 | 171 | 7/8 | 3/4 |
Ans 1:
Class : Class 4
Answer is D). How? So let’s hear the question and answers fill in the blanks.
• There were 40 children at a party. 14 of them were boys. __P__ fraction of children were girls.
• Cost of a teddy bear is of the cost of a doll. If cost of the teddy bear is ₹ 114, then cost of the doll is ₹ __Q__ .
• Difference between is __R__.
• If then x = __S__.
P Q R S
A 7/20 76 5/8 1/4
B 13/20 76 7/8 1/4
C 7/20 171 5/8 3/4
D 13/20. 171 7/8 3/4
So the first question is.
• There were 40 children at a party. 14 of them were boys. __P__ fraction of children were girls.
So the answer is 26/40 or 13/20 because if there are 14 boys out of 40 children then 26 girls out of 40 children answer for the first question is 26/40 or 13/20.
So option A) and C) cannot be the answer because they are not equivalent to 26/40 or 13/20. Now let’s hear the second question.
• Cost of a teddy bear is of the cost of a doll. If cost of the teddy bear is ₹ 114, then cost of the doll is ₹ __Q__ .
So the cost of the doll is ₹171 because cost of a teddy bear is 2/3 cost of a doll And the cost of the teddy bear is also equal to ₹114 so how get answer as ₹171 you have to divide ₹114 by 2 to get 1/3 of cost of the doll and then we ₹57, and then we multiply ₹57 by 3 to get the cost of the doll answer is ₹57 + ₹57 + ₹57 = ₹114 + ₹57 or ₹171. Now the option B) cannot be the answer because it is not equivalent to ₹171. Now you’ll are thinking that why I didn’t show the explanation of questions 3 and 4. I did not show you questions 3 and 4 because there are only 4 options and in answers none of the options none of these as their answers. Hence we have an answer which is D).
Ans 2:
Class : Class 4
Post Your Answer
Subject :IMO Class : Class 4
Ans 1:
Class : Class 7
According to BODMAS or DMAS, first / (divide),then * (multiply), then (add) and then - (subtract). So answer should be: S * R - P Q= 5 x 7 - 2 8= 35 - 2 8= 35 - 10= 25
Ans 2:
Class : Class 7
Is there any rule for DMAS solving? Hope you answer both my questions. 1. According to......... and 2. Is there any ......................
Ans 3:
Class : Class 7
Hope you answer soon
Ans 4:
Class : Class 3
Post Your Answer
Subject :IMO Class : Class 8
Ans 1:
Class : Class 9
Let the sum be x.
Compound interest:
P(1+r/100)^n-P
=x(11/10)^2-x
Taking x common,
x[(121/100)-1]
=21x/100
Simple interest:p*r*t/100
=x*10*2/100
=x/5
Compound interest - simple interest =500
21x/100-x/5=500
x/100=500
x=50000
Ans 2:
Class : Class 8
Post Your Answer
Subject :IMO Class : Class 6
Ans 1:
Class : Class 7
414720 /144 = 2880
correct answer is D
Post Your Answer
Subject :IMO Class : Class 6
Post Your Answer
Subject :IMO Class : Class 6
Ans 1: (Master Answer)
Class : Class 1
(A): Let the other number be y.
HCF × LCM = Product of numbers
11 × 7700 = 275 × y
y = 308
Post Your Answer
Subject :IMO Class : Class 7
from 
and then multiply the result by the multiplicative inverse of 
Ans 1:
Class : Class 7
Post Your Answer
Subject :IMO Class : Class 3
Post Your Answer
Subject :IMO Class : Class 6
Ans 1: (Master Answer)
Class : Class 1
(C): Two plots have same perimeter:
So, 60 × 3 = 2 × ( length + 30)
90 = length + 30
Length = 60 m
Hence, area = 60 × 30 = 1800 sq. m