Subject :IMO Class : Class 3

Subject :IMO Class : Class 7

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Subject :IMO Class : Class 7

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Subject :IMO Class : Class 6

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Subject :IMO Class : Class 3

## Ans 4:

Class : Class 2

endi ra antha tough questions isthanu niku pain theliadhura easy questons ivvu

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Subject :IMO Class : Class 7

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Subject :IMO Class : Class 7

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Subject :IMO Class : Class 8

## Ans 1:

Class : Class 10

Answer: C

Solution

If a polygon has 'n' sides, then it is divided into (n â€“ 2) triangles. The sum of the angles of a triangle = 180Â°. Therefore, the sum of interior angles of a polygon having n sides is (n â€“ 2) x 180.

(n - 2) x180 = 1440

n - 2 = 1440/180 = 8

n = 8 + 2 = 10

Solution

If a polygon has 'n' sides, then it is divided into (n â€“ 2) triangles. The sum of the angles of a triangle = 180Â°. Therefore, the sum of interior angles of a polygon having n sides is (n â€“ 2) x 180.

(n - 2) x180 = 1440

n - 2 = 1440/180 = 8

n = 8 + 2 = 10

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Subject :IMO Class : Class 6

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Subject :IMO Class : Class 4

## Ans 1:

Class : Class 4

Heads ( Lions + Peacocks) = 15, No. of Legs = 25 +15 = 40. Since total legs were 40 no. of lions has to be less than 10 (because 10 x 4 legs = 40 which means zero peacock, which is not possible...) . so if we take 5 lions and 10 peacocks, total heads = 15 & total legs = 5 x 4 + 10 x 2 = 40 legs. Thus the answer is 5 peacocks were more than lions.