International Maths Olympiad Forum By SOF Olympiad Trainer - Page 435

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Subject :IMO    Class : Class 2

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Subject :IMO    Class : Class 7

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

Ans 2:

Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

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Subject :IMO    Class : Class 3

Ans 1:

Class : Class 4
B Question

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 5
C C C THE ANSWER IS C

Ans 2:

Class : Class 5
Ans is C because LIV=54 & XCIX=99 XLIV=44 & XLVI=46 CCV=205 & XCV=95 Therefore, LIVXCV

Ans 3:

Class : Class 5
probably

Ans 4:

Class : Class 4

Ans 5:

Class : Class 5
Answer is C because: LIV=54 XCIX=99 54<99 XLIV=44 XLVI=46 44<46 CCV=205 XCV=95 205>95

Ans 6:

Class : Class 3
bad question

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Subject :IMO    Class : Class 9

Ans 1:

Class : Class 9
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Ans 2:

Class : Class 9
Yes the correct answer is option C because first is false and rest are.

Ans 3:

Class : Class 10
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Ans 4:

Class : Class 9
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Ans 5:

Class : Class 9
Yes it is correct

Ans 6:

Class : Class 8
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Ans 7:

Class : Class 10
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Ans 8:

Class : Class 10
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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 5
It is too easy 80-60+15-2=33

Ans 2:

Class : Class 3
Yeah A is the answer

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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 5
1836

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Subject :IMO    Class : Class 8

Ans 1:

Class : Class 9
The answer is (B) Using Unitary Method- Angle for 15,000 rupees= 360 degrees Angle for x rupees=60 degrees If money spent increases, degree of angle used increases, Therefore it is direct variation- x/1500=60/360 x=1/6 x 15,000 x= 2500 rupees

Ans 2:

Class : Class 10
B

Ans 3:

Class : Class 8
B. Is the correct answer

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Subject :IMO    Class : Class 8

Ans 1:

Class : Class 10
A

Ans 2:

Class : Class 9
A

Ans 3:

Class : Class 4
A

Ans 4:

Class : Class 10
A

Ans 5:

Class : Class 10
A

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