# User Forum

Subject :IMO    Class : Class 6

Subject :IMO    Class : Class 6

## Ans 1:

Class : Class 6
its d 1\15

Subject :IMO    Class : Class 6

## Ans 1:

Class : Class 7
India invented 0 and its inventor is Aryabhatta.

## Ans 2:

Class : Class 7
INDIA invented zero and its inventor is Bramagupta or Aryabhatta

Subject :IMO    Class : Class 6

Subject :IMO    Class : Class 4

## Ans 1:

Class : Class 3
B is the right answer as the date he will join is 14th Oct

Class : Class 6

Class : Class 3

Class : Class 5

Class : Class 4

## Ans 6:

Class : Class 4
ans will be b because holidays till 13th but he will join on 14th

## Ans 7:

Class : Class 4

Subject :IMO    Class : Class 2

Subject :IMO    Class : Class 7

## Ans 1:

Class : Class 6

Subject :IMO    Class : Class 7

## Ans 1:

Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

## Ans 2:

Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

Subject :IMO    Class : Class 3

Subject :IMO    Class : Class 4

## Ans 1:

Class : Class 5
Ans is C because LIV=54 & XCIX=99 XLIV=44 & XLVI=46 CCV=205 & XCV=95 Therefore, LIVXCV

## Ans 2:

Class : Class 5
Answer is C because: LIV=54 XCIX=99 54<99 XLIV=44 XLVI=46 44<46 CCV=205 XCV=95 205>95