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kamakshi garg from venkateshwar global school, New Delhi
Subject :IMO    Class : Class 6

Ans 1:

Nisarg Milan Salot from Narayana E-Techno School, Mumbai
Class : Class 8

Ans 2:

surya pratap mishra from central school, jajpur town, odisha-755007, Jajpur Town
Class : Class 6
answer is D because maximum water that cant be consumed is 4:1 but in the options all the ratios have more quantity of water

Ans 3:

Pravir Mishra from National Public School, Bengaluru
Class : Class 8
of coure its not its written that maximum water is only 1 part in the ratio. in the options all the parts for water are more than 1, so its none of these Pravir

Ans 4:

Mohinder singh from Sacred heart convent school, Ludhiana
Class : Class 7
Can u make me understand the question, Please?

Ans 5:

Mohinder singh from Sacred heart convent school, Ludhiana
Class : Class 7

Ans 6:

Abhjith S Kumar from Airport Senior Secondary school Karipur, Kozhikode Intl. Airport, Kozhikode Airport
Class : Class 9
Please make the question clear cut.

Ans 7:

Vidit bohra from Campion , Mumbai
Class : Class 6
KThe question itself is not clear at all

Ans 8:

nabendu kumar mohakud from dav public school chandrasekharpur, Bhubaneswar
Class : Class 6
can anyone explain please

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Arindam Manoj Phukon from Delhi Public School, ONGC NAZIRA, Sivasagar , Assam
Subject :IMO    Class : Class 4

Ans 1:

from Ira Global School, Dombivli
Class : Class 7
36 SECONDS

Ans 2:

Udayan Sindhu Chaudhuri from The Indian School, NEW DELHI
Class : Class 7
c)36 seconds

Ans 3:

ASHIM SARKAR from ,
Class : Class 4
36

Ans 4:

Apoorva from Blue Ridge Public School, Pune
Class : Class 8
36 sec

Ans 5:

Darsh Jain from Advanced Academy, Indore
Class : Class 5
Ball A rotates in 6 seconds, ball B in 9 seconds and ball C in 12 seconds. So we have to take out the LCM of the three numbers. LCM = 36. So the answer is 36 seconds.

Ans 6:

Darsh Jain from Advanced Academy, Indore
Class : Class 5
Ball A rotates in 6 seconds, ball B in 9 seconds and ball C in 12 seconds. So we have to take out the LCM of the three numbers. LCM = 36. So the answer is 36 seconds.

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Rishit Sharma from Nehru World School, Ghaziabad
Subject :IMO    Class : Class 6

Ans 1:

Diya from delhi public school dlf phase-2, GURUGRAM
Class : Class 6

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is B.

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Rishit Sharma from Nehru World School, Ghaziabad
Subject :IMO    Class : Class 6

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is C.

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Rishit Sharma from Nehru World School, Ghaziabad
Subject :IMO    Class : Class 6

Ans 1:

sachinthite@rocketmail.com from Sinhghad Public School Korti, Pandharpur
Class : Class 4
to chaitanya LK

Ans 2:

Budhanath Panda from chinmaya vidyalaya therubali, Rayagada
Class : Class 6
plz give solution

Ans 3:

Anish Singh from Podar World School , Vadodara
Class : Class 7

Ans 4:

Sayandeep Basu from Delhi Public School, Bengaluru
Class : Class 6

Ans 5:

Chaitanya L K from SKCHEC, bangalore
Class : Class 8
ans. is D. when all the given numbers [16,34,75,21,13] are multiplied,we get 1,11,38,400.this number is ending with two zeros.if this number must end with six zeros,there must be four more zeros.to achieve this,we multiply 1,11,38,400 by 10,000.

Ans 6:

Tejasvi Bhosale from The somaiya School, Mumbai
Class : Class 6
whats the simple solution? do we have to multiply all the numbers?

Ans 7:

sachinthite@rocketmail.com from Sinhghad Public School Korti, Pandharpur
Class : Class 4
gone mad or what !!!!!! read question carefully i,m more reading questioncarefully

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Rishit Sharma from Nehru World School, Ghaziabad
Subject :IMO    Class : Class 6

Ans 1:

Pravir Mishra from National Public School, Bengaluru
Class : Class 8
its 36 As the ant which walks around the square covers 12 cm in one round and the ant which walks around the rectangle covers 18 cm in one round. To find out when they will meet you can take the LCM of the distance they cover in one round. it is 36 so they will meet after both the ants cover 36 cm. Pravir

Ans 2:

Pravir Mishra from National Public School, Bengaluru
Class : Class 8
its 36 As the ant which walks around the square covers 12 cm in one round and the ant which walks around the rectangle covers 18 cm in one round. To find out when they will meet you can take the LCM of the distance they cover in one round. it is 36 so they will meet after both the ants cover 36 cm. Pravir

Ans 3:

Admin from SOF, Noida
Class : Class 10
Answer: B
We have corrected the answer. Thanks for pointing out.

Solution
Perimeter of small square = 12 cm
Perimeter of big square = 18 cm
LCM of 12 and 18 = 36

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Rishit Sharma from Nehru World School, Ghaziabad
Subject :IMO    Class : Class 6

Ans 1:

Ashwin Shridhar from Vidyashilp Academy, Bangalore
Class : Class 9
area of the lawn is 81 sq mtr but your question says including the path which will be 121 sq mtr. this option is not there. You need to remove including path from the question.

Ans 2:

VANSH Aggrawal from Surajkund International School, Faridabad
Class : Class 8
solution let the side of the lawn(without the path) is xso the side of the lawn (with the path ) =x 2area =(x 2)^2 =x^2 4 4x40 =x^2 4 4x-x^2=40 =4 4x=40-4=4x=36=4x=x=36/4=x=9area of lawn=9*9=81area of lawn(including the path)=(9 2)*(9 2)=11*11=121

Ans 3:

Venneti Bhargav from gyan bharati, New Delhi
Class : Class 7
wrong answer because the question says to include area of pathway as well as are of lawn

Ans 4:

Admin from SOF, Noida
Class : Class 10
Answer : D

Solution
Let the length of one side of the path (outer square) be x.
Area of lawn + path = x2
Length of one side of the lawn = (x -2)
Area of path = x2 - (x-2)2 = 40
Solving the above equation x = 11
Side of lawn = 11 - 2 = 9
Area of lawn = 81 m2

Ans 5:

Chaitanya L K from SKCHEC, bangalore
Class : Class 8
Correct answer is 40 (area of path) 81(area of lawn)=121 sq mtrs. This option is not given

Ans 6:

Mehreen Brar from Delhi Public School, Chandigarh
Class : Class 7
but we had to find total area not area of lawn.....81 is only area of lawn.....the answer given is wrong

Ans 7:

Allu Gowri sasaank from timpany school, Visakhapatnam
Class : Class 7

Ans 8:

arvind kumar Singh from SUDHIR MEMORIAL INSTITUTE LILUAH HOWRAH, HOWRAH
Class : Class 7
c

Ans 9:

Pravir Mishra from National Public School, Bengaluru
Class : Class 8
area of the shaded region Pravir

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Rishit Sharma from Nehru World School, Ghaziabad
Subject :IMO    Class : Class 6

Ans 1:

Sanjib ghosh from ,
Class : Class 6
As mean of 5 number is 12. Therefore sum of the 5 number is 12x5=60 Mean of 4 number is 14 Sum=14x4=56. Therefore the removed no.is 60-56=4

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Sanjib ghosh from ,
Subject :IMO    Class : Class 6

Ans 1:

Sanket Kulkarni from Euroschool, Pune
Class : Class 8

Ans 2:

vaibhav jain  from bbps, New Delhi
Class : Class 5
The answer should be 42

Ans 3:

Abhjith S Kumar from Airport Senior Secondary school Karipur, Kozhikode Intl. Airport, Kozhikode Airport
Class : Class 9
the answer should be 42

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Ankita Dharmani from Euroschool, Mumbai
Subject :IMO    Class : Class 4

Ans 1:

Darsh Jain from Advanced Academy, Indore
Class : Class 5
( 25 * 110 ) + ( 32 * 120 ) =6590. So option A is correct.

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