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Bhumika Balani from ,
Subject :IMO    Class : Class 7

Ans 1:

from ,
Class :
how is the answer worked out?

Ans 2:

from ,
Class :
FIRST MAKE THAT SIMILAR 4 TRAINGLES INSIDE A RECTANGLE WHOSE TOTAL AREA IS 28 CM SQUARE NOW WE ARE LEFT WITH FOUR EQUALITERAL TRAINGLES ARE OF WHOSE ONE IS 1/2*L/2*B/2=LB/8 FOR FOUR TRAINGLES TOTAL AREA =4*LB/8=LB/2 NOW LB=LB/2+28 LB/2=28 LB=56 CM SQAURE

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Nandha Gopi Krishna from DPS, Bengaluru
Subject :IMO    Class : Class 6

Ans 1:

from ,
Class :
C.) 75

Ans 2:

from ,
Class :

Ans 3:

from ,
Class :
plz explain

Ans 4:

from ,
Class :
75 was very close so I chose 75

Ans 5:

from ,
Class :

Ans 6:

pranav from Sri Kumaran Children's Home - CBSE Mallasandra, Bengaluru
Class : Class 6
explain how it is pls

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Anusha from LBS School , Kota
Subject :IMO    Class : Class 3

Ans 1:

Soham Gupta from JSSIS Dubai, Dubai
Class : Class 6
c

Ans 2:

Tanmay 2009 from MVN Aravali Hills, Faridabad
Class : Class 6
Correct ans is c. But it is shown as wrong . Please correct

Ans 3:

Anusha from LBS School , Kota
Class : Class 10
Correct answer is C. Please update the answers.

Ans 4:

Abhijato Chatterjee from Bharatiya Vidya Bhavan, Kolkata, kOLKATA
Class : Class 6
Please correct.Right ans is c.l

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sain_nalini@yahoo.com from DPS, Gurgaon
Subject :IMO    Class : Class 3

Ans 1:

Yash from Dps, Noida
Class : Class 2
Solution is wrong

Ans 2:

AANYA GUPTA from MDPS Faridabad, Faridabad
Class : Class 8
yes, it should be 12-11 = 1

Ans 3:

VANSH GARG from DPSG, GHAZIABAD
Class : Class 4
ANS. WRONG STRAIGHT LINES-12 TRIANGLES-11 12-11=1

Ans 4:

Vidya Maji from Kendriya Vidyalaya No 2, Pathankot, Pathankot
Class : Class 5

Ans 5:

Anuva maity from The Royal International School , Kolkata
Class : Class 3

Ans 6:

Swarnava Pal from Vivekananda Mission School, Haldia
Class : Class 8

Ans 7:

VANSH GARG from DPSG, GHAZIABAD
Class : Class 4

Ans 8:

sreeram from christ academy, Bengaluru
Class : Class 4
yes 12-11 = 1 is the solution

Ans 9:

Naitik from Billabong High International School, Noida
Class : Class 5
the answer is b 2

Ans 10:

Janam Patel from R M G Maheshwari, Surat
Class : Class 8
Ans. is 12-11=1

Ans 11:

VANSH GARG from DPSG, GHAZIABAD
Class : Class 4

Ans 12:

Afeefa from Afeefa, Bhubaneshwar
Class : Class 4
solution is wrong

Ans 13:

from ,
Class :
Yes number of straight line is 12 and number of triangle is 11 so 12-11=1

Ans 14:

dhruv anand from DPS vindhyanagar, kahalgaon bhagalpur
Class : Class 7
Answer should be D.

Ans 15:

Bhargav Gupta from Naval Children School, Visakhapatnam
Class : Class 3
yes you are right

Ans 16:

Elina from BASELIOUS PUBLIC SCHOOL, Gujarat refinery
Class : Class 2

Ans 17:

Anuva maity from The Royal International School , Kolkata
Class : Class 3

Ans 18:

from ,
Class :
answer is 12-11=1

Ans 19:

Sanjivani Saha from Chrysalis High, Bangalore
Class : Class 8
the answer is incorrect 12-11=1

Ans 20:

Sourish Mahakul from Delhi Public School Electronic City, Bengaluru
Class : Class 8
yes it is 12 - 11 solution is wrong

Ans 21:

Darshini Chakravarty from Pinnacle High International School, Mumbai
Class : Class 4
12-11=1, so the answer should be D.

Ans 22:

Elina from BASELIOUS PUBLIC SCHOOL, Gujarat refinery
Class : Class 2
Yes, 12-11=1The answer given is wrong

Ans 23:

Prithwanko Ghosh from Kendriya Vidyalaya IIT Kanpur, Kanpur
Class : Class 9
answer is wrong

Ans 24:

Saha from Bangalore, Bangalore
Class : Class 3
the answer is incorrect. It should be 12-11 = 1

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from ,
Subject :IMO    Class : Class 4

Ans 1:

Admin from SOF, Noida
Class : Class 10
Number of Rs. 10 Notes only: 260/10 = 26 Number of Rs. 5 Notes only: 260/10 = 52 Therefore Rs. 5 notes more than Rs. 10, 52-26=26 Option (B)

Ans 2:

NEEV SINGH from VISHWA BHARATI PUBLIC SCHOOL, Noida
Class : Class 8

Ans 3:

Kanav Dhingra from DPS sec45, Gurgaon
Class : Class 10
AFTER THE SOLUTION I FOUND IT VERY EASY

Ans 4:

Kanav Dhingra from DPS sec45, Gurgaon
Class : Class 10

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adwaita from DPS NOIDA, Noida
Subject :IMO    Class : Class 4

Ans 1: (Master Answer)

from ,
Class :
The correct answer is D.

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from ,
Subject :IMO    Class : Class 4

Ans 1:

Oscar Maltman from DBSEH, dubai
Class : Class 10

Ans 2:

aarav from GURUKUL THE SCHOOL, GHAZIABAD
Class : Class 7
answer is 11/20 as if unshaded is less than 1/2 we take it as 1/2 if it is more than 1/2 then we take it as 1 but if it is 1/2 we take it as 1/2 now count all of unshaded boxes you will get the answer

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SWASTIK from JANKIDAS KAPUR PUBLIC SCHOOL, SONEPAT
Subject :IMO    Class : Class 8

Ans 1:

Anidroid ,Aniruddha from Modern DPS, Faridabad
Class : Class 8
1000m

Ans 2:

from ,
Class :
Relative velocity of two trains is 384km/hr=320/3 m/sec. Therefore,it can travel 1600m in 15 sec. Therefore, the length of the second train is (1600-600)m=1000m

Ans 3:

Anidroid ,Aniruddha from Modern DPS, Faridabad
Class : Class 8
Add up the speeds and multiply with time as trains are in opposite directions.Then subtract the length of the first train. Ans -1000m

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SWASTIK from JANKIDAS KAPUR PUBLIC SCHOOL, SONEPAT
Subject :IMO    Class : Class 8

Ans 1:

from ,
Class :
Let the ages of A, B and C be a years, b years and c years respectively. (a + b) is 12 greater than (b + c) => 12 + b + c = a + b => 12 + c = a => 12 = a - c So, C is younger than A by 12 years Answer is A

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from ,
Subject :IMO    Class : Class 4

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