Subject :IMO Class : Class 8
Class : Class 8
The question is wrong.If A is the answer, solving this quadratic eqn, we get a=10 or -2since the answer is a simplified form of the question, these values of a should also hold for question also. But if we put these vales in the question either LHS or RHS denominator will become 0 making it undefined.the actual procedure is to factorize.=> [(a-3)(a-10)]/(a-10)=[(a 2)(a 2)]/(a 2)=> a-3 = a 2=> -3 = 2 which is absurd. so the question is wrong.
Class : Class 9
a2 - 13a + 30 = a2 + 4a + 4
a - 10 a + 2
=> (a2 - 13a + 30)(a + 2) = (a2 + 4a + 4)(a - 10)
=> a3 + 2a2 - 13a2 - 26a + 30a + 60 = a3 - 10a2 +4a2 + 4a - 40
=> - 11a2 + 4a + 60 = - 6a2+ 4a - 40
=> - 11a2 + 6a2 + 60 + 40 = 0
=> - 5a2 + 100 = 0
=> 5a2 = 100
=> a2 = 20
=> a = √20
Insert the value of'a'and you will get the answer.
Subject :IMO Class : Class 4
Match the following.
Column 1----------Column 2
(i) | 926543 | (p) | Smallest 5-digit number |
(ii) | 10000 | (q) | Place value of 2 is 2000 |
(iii) | 962540 | (r) | 100039 when rounded off to nearest 100 |
(iv) | 100000 | (s) | Successor of 926542 |
A (i) - (s), (ii) - (p), (iii) - (q), (iv) - (r)
B (i) - (q), (ii) - (r), (iii) - (s), (iv) - (p)
C (i) - (s), (ii) - (r), (iii) - (q), (iv) - (p)
D (i) - (q), (ii) - (p), (iii) - (s), (iv) - (r)
rd
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Subject :IMO Class : Class 4
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Subject :IMO Class : Class 6
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Subject :IMO Class : Class 7
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Subject :IMO Class : Class 6
Fill in the blanks.
(i) The additive identity of the integers is P.
(ii) The integer which is 8 less than - 24 is Q.
(iii) Every integer less than zero is R.
P | Q | R | |
A | 0 | - 32 | negative |
B | 1 | - 32 | positive |
C | 0 | - 16 | negative |
D | 1 | - 32 | negative |
how is the answer a? its supposed to be c right?
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Subject :IMO Class : Class 4
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Subject :IMO Class : Class 6
State ‘T’ for true and ‘F’ for false.
I. If a whole number is divided by another whole number, which is greater than first one, then the quotient is not equal to zero.
II. Sum of two whole numbers is always less than their product.
III. Whole numbers are not closed under multiplication.
I | II | III | |
A | T | T | T |
B | T | F | F |
C | T | T | F |
D | F | T | T |
please give me the proper solution
Ans 3:
Class : Class 6
the answer is b only because the second question is, 'the sum of two numbers is ALWAYS smaller than their product.' this statement is definitely false because if we take example of 2 and 2, their product is equal to their sum and if we take 1 and 1, then its product is smaller than its sum. then according to the statement above, answer should be false which should be answer 'B'
Ans 8:
Class : Class 7
The answer is BBecause if we take 1 2=3 but 1x2=2 which is less than the product. Statement ll is false.
Ans 9:
Class : Class 6
The answer is C.Even if the answer is B then how???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
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Subject :IMO Class : Class 7
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Subject :IMO Class : Class 4
Ans 2:
Class : Class 5
Perimeter is the length of the boundary. The number of lines that are in outer part of the figure are 14. So, 216/14=9. So, ans is B