International Maths Olympiad Forum By SOF Olympiad Trainer

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Subject :IMO    Class : Class 5

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Subject :IMO    Class : Class 3

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Class : Class 3

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Subject :IMO    Class : Class 6

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Class : Class 6
30

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Subject :IMO    Class : Class 5

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Subject :IMO    Class : Class 4

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 8

Ans 2:

Class : Class 6

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Subject :IMO    Class : Class 7

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Class : Class 8
No answer is 2000 sorry

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 7
c is correct

Ans 2:

Class : Class 4
option C,154 is correct answer

Ans 3:

Class : Class 7
c is correct

Ans 4:

Class : Class 7
c is correct

Ans 5:

Class : Class 8
c is correct

Ans 6:

Class : Class 7
Here the given answer option D is wrong . The correct answer is option C.

Ans 7:

Class : Class 7
C is correct

Ans 8:

Class : Class 8
Option C is the answer

Ans 9:

Class : Class 8
Answer is (C)Diameter of bigger circle=28 cmradius=28/2=14 cmArea of semicircle=1/2*22/7*14*14=4312/14=308 sq.cm2 semicircle=circleArea=22/7*7*7=1078/7=154 sq.cmArea left=308-154=154 cm

Ans 10:

Class : Class 8

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Subject :IMO    Class : Class 8

Ans 1:

Class : Class 8
√3844=62 Hence the answer is c

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 7
let the price of object B be x the the price of object A is (6x-100) now ATP, 1(6x-100) + 4*x=1400 =>6x-100 + 4x=1400 =>10x -100=1400 =>10x=1500 =>x=1500/10 =>x=150 now the price of object A=150*6-100 =800(d)

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