Subject :IMO Class : Class 6
Class : Class 1
Priya started her work from a monday and continued her work for 15 days. So, she had worked for 2 saturdays + 13 weekdays.
We know that she works for 8 hours a day,so
For working on the weekdays, she will receive= 13 X Rs. 50.50 X 8 = Rs. 5252
For working on 2 saturdays, she will receive= 2 X Rs.85 X 8 = 1360
Thus, the total amount she will receive is Rs.5252 + Rs. 1360 = Rs. 6612.
Hence, the correct answer is D.
Subject :IMO Class : Class 5
Ans 2:
Class : Class 6
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Subject :IMO Class : Class 2
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Subject :IMO Class : Class 2
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Subject :IMO Class : Class 2
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Subject :IMO Class : Class 8
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Subject :IMO Class : Class 10
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Subject :IMO Class : Class 2
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Subject :IMO Class : Class 5
Ans 1: (Master Answer)
Class : Class 1
Here, the answer is A.
7 tenths is 7 over 10, if you divide 7 by 10 you get 7 tenths as a decimal which is 0.7
Similarly, 45 tenths is 45 over 10,if you divide 45 by 10 you get 45 tenths as a decimal which is 4.50
21 hundredths is 21 over 100, if you divide 21 by 100 you get 21 hundredths as a decimal which is 0.21
Hence, the sum of 7 tenths, 21 hundredths and 45 tenths is (0.7 + 0.21 + 4.50) = 5.41
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Subject :IMO Class : Class 8
Ans 3:
Class : Class 9
This question is completely wrong as when we factorise (a^2-13a 30) and (a^2 4a 4), we get (a-3)(a-10) and (a 2)^2 respectively. After calculating more, we get a-3=a 2 which has no solution as -3≠2
Ans 5:
Class : Class 9
a2 - 13a + 30 = a2 + 4a + 4
a - 10 a + 2
=> (a2 - 13a + 30)(a + 2) = (a2 + 4a + 4)(a - 10)
=> a3 + 2a2 - 13a2 - 26a + 30a + 60 = a3 - 10a2 +4a2 + 4a - 40
=> - 11a2 + 4a + 60 = - 6a2+ 4a - 40
=> - 11a2 + 6a2 + 60 + 40 = 0
=> - 5a2 + 100 = 0
=> 5a2 = 100
=> a2 = 20
=> a = √20
Insert the value of'a'and you will get the answer.
Ans 6:
Class : Class 9
The question is wrong.If A is the answer, solving this quadratic eqn, we get a=10 or -2since the answer is a simplified form of the question, these values of a should also hold for question also. But if we put these vales in the question either LHS or RHS denominator will become 0 making it undefined.the actual procedure is to factorize.=> [(a-3)(a-10)]/(a-10)=[(a 2)(a 2)]/(a 2)=> a-3 = a 2=> -3 = 2 which is absurd. so the question is wrong.