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Subject :IMO    Class : Class 3

Ans 1:

Class : Class 3
C ,60 as 20 10 = 30 so a should be the answer but this is only half square ,30 * 2 = 60 .So C is the answer.

Ans 2:

Class : Class 4

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 6
(D) (-,/)

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Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Class : Class 1

(B)

Milk + Milk + Milk + Milk = 900 ml
⇒ 4 (Milk) = 900 ml
⇒ Milk = 900 ÷ 4 = 225 ml


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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4
HOW ? THE FORMULA IS 5 X 7 8 AND THE DENOMINATOR WILL REMAIN 8 ONLY. PLEASE CHECK AGAIN REVISEWISE, NOIDA.

Ans 2: (Master Answer)

Class : Class 1

The correct answer is option A.


Ans 3:

Class : Class 5
a

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 6

Ans 2:

Class : Class 6

Ans 3:

Class : Class 6

Ans 4:

Class : Class 6

Ans 5:

Class : Class 6

Ans 6:

Class : Class 6

Ans 7:

Class : Class 6
(D) iii and iv

Ans 8:

Class : Class 6

Ans 9:

Class : Class 6

Ans 10:

Class : Class 6

Ans 11:

Class : Class 6

Ans 12:

Class : Class 6

Ans 13:

Class : Class 6

Ans 14:

Class : Class 6

Ans 15:

Class : Class 6

Ans 16:

Class : Class 6

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Subject :IMO    Class : Class 2

Ans 1: (Master Answer)

Class : Class 1

(D)

Time taken by Anjali to complete one round = 30 minutes
Time taken by Anjali to complete two rounds = 30+ 30 = 60 minutes or 1 hour.


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Subject :IMO    Class : Class 2

Ans 1: (Master Answer)

Class : Class 1

Amount of money Shilpa has = ₹500
Cost of hat = ₹199
Cost of hairclip = ₹ 25
∴ Total cost = ₹(199 + 25) = ₹224
Now, money left with Shilpa
₹ (500 - 224) = ₹276


Ans 2: (Master Answer)

Class : Class 1

Amount of money Shilpa has = ₹500
Cost of hat = ₹199
Cost of hairclip = ₹ 25
∴ Total cost = ₹(199 + 25) = ₹224
Now, money left with Shilpa
₹ (500 - 224) = ₹276


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Subject :IMO    Class : Class 8

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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 5
Answer =c

Ans 2:

Class : Class 4
B is the answer to this question

Ans 3:

Class : Class 5
It should be 35 Sq. m

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Subject :IMO    Class : Class 8

Fill in the blanks.
(i) Sum of interior angles of a polygon of n __P__ sides is right angles.
(ii) The measure of at least one __Q__ angle of a concave quadrilateral is more than 180°.
(iii) A quadrilateral which has only one pair of equal opposite angles is __R__.
(iv) Sum of all exterior angles of a polygon of n sides is __S__.

P Q R S
A 4 exterior kite n × 360°
B n – 2 exterior trapezium n × 180°
C 2n – 4 interior trapezium 360°
D 2 interior trapezium 180°


Please explain me the (i) question and how it's answer obtained

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