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Tanushri Prabhakar Chavan from Vidhyadham Prashala Shirur, Shirur
Subject :IMO    Class : Class 7

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Deepayan Das from South Point High School, Kolkata
Subject :IMO    Class : Class 4

Ans 1:

Sameer Anand from ST MICHAEL'S HIGH SCHOOL, PATNA
Class : Class 8
sorry A is the right answer

Ans 2:

Bhagyesh Dhuri from NEW HORIZON PUBLIC SCHOOL AIROLI, Mumbai
Class : Class 5
a is the rit awnser

Ans 3:

samridh from vidyashilpacadmy, banglore
Class : Class 4
A S TIGHT CAUSE 400 0 1500 = 2500

Ans 4:

Sameer Anand from ST MICHAEL'S HIGH SCHOOL, PATNA
Class : Class 8
C is the right answer

Ans 5:

AREEN from BOLTON SCHOOL, Secunderabad
Class : Class 5
Ans is A because: 4000 -1500= 2500

Ans 6:

SM Siddharthan from PSG Public Schools, Coimbatore
Class : Class 4
c

Ans 7:

Bhagyesh Dhuri from NEW HORIZON PUBLIC SCHOOL AIROLI, Mumbai
Class : Class 5
a is the rit awnser

Ans 8:

SM Siddharthan from PSG Public Schools, Coimbatore
Class : Class 4
C $3000

Ans 9:

Ayushi from DPS Noida, Noida
Class : Class 4
C is the right ANS......

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K Aditya from Army Public School, Secunderabad
Subject :IMO    Class : Class 1

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Shreeja from MLZS Manikonda, Hyderabad
Subject :IMO    Class : Class 5

Ans 1:

Kaustubh Jha from Mount litera zee school, Patna
Class : Class 5
(18×3)+(12×6)=54+72=126 1+2+3+4+6+8+12+24=60 126-60=66

Ans 2:

Kaustubh Jha from Mount litera zee school, Patna
Class : Class 5
(18×3)+(12×6)=54+72=126 1+2+3+4+6+8+12+24=60 126-60=66

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Sumit Kumar from Welspun Vidya Mandir, Anjar
Subject :IMO    Class : Class 8

Ans 1:

sagar kumar from D A V public school , NOIDA
Class : Class 10
28148.04

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Sumit Kumar from Welspun Vidya Mandir, Anjar
Subject :IMO    Class : Class 8

Ans 1:

sagar kumar from D A V public school , NOIDA
Class : Class 10
28148.04

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Shlok banerjee from Euroschool , Mumbai
Subject :IMO    Class : Class 3

Ans 1:

Girish Garg from Delhi public school, Bathinda
Class : Class 3
c'saturday

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Anshita Bardoloi from Delhi Public School Guwahati, GUWAHATI
Subject :IMO    Class : Class 5

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Akriti ANannd from DPS Gaya, GAYA
Subject :IMO    Class : Class 7

Arrange the given steps in CORRECT order, while constructing ΔPQR where PM QS and it is given that QR = 4.2 cm, ∠Q = 120° and PQ = 3.5 cm.
Step 1. :RQ to S and with P as centre and with a sufficient radius, draw an arc, cutting SQ at A and B.
Step 2.QX, set off QP = 3.5 cm.
Step 3.QR = 4.2 cm and construct ∠RQX = 120°.
Step 4.PR.
Step 5.PC, meeting RQ product at M. Then, PM QS
Step 6.A as centre and radius more than half AB, draw an arc. Now with B as centre and with the same radius draw another arc, cutting the previous arc at C.

A 1 → 2 → 3 → 4 → 5 → 6
B 4 → 1 → 2 → 3 → 5 → 6
C 2 → 4 → 3 → 1 → 5 → 6
D 3 → 2 → 4 → 1 → 6 → 5


GIVE SOLUTION

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Smita Desai from GOKULDHAM HIGHSCHOOL , MUMBAI
Subject :IMO    Class : Class 4

Ans 1:

AREEN from BOLTON SCHOOL, Secunderabad
Class : Class 5
Ans is C

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